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While a roofer is working on a roof that slants at \(36^{\circ}\) above the horizontal, he accidentally nudges his \(85.0 \mathrm{~N}\) toolbox, causing it to start sliding downward, starting from rest. If it starts \(4.25 \mathrm{~m}\) from the lower edge of the roof, how fast will the toolbox be moving just as it reaches the edge of the roof if the kinetic friction force on it is \(22.0 \mathrm{~N} ?\)

Short Answer

Expert verified
The toolbox will be moving at approximately 5.2 m/s when it reaches the roof edge.

Step by step solution

01

Determine the net force parallel to the roof

Calculate the gravitational force component down the slope using the formula \[ F_{\text{gravity}} = mg\sin(\theta) \]. Here, \( m = \frac{85.0\, \text{N}}{9.8\, \text{m/s}^2} \) is the mass of the toolbox, and \( \theta = 36^{\circ} \). The net force \( F_{\text{net}} \) is then \( F_{\text{gravity}} - F_{\text{friction}} \).
02

Calculate the acceleration of the toolbox

Using Newton's second law, \( F = ma \), we find the acceleration \( a \) of the toolbox. Rearrange to solve for \( a \): \[ a = \frac{F_{\text{net}}}{m} \]. Use the net force calculated in Step 1 and the mass \( m = 85.0 \text{ N} / 9.8 \text{ m/s}^2 \).
03

Apply the kinematic equation

Use the kinematic equation \( v^2 = u^2 + 2a s \) to find the final velocity \( v \) of the toolbox. Here, \( u = 0 \) (starting from rest) and \( s = 4.25 \text{ m} \). Substitute \( a \) from Step 2 and solve for \( v \).
04

Solve for the velocity

Substitute all the known values into the equation from Step 3: \( v^2 = 0^2 + 2 \cdot a \cdot 4.25 \). Calculate \( v \) by taking the square root of the result.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's Laws of Motion
Newton's laws of motion provide the foundation for understanding the motion of objects. In this exercise, the motion of the toolbox can be understood through these laws. The most relevant is Newton's second law, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration, expressed as \( F = ma \). This law helps us calculate the acceleration of the toolbox by analyzing the forces at play, including gravitational force and friction.
First, we must calculate the net force acting parallel to the roof. The gravitational force component along the slope applies a force down the roof, while kinetic friction opposes the motion, reducing the effective force, or net force. Newton's laws help us quantify this to find the resulting acceleration of the toolbox. Understanding these laws is key when predicting motion as it helps separate forces and understand how each influences the object's movement.

Newton's laws allow us to predict and compute values such as acceleration and velocity, which are essential for any motion-related problem. They ensure that we can define a systematic way of understanding the cause and effect in any kinematic scenario.
Friction
Friction is the resisting force that occurs when two surfaces slide against each other. In physics, it plays a vital role in determining the motion of objects, as seen in this exercise. When the toolbox slides down the roof, friction works against the gravitational force, slowing down its descent.
There are two main types of friction: static and kinetic. Static friction acts on stationary objects, while kinetic friction acts on moving objects. In the toolbox's case, kinetic friction is relevant because the toolbox is already in motion. The friction force of 22.0 N acts upward along the slope, opposing the motion.
The magnitude of kinetic friction depends on two key factors:
  • The nature of the surfaces in contact.
  • The normal force, which is the perpendicular force exerted by a surface supporting the weight of the object.
Understanding friction is important because its magnitude can significantly impact how fast or slow an object moves. It is a crucial factor in determining the net force acting on moving objects.
Gravitational Force
Gravitational force is the force that attracts two bodies towards each other. On Earth, it gives weight to physical objects and causes them to fall towards the ground when dropped. For the toolbox on the roof, this force is represented as part of the force causing it to slide down.
In this scenario, gravity's effect is divided into components perpendicular and parallel to the inclined plane of the roof. The relevant component for motion down the slope is calculated using \( F_{\text{gravity}} = mg\sin(\theta) \), where \( m \) is the mass of the toolbox, \( g \) is the gravitational acceleration (9.8 \( \text{m/s}^2 \)), and \( \theta \) is the angle of the incline.

By examining the parallel component, we can see how gravitational force impacts the motion of the toolbox. This component, along with friction, determines the resultant acceleration and thus the speed at which the toolbox will move. Gravitational force is fundamental in kinematics as it dictates how objects move under the influence of weight.
Kinematic Equations
Kinematic equations are mathematical formulas used to describe the motion of objects. They are particularly useful for finding quantities such as velocity, acceleration, displacement, and time when certain conditions are met.
In this exercise, the relevant kinematic equation is: \[ v^2 = u^2 + 2as \] where:
  • \( v \) is the final velocity.
  • \( u \) is the initial velocity (0, since the toolbox starts from rest).
  • \( a \) is the acceleration.
  • \( s \) is the displacement along the slope.
By substituting the appropriate values derived from the calculations of acceleration and displacement, we can solve for \( v \), the velocity of the toolbox just as it reaches the roof's edge. Kinematic equations are crucial in translating the forces and accelerations we've discussed into tangible speed or velocity values. They bridge the gap from theoretical physics of forces and motion to real-world practical outcomes.

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