/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 66 At the site of a wind farm in No... [FREE SOLUTION] | 91Ó°ÊÓ

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At the site of a wind farm in North Dakota, the average wind speed is \(9.3 \mathrm{~m} / \mathrm{s},\) and the average density of air is \(1.2 \mathrm{~kg} / \mathrm{m}^{3}\) (a) Calculate how much kinetic energy the wind contains, per cubic meter, at this location. (b) No wind turbine can capture all of the energy contained in the wind, the main reason being that capturing all the energy would require stopping the wind completely, meaning that air would stop flowing through the turbine. Suppose a particular turbine has blades with a radius of \(41 \mathrm{~m}\) and is able to capture \(35 \%\) of the available wind energy. What would be the power output of this turbine, under average wind conditions?

Short Answer

Expert verified
(a) 51.894 J/m³. (b) Power output is approximately 715.72 kW.

Step by step solution

01

Calculate Wind Kinetic Energy per Cubic Meter

The kinetic energy of air, per cubic meter, is given by the formula:\[ KE = \frac{1}{2} \rho v^2 \]where, \(\rho\) is the air density \(= 1.2 \mathrm{~kg/m^3}\) and \(v\) is the wind speed \(= 9.3 \mathrm{~m/s}\).Substituting these values:\[ KE = \frac{1}{2} \times 1.2 \mathrm{~kg/m^3} \times (9.3 \mathrm{~m/s})^2 \]Calculate the result:\[ KE = \frac{1}{2} \times 1.2 \times 86.49 \mathrm{~m^2/s^2} \]\[ KE = 0.6 \times 86.49 = 51.894 \mathrm{~J/m^3} \]
02

Determine the Area of the Turbine Blades

The area \(A\) that the turbine blades sweep can be calculated using the formula for the area of a circle:\[ A = \pi r^2 \]where \(r\) is the radius of the blades \(= 41 \mathrm{~m}\).\[ A = 3.14159 \times (41)^2 \]Calculate:\[ A = 3.14159 \times 1681 \mathrm{~m^2} \]\[ A = 5281.75 \mathrm{~m^2} \]
03

Calculate Wind Power Through the Turbine

Wind power \(P\) passing through area \(A\) can be calculated as:\[ P_{total} = \frac{1}{2} \rho A v^3 \]Substitute \(\rho = 1.2 \mathrm{~kg/m^3}\), \(A = 5281.75 \mathrm{~m^2}\), and \(v = 9.3 \mathrm{~m/s}\) into the equation:\[ P_{total} = \frac{1}{2} \times 1.2 \times 5281.75 \times (9.3)^3 \]\[ P_{total} = 0.6 \times 5281.75 \times 804.357 \]\[ P_{total} = 2542.65 \times 804.357 = 2044917.75 \mathrm{~W} \]
04

Calculate the Power Captured by the Turbine

The power captured by the turbine is \(35\%\) of the total wind power through the blades:\[ P_{captured} = 0.35 \times P_{total} \]\[ P_{captured} = 0.35 \times 2044917.75 \mathrm{~W} \]Calculate:\[ P_{captured} = 715721.21 \mathrm{~W}\]Convert to kilowatts:\[ P_{captured} \approx 715.72 \mathrm{~kW}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy of Wind
The kinetic energy of wind is the energy that is possessed by moving air. This energy can be harnessed and converted into useful work, such as electricity. To calculate the kinetic energy contained in wind, we use the formula:
  • \( KE = \frac{1}{2} \rho v^2 \)
In this equation:
  • \( KE \) represents the kinetic energy per unit volume.
  • \( \rho \) is the air density, which represents how much mass of air is packed into a given volume.
  • \( v \) denotes the wind speed, indicating how fast the air particles are moving.
When calculating, the units will typically be in Joules per cubic meter \(( \text{J/m}^3 )\). With North Dakota’s wind averaging a speed of \( 9.3 \text{ m/s} \) and air density at \( 1.2 \text{ kg/m}^3 \), the kinetic energy per cubic meter is\( 51.894 \text{ J/m}^3 \). This provides a basic measure of the energy available in the air at this location.
Air Density
Air density is a crucial factor in determining the energy potential of wind since it affects how much energy is available to be extracted by a wind turbine. The density of air can vary based on several ambient factors such as temperature, altitude, and humidity.In general, the formula for air density \( \rho \) can be understood as:
  • \( \rho = \frac{P}{R \cdot T} \)
where:
  • \( P \) is the atmospheric pressure,
  • \( R \) is the specific gas constant for dry air,
  • \( T \) is the absolute temperature in Kelvin.
In the context of wind power calculations, a higher air density means there is more mass of air moving past the turbine blades, thereby increasing the potential energy available. At an average of \( 1.2 \text{ kg/m}^3 \) in North Dakota, the air is sufficiently dense to provide ample wind energy.
Wind Speed
Wind speed is another key factor in the calculation of wind power, and it links directly to kinetic energy, as noted before. The influence of wind speed is shown by its presence squared in the kinetic energy formula and cubed in the power calculation.
  • \( P \propto v^3 \)
This means even small increases in wind speed lead to significant increases in the energy or power that can be harnessed. For instance, if the wind speed doubles, the power available increases by eightfold. In practice, this dependence on wind speed makes it one of the most critical variables in determining the viability of wind as a power source in any given location. At an average wind speed of \( 9.3 \text{ m/s} \), the site in North Dakota is quite favorable for wind power generation.
Turbine Blade Area
The area covered by turbine blades, or swept area, is fundamental in determining how much wind energy a turbine can capture. The larger the area, the more wind energy can be intercepted.The formula for the area of a circle is used:
  • \( A = \pi r^2 \)
where \( r \) is the radius of the turbine blades. In this case with a radius of \(41 \text{ m} \), the turbine blade area calculates to \( 5281.75 \text{ m}^2 \). This substantial area helps capture more energy as the wind passes through, translating into more potential power output from the turbine.
Energy Conversion Efficiency
Energy conversion efficiency in wind turbines refers to the portion of kinetic energy in the wind that is converted into useful electricity. Not all kinetic energy from wind can be efficiently captured—the theoretical maximum is about 59.3%, known as the Betz limit.In this exercise scenario, the turbine is said to capture 35% of the wind's kinetic energy. This efficiency level represents the effectiveness of the conversion process within the turbine. To find the power captured, multiply the total wind power passing through the turbine by the efficiency percentage:
  • \( P_{captured} = \text{Efficiency Fraction} \times P_{total} \)
Using this, the power output in North Dakota's wind conditions equates to a substantial \( 715.72 \text{ kW} \), reflecting both the vast resources in wind supply and the turbine's design strength.

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