/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 \(\bullet\) Two particles are cr... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

\(\bullet\) Two particles are created in a high-energy accelerator and move off in opposite directions. The speed of one particle, as measured in the laboratory, is \(0.650 c,\) and the speed of each particle relative to the other is 0.950\(c .\) What is the speed of the second particle, as measured in the laboratory?

Short Answer

Expert verified
The speed of the second particle is approximately 0.784c.

Step by step solution

01

Understand the Problem

We have two particles, and we know the speed of the first particle is \(0.650c\) relative to a stationary laboratory observer. We need to find the speed of the second particle as measured in the laboratory, given that the speed of the second particle relative to the first is \(0.950c\).
02

Use the Relativistic Velocity Addition Formula

The relativistic velocity addition formula is given by: \[ u' = \frac{u + v}{1 + \frac{uv}{c^2}} \] where \(u\) and \(v\) are the velocities of the two objects relative to an observer, and \(u'\) is the velocity of one object relative to the other. In our problem, \(u = 0.650c\) and \(u' = 0.950c\). We need to solve for \(v\), which is the velocity of the second particle relative to the laboratory.
03

Solve for the Velocity of the Second Particle

Plug in the known values into the relativistic velocity addition formula: \[ 0.950c = \frac{0.650c + v}{1 + \frac{0.650c \cdot v}{c^2}} \] Simplify and solve for \(v\):Simplify left side:\[ 0.950 = \frac{0.650 + v/c}{1 + 0.650v/c^2} \]Cross-multiply:\[ 0.950 (1 + 0.650v/c^2) = 0.650 + v/c \]Distribute on left:\[ 0.950 + 0.6175v/c^2 = 0.650 + v/c \]Rearrange terms to collect v (replace \(v\) with \(vc\) to make steps clearer):\[ 0.950 - 0.650 = (v/c) - 0.6175 (v/c^2) \]\[ 0.300 = (v/c)(1 - 0.6175/c) \]Solve for \(v\):\[ v = \frac{0.300c}{1 - 0.6175} \]Calculate:\[ v = \frac{0.300c}{0.3825} \approx 0.784c \]
04

Conclusion

The velocity of the second particle, as measured in the laboratory, is approximately \(0.784c\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Special Relativity
Special relativity is a fascinating theory introduced by Albert Einstein, which fundamentally changed how we understand the physics of high-speed travel and motion. One of its principal ideas is that the laws of physics are the same for all observers, regardless of their constant velocity relative to each other. This leads to surprising results, particularly when dealing with objects moving at velocities close to the speed of light, denoted by \( c \).

A critical aspect of special relativity is its effect on time and space. As an object's speed approaches the speed of light, time appears to slow down for it relative to a stationary observer, an effect known as time dilation. Simultaneously, distances appear contracted along the direction of motion, called length contraction. These effects ensure that no object with mass can reach or exceed the speed of light.

The concept of relativistic velocity addition also arises from special relativity. Unlike classical physics, where velocities simply add up, special relativity uses a specific formula that takes into account the finite and invariant nature of the speed of light, ensuring the resulting velocity doesn't exceed \( c \). This ensures that observers in different reference frames measure velocities relative to each other in a way that's consistent with relativity's principles.
Particle Physics
Particle physics is the branch of science that explores the smallest constituents of matter and the fundamental forces governing them. In high-energy accelerators, particles are often sped up to velocities near the speed of light. Understanding their velocities becomes essential, particularly when they collide or move in opposite directions, as described in our exercise.

These high-speed experiments allow researchers to investigate the interactions of particles that make up the universe, such as protons, neutrons, and electrons. Scientists use this information to test predictions of the Standard Model, the prevailing theory describing particle interactions. Notably, relativistic effects, like those in special relativity, are crucial for interpreting these high-speed interactions accurately.

By analyzing the results of such experiments, physicists can gather insights into phenomena like antimatter, the nature of neutrinos, and even explore beyond the Standard Model physics. This aids in understanding both the fundamental particles and the forces that hold matter together, providing clues to the fabric of our universe.
Velocity Calculations
Velocity calculations in the context of special relativity differ significantly from those in classical mechanics. The relativistic velocity addition formula is a key tool in these calculations, used to determine how speeds add up when objects move at relativistic speeds, that is, speeds close to the speed of light.

The formula for relativistic velocity addition is:
  • \( u' = \frac{u + v}{1 + \frac{uv}{c^2}} \)
Where \( u \) is the velocity of one object relative to a stationary observer, \( v \) is the velocity of the other object, and \( u' \) is the velocity of one object relative to the other. This formula ensures that the resulting velocity \( u' \) never exceeds the speed of light \( c \).

In our exercise, this formula helps us find out how fast the second particle is moving relative to the laboratory frame, even when both particles are moving close to the speed of light. Calculations involve plugging in the given velocities, manipulating the equation algebraically, and solving for the unknown velocity. Understanding and applying these calculations are fundamental when discussing the behavior of particles moving at such high speeds.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A meterstick moves past you at great speed. Its motion relative to you is parallel to its long axis. If you measure the length of the moving meterstick to be \(1.00 \mathrm{ft}(1 \mathrm{ft}=0.3048 \mathrm{m})-\) for example, by comparing it with a l-foot ruler that is at rest relative to you, at what speed is the meterstick moving relative to you?

\(\cdot\) An enemy spaceship is moving toward your starfighter with a speed of \(0.400 c,\) as measured in your reference frame. The enemy ship fires a missile toward you at a speed of 0.700\(c\) relative to the enemy ship. (See Figure \(27.24 . )\) (a) What is the speed of the missile relative to you? Express your answer in terms of the speed of light. (b) If you measure the enemy ship to be \(8.00 \times 10^{6} \mathrm{km}\) away from you when the missile is fired, how much time, measured in your frame, will it take the missile to reach you?

\bullet A proton (rest mass \(1.67 \times 10^{-27} \mathrm{kg}\) ) has total energy that is 4.00 times its rest energy. What are (a) the kinetic energy of the proton; (b) the magnitude of the momentum of the proton; (c) the speed of the proton?

\(\cdot\) Inside a spaceship flying past the earth at three-fourths the speed of light, a pendulum is swinging. (a) If each swing takes 1.50 s as measured by an astronat performing an experiment inside the spaceship, how long will the swing take as measured by a person at mission control on earth who is watching the experiment? (b) If each swing takes 1.50 s measured by a person at mission control on earth, how long will it take as measured by the astronaut in the spaceship?

In the year \(2084,\) a spacecraft flies over Moon Station III at a speed of 0.800\(c .\) A scientist on the moon measures the length of the moving spacecraft to be 140 \(\mathrm{m} .\) The spacecraft later lands on the moon, and the same scientist measures the length of the now stationary spacecraft. What value does she get?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.