/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 47 A \(1.50 \mathrm{~kg}\) brick is... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A \(1.50 \mathrm{~kg}\) brick is sliding along on a rough horizontal surface at \(13.0 \mathrm{~m} / \mathrm{s}\). If the brick stops in \(4.80 \mathrm{~s}\), how much mechanical energy is lost, and what happens to this energy?

Short Answer

Expert verified
The brick loses 126.75 J of mechanical energy, which is converted into thermal energy due to friction.

Step by step solution

01

Identify the Given Information

We're given a brick with a mass of \(1.50\,\mathrm{kg}\) sliding at an initial velocity of \(13.0\,\mathrm{m/s}\) which comes to a stop in \(4.80\,\mathrm{s}\).
02

Calculate the Initial Kinetic Energy

The initial kinetic energy \( KE_i \) of the brick can be calculated using the formula \( KE_i = \frac{1}{2} m v^2 \), where \( m = 1.50\,\mathrm{kg} \) and \( v = 13.0\,\mathrm{m/s} \). Plug these values into the equation:\[ KE_i = \frac{1}{2} \times 1.50 \times (13.0)^2 \]
03

Solve for Initial Kinetic Energy

Calculate \( KE_i \):\[ KE_i = \frac{1}{2} \times 1.50 \times 169 \]\[ KE_i = 0.75 \times 169 \]\[ KE_i = 126.75 \,\mathrm{J} \]
04

Determine Final Kinetic Energy

Since the brick comes to a stop, its final velocity \( v_f \) is \(0\,\mathrm{m/s}\). Therefore, the final kinetic energy \( KE_f = \frac{1}{2} m v_f^2 = 0\,\mathrm{J} \).
05

Calculate the Mechanical Energy Lost

The mechanical energy lost is the difference between the initial and final kinetic energy:\[ \Delta KE = KE_i - KE_f \]\[ \Delta KE = 126.75 \,\mathrm{J} - 0 \,\mathrm{J} \]\[ \Delta KE = 126.75 \,\mathrm{J} \]
06

Explain What Happens to the Lost Energy

The lost mechanical energy is converted into thermal energy due to friction between the brick and the rough surface.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is the energy an object possesses due to its motion. It depends heavily on the object's mass and velocity. The formula for kinetic energy is given by \[ KE = \frac{1}{2}mv^2 \]where:
  • \( m \) is the mass of the object, measured in kilograms (kg),
  • \( v \) is the velocity of the object, measured in meters per second (m/s).
This formula shows that kinetic energy is directly proportional to the mass of the object and the square of its velocity. When the velocity of an object doubles, its kinetic energy increases by a factor of four, highlighting how powerful speed is in determining kinetic energy.
In the given exercise, the brick initially has a certain amount of kinetic energy when it is moving along the surface. Understanding how this energy is calculated helps to see how much energy will be transformed or lost when the object stops.
Friction
Friction is the resistive force that occurs when two surfaces come in contact and slide against each other. It acts in the opposite direction to the movement, causing objects to slow down or stop entirely.
The role of friction in this exercise is crucial. It is the primary reason why the brick comes to a halt. As the brick slides along the rough surface, the friction force acts against its motion, converting the brick's kinetic energy into other forms of energy.
Friction depends on several factors:
  • The types of materials in contact (rough or smooth)
  • The normal force exerted by the surface, which usually corresponds to the object's weight
  • The surface area of contact, although to a lesser extent compared to the other factors
A rougher surface will produce more friction, leading to greater energy conversion as shown in the problem. This frictional force is essential for everyday activities, providing grip and control, but it also leads to energy losses in systems where efficiency is desired.
Energy Conversion
Energy conversion is the process of changing energy from one form to another. In the context of the exercise, the initial kinetic energy of the moving brick is converted into other forms of energy, primarily thermal energy, known as heat.
This conversion occurs due to the frictional forces acting upon the brick. As the kinetic energy decreases, the frictional force induces microscopic deformations and internal molecular movements, which then manifest as heat.
Energy conversion is a universal concept that is vital in many technological applications. From engines converting chemical energy into electrical energy, to everyday tasks like walking, which converts cellular chemical energy into kinetic energy, the transformation and balance of energy forms is a pivotal element in understanding how systems work.
In the exercise, comprehending the energy conversion process helps us determine how the initial mechanical energy vanishes as the brick comes to a stop.
Thermodynamics
Thermodynamics is the study of energy, heat, and their transformations. It provides the principles to understand the behavior of systems when they undergo changes involving heat transfer and work.
When the brick in the exercise stops due to friction, thermodynamics explains what happens to the energy. The concept of conservation of energy, a key principle in thermodynamics, states that energy cannot be created or destroyed but only transformed from one form to another.
In this case, the mechanical energy lost by the brick is not "gone" but has converted into thermal energy due to friction. The surface and the brick might warm up slightly due to this conversion.
  • First Law of Thermodynamics: Energy conservation during transformations (the lost mechanical energy becomes heat)
  • Second Law of Thermodynamics: Energy transformations increase the entropy, or disorder, of a system, often manifested as converted heat which spreads out
Understanding thermodynamics provides a deeper insight into how and why energy transitions occur, beyond just solving for values. It's the science behind the occurrence of real-world phenomena in all physical processes, helping us utilize energy resources more effectively.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A 575 N woman climbs a staircase that rises at \(53^{\circ}\) above the horizontal and is \(4.75 \mathrm{~m}\) long. Her speed is a constant \(45 \mathrm{~cm} / \mathrm{s}\). (a) Is the given weight a reasonable one for an adult woman? (b) How much has the gravitational potential energy increased by her climbing the stairs? (c) How much work has gravity done on her as she climbed the stairs?

DATA A physics student measures the energy stored in a spring as a function of the distance it is stretched beyond its undistorted length. Her data are given in the table. $$ \begin{array}{cc} x(\mathrm{~cm}) & \text { Energy (J) } \\ \hline 2.6 & 0.34 \\ 6.3 & 2.00 \\ 7.5 & 2.81 \\ 8.2 & 3.36 \end{array} $$ Draw a linearized graph of the data by plotting the spring's energy as a function of the square of the distance it is stretched. Using a linear "best fit" to the data, determine the force constant of the spring.

While a roofer is working on a roof that slants at \(36^{\circ}\) above the horizontal, he accidentally nudges his \(85.0 \mathrm{~N}\) toolbox, causing it to start sliding downward, starting from rest. If it starts \(4.25 \mathrm{~m}\) from the lower edge of the roof, how fast will the toolbox be moving just as it reaches the edge of the roof if the kinetic friction force on it is \(22.0 \mathrm{~N} ?\)

A good workout. You overindulged in a delicious dessert, so you plan to work off the extra calories at the gym. To accomplish this, you decide to do a series of arm raises while holding a \(5.0 \mathrm{~kg}\) weight in one hand. The distance from your elbow to the weight is \(35 \mathrm{~cm}\), and in each arm raise you start with your arm horizontal and pivot it until it is vertical. Assume that the weight of your arm is small enough compared with the weight you are lifting that you can ignore it. As is typical, your muscles are \(20 \%\) efficient in converting the food energy into mechanical energy, with the rest going into heat. If your dessert contained 350 food calories, how many arm raises must you do to work off these calories? Is it realistic to do them all in one session?

On an essentially frictionless horizontal ice-skating rink, a skater moving at \(3.0 \mathrm{~m} / \mathrm{s}\) encounters a rough patch that reduces her speed by \(45 \%\) due to a friction force that is \(25 \%\) of her weight. Use the work-energy theorem to find the length of the rough patch.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.