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An inductor has inductance of \(0.260 \mathrm{H}\) and carries a current that is decreasing at a uniform rate of \(18.0 \mathrm{~mA} / \mathrm{s}\). Find the self-induced \(\mathrm{emf}\) in this inductor.

Short Answer

Expert verified
The self-induced EMF is 0.00468 V.

Step by step solution

01

Understand the concept of self-induced EMF

Self-induced electromotive force (EMF) in an inductor can be found using Faraday's law of induction. According to this law, the induced EMF is proportional to the rate of change of current through the inductor.
02

Use Faraday's Law formula for inductors

The formula for EMF (\( \mathcal{E} \)) induced in an inductor is given by:\[ \mathcal{E} = -L \frac{dI}{dt} \]where \(L\) is the inductance of the inductor and \(\frac{dI}{dt}\) is the rate of change of current.
03

Substitute the given values into the formula

Here, \(L = 0.260 \, \text{H}\), and the rate of change of current \(\frac{dI}{dt} = -18.0 \, \text{mA/s} = -0.018 \, \text{A/s}\). Substitute these values into the formula:\[ \mathcal{E} = -0.260 \, \text{H} \times (-0.018 \, \text{A/s}) \]
04

Calculate the self-induced EMF

Multiply the values:\[ \mathcal{E} = 0.260 \, \text{H} \times 0.018 \, \text{A/s} = 0.00468 \, \text{V} \]Thus, the self-induced EMF in the inductor is 0.00468 V.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Faraday's law of induction
Faraday's law of induction is a fundamental principle in electromagnetism. It explains how electric currents are generated within a circuit due to a changing magnetic field.
Faraday discovered that an electromotive force (EMF) is induced in a wire loop whenever the magnetic environment of the circuit is altered. This action can occur through changing the magnetic field intensity or the position of the loop.
The law is mathematically defined by the equation:
  • \[ \mathcal{E} = - \frac{d\Phi_B}{dt} \]
Here, \(\mathcal{E}\) represents the induced EMF, \(\Phi_B\) is the magnetic flux, and \(\frac{d\Phi_B}{dt}\) denotes the rate of change of the magnetic flux. The negative sign signifies Lenz's Law, indicating that the induced EMF will act in a way to oppose the change causing it.
Self-induced electromotive force (EMF)
Self-induced electromotive force (EMF) occurs when the changing magnetic field is generated by the current flowing through the coil itself.
This phenomenon is significant in inductors, where a coil creates its own changing magnetic field as current changes occur.
This self-induced EMF is calculated with the formula derived from Faraday's law:
  • \[ \mathcal{E} = -L \frac{dI}{dt} \]
In this equation, \(L\) is the inductance, and \(\frac{dI}{dt}\) is the rate of change of current. The negative sign demonstrates that the EMF induced opposes the change in current direction, aligning with Lenz's Law.
Rate of change of current
The rate of change of current describes how quickly the current in a circuit is changing over time. It measures the speed at which the electric current is increasing or decreasing.
This rate is key to determining the magnitude of the self-induced EMF in an inductor.
In the given solution, the rate of change in the current was provided as a decrease at 18.0 mA/s. Converting this to amperes (
  • \[ 18.0 \, \text{mA/s} = 0.018 \, \text{A/s} \]
We note a negative sign while substituting into the formula to indicate the current is decreasing. The faster the current changes, the larger the induced EMF becomes.
Inductance
Inductance is a property of an electrical circuit, particularly coils, that quantifies its ability to induce an electromotive force due to a change in current.
It is measured in henries (H) and involves the circuit's ability to store energy in a magnetic field created by the current flowing.
  • The larger the inductance, the more resistance a coil has to changes in current, leading to a higher self-induced EMF.
  • An inductor with inductance \(L\) of 0.260 H efficiently stores energy and responds predictably to changes in current over time.
The relationship of inductance with other factors such as the number of coils and the medium surrounding the coil strongly influences the circuit's behavior when exposed to current variations.

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Most popular questions from this chapter

A coil of wire with 200 circular turns of radius \(3.00 \mathrm{~cm}\) is in a uniform magnetic field along the axis of the coil. The coil has \(R=40.0 \Omega\). At what rate, in teslas per second, must the magnetic field be changing to induce a current of \(0.150 \mathrm{~A}\) in the coil?

A very thin \(15.0 \mathrm{~cm}\) copper bar is aligned horizontally along the east-west direction. If it moves horizontally from south to north at \(11.5 \mathrm{~m} / \mathrm{s}\) in a vertically upward magnetic field of \(1.22 \mathrm{~T},\) (a) what potential difference is induced across its ends, and (b) which end (east or west) is at a higher potential? (c) What would be the potential difference if the bar moved from east to west instead?

Quenching an MRI magnet. Magnets carrying very large currents are used to produce the uniform, large-magnitude magnetic fields that are required for magnetic resonance imaging (MRI). A typical MRI magnet may be a solenoid that is \(2.0 \mathrm{~m}\) long and \(1.0 \mathrm{~m}\) in diameter, has a self- inductance of \(4.4 \mathrm{H},\) and carries a current of 750 A. A normal wire carrying that much current would dissipate a great deal of electric power as heat, so most MRI magnets are made with coils of superconducting wire cooled by liquid helium at a temperature just under its boiling point \((4.2 \mathrm{~K})\). After a current is established in the wire, the power supply is disconnected and the magnet leads are shorted together through a piece of superconductor so that the current flows without resistance as long as the liquid helium keeps the magnet cold. Under rare circumstances, a small segment of the magnet's wire may lose its superconducting properties and develop resistance. In this segment, electrical energy is converted to thermal energy, which can boil off some of the liquid helium. More of the wire then warms up and loses its superconducting properties, thus dissipating even more energy as heat. Because the latent heat of vaporization of liquid helium is quite low \((20.9 \mathrm{~kJ} / \mathrm{kg}),\) once the wire begins to warm up, all of the liquid helium may boil off rapidly. This event, called a quench, can damage the magnet. Also, a large volume of helium gas is generated as the liquid helium boils off, causing an asphyxiation hazard, and the resulting rapid pressure buildup can lead to an explosion. You can see how important it is to keep the wire resistance in an MRI magnet at zero and to have devices that detect a quench and shut down the current immediately. If all of the magnetic energy stored in this MRI magnet is converted to thermal energy, how much liquid helium will boil off? A. \(27 \mathrm{~kg}\) B. \(38 \mathrm{~kg}\) C. \(60 \mathrm{~kg}\) D. \(110 \mathrm{~kg}\)

elf-inductance of a straight solenoid. Suppose you were to take the toroidal solenoid in Example 21.10 and unbend it in order to form a straight solenoid. Show that its inductance would be given by the equation \(L=\mu_{0} A N^{2} / l,\) where \(l\) is the length of the newly formed straight solenoid. (Your answer is approximate because \(B\) is actually smaller at the ends than at the center of the straight solenoid. For this reason, your answer is actually an upper limit on the inductance.)

Two coils are wound around the same cylindrical form, like the coils in Example \(21.8 .\) When the current in the first coil is decreasing at a rate of \(0.242 \mathrm{~A} / \mathrm{s},\) the induced emf in the second coil has magnitude \(1.65 \mathrm{mV}\). (a) What is the mutual inductance of the pair of coils? (b) If the second coil has 25 turns, what is the average magnetic flux through each turn when the current in the first coil equals \(1.20 \mathrm{~A} ?\) (c) If the current in the second coil increases at a rate of \(0.360 \mathrm{~A} / \mathrm{s},\) what is the magnitude of the induced emf in the first coil?

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