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A fun-loving \(11.4 \mathrm{~kg}\) otter slides up a hill and then back down to the same place. If she starts up at \(5.75 \mathrm{~m} / \mathrm{s}\) and returns at \(3.75 \mathrm{~m} / \mathrm{s}\) how much mechanical energy did she lose on the hill, and what happened to that energy?

Short Answer

Expert verified
108.55 J of mechanical energy was lost, converted into heat due to friction and air resistance.

Step by step solution

01

Calculate Initial Kinetic Energy

The initial kinetic energy (\( KE_i \)) can be calculated using the formula \( KE = \frac{1}{2} m v^2 \), where \( m \) is mass and \( v \) is velocity. Here, \( m = 11.4 \) kg and initial velocity \( v_i = 5.75 \) m/s. Calculate: \[ KE_i = \frac{1}{2} \times 11.4 \times (5.75)^2 = 188.51 \text{ J} \]
02

Calculate Final Kinetic Energy

The final kinetic energy (\( KE_f \)) is similarly calculated using the same formula, where final velocity \( v_f = 3.75 \) m/s. Calculate: \[ KE_f = \frac{1}{2} \times 11.4 \times (3.75)^2 = 79.96 \text{ J} \]
03

Determine Mechanical Energy Lost

The mechanical energy lost is the difference between the initial and final kinetic energies. Calculate the energy lost: \[ \text{Energy lost} = KE_i - KE_f = 188.51 - 79.96 = 108.55 \text{ J} \]
04

Describe the Fate of Lost Energy

The lost mechanical energy is converted into other forms, likely due to non-conservative forces such as friction and air resistance. This energy is mostly dissipated as heat.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is the energy that an object possesses due to its motion. It can be calculated using the equation \( KE = \frac{1}{2} m v^2 \), where \( m \) is the mass of the object and \( v \) is its velocity. It's important to note that kinetic energy depends on both the mass and the square of the velocity. This means, changing velocity has a significant impact on kinetic energy.
In our otter example, the initial kinetic energy when it begins its slide is calculated with its starting speed of 5.75 m/s. As it ascends the hill and slows down, the kinetic energy decreases until it reaches zero at the hill's peak. When the otter slides back down, its kinetic energy increases again as it picks up speed, ending at a lower value than it started. This change is due to energy conversion and the effects of friction.
Energy Conversion
Energy conversion refers to the process of changing energy from one form to another. In mechanical systems, like the otter sliding up and down the hill, energy conversion is a common occurrence.
- **Potential to Kinetic Energy**: Initially, the otter has kinetic energy. As it moves uphill, some of that energy converts into potential energy until reaching the top, where its speed reduces considerably. - **Kinetic to Thermal**: Naturally, when moving back down, not all potential energy reconverts perfectly back into kinetic energy due to the involvement of forces like friction which converts some kinetic energy to heat. Whenever energy changes its form, some energy might be "lost" from the system's mechanical perspective but is still present in another form, like heat or sound.
Friction
Friction is a force that opposes the relative motion or tendency towards such motion of two surfaces in contact. It plays a critical role in energy conversion processes.
In the case of the sliding otter, friction acts between its body and the hill's surface. Here, friction forces work against the otter's motion, converting part of the mechanical energy (kinetic) into thermal energy (heat), which is why the otter returns at a lower speed of 3.75 m/s.
The energy "lost" due to friction is not gone but has changed form, contributing to objects and surfaces warming slightly.—that warmth comes from this conversion process.
Non-Conservative Forces
Non-conservative forces, like friction and air resistance, are forces where the work done depends on the path taken. This is in contrast to conservative forces, like gravity, where path independence is observed.
The otter's movement up and down the hill involves non-conservative forces. Friction and possibly some air resistance operate during its motion, which impacts the overall energy status more than just gravitational pull. These forces cause a permanent energy transformation. Despite being categorized as energy "losses," they are essential for creating real-life scenarios. Without these non-conservative forces, the otter would regain its entire initial kinetic energy as it descended, which isn't what happens in nature.

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Most popular questions from this chapter

II A slingshot obeying Hooke's law is used to launch pebbles vertically into the air. You observe that if you pull a pebble back \(20.0 \mathrm{~cm}\) against the elastic band, the pebble goes \(6.0 \mathrm{~m}\) high. (a) Assuming that air drag is negligible, how high will the pebble go if you pull it back \(40.0 \mathrm{~cm}\) instead? (b) How far must you pull it back so it will reach \(12.0 \mathrm{~m} ?\) (c) If you pull a pebble that is twice as heavy back \(20.0 \mathrm{~cm},\) how high will it \(\mathrm{go} ?\)

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In action movies there are often chase scenes in which a car becomes airborne. When the car lands, its four suspension springs, one on each wheel, are compressed by the impact. For a typical passenger car, the suspension springs each have a spring constant of about \(500 \mathrm{lb} / \mathrm{in} .\) and a maximum compression of \(6 \mathrm{in} .\) Using this information, estimate the maximum height from which a \(3300 \mathrm{lb}\) car could be dropped without the suspension springs exceeding their maximum compression. Assume that the mass of the car is distributed evenly among the four suspension springs.

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A \(0.5 \mathrm{~kg}\) ball is thrown up into the air with an initial speed of \(5 \mathrm{~m} / \mathrm{s}\) At what height does the gravitational potential energy of the ball equal its initial kinetic energy? What is the maximum height of the ball?

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