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A coil of wire with 200 circular turns of radius \(3.00 \mathrm{~cm}\) is in a uniform magnetic field along the axis of the coil. The coil has \(R=40.0 \Omega\). At what rate, in teslas per second, must the magnetic field be changing to induce a current of \(0.150 \mathrm{~A}\) in the coil?

Short Answer

Expert verified
The magnetic field must be changing at approximately -10.6 T/s.

Step by step solution

01

Understand the Problem

To find the rate of change of the magnetic field, we'll use Faraday's law of electromagnetic induction, which states that the electromotive force (EMF) induced in a coil is equal to the rate of change of magnetic flux through the coil. The formula for the induced EMF in terms of current and resistance is: \( \text{EMF} = I \times R \), where \( I \) is the current and \( R \) is the resistance of the coil.
02

Calculate the Required EMF

Given that the current \( I = 0.150 \text{ A} \) and the resistance \( R = 40.0 \Omega \), we can calculate the electromotive force (EMF) induced in the coil:\[ \text{EMF} = I \times R = 0.150 \times 40.0 = 6.0 \text{ V} \]
03

Use Faraday’s Law

According to Faraday's Law, the induced EMF is equal to the rate of change of the magnetic flux times the number of turns \( N \) in the coil:\[ \text{EMF} = -N \left( \frac{d\Phi}{dt} \right) \]Rearranging gives:\[ \frac{d\Phi}{dt} = -\frac{\text{EMF}}{N} \]
04

Calculate the Magnetic Flux Change Rate

The magnetic flux \( \Phi \) through one turn of the coil is given by \( \Phi = B \cdot A \), where \( B \) is the magnetic field and \( A \) is the area of the coil. For a circular coil, \( A = \pi r^2 \) where \( r = 3.00 \text{ cm} = 0.0300 \text{ m} \). Therefore, the area of the coil is:\[ A = \pi \times (0.0300)^2 = 2.83 \times 10^{-3} \text{ m}^2 \]
05

Plug Values into the Equation

Now, substitute the values into the equation for the rate of change of the flux:\[ \frac{d\Phi}{dt} = -\frac{6.0}{200} = -0.030 \text{ T} \cdot \text{m}^2/s \]
06

Find the Rate of Change of the Magnetic Field

The rate of change of the magnetic field \( \frac{dB}{dt} \) can be calculated since \( \frac{d\Phi}{dt} = A \cdot \frac{dB}{dt} \). Solve for \( \frac{dB}{dt} \):\[ \frac{dB}{dt} = \frac{-0.030}{2.83 \times 10^{-3}} \approx -10.6 \text{ T/s} \]
07

Conclusion

The rate at which the magnetic field must be changing to induce the specified current is approximately \(-10.6 \text{ T/s}\). The negative sign indicates that the direction of the change in the magnetic field is opposite to the initial magnetic flux direction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Induced Electromotive Force (EMF)
When a coil is in the presence of a changing magnetic field, an electromotive force (EMF) is generated within the coil. This is due to Faraday's Law of Electromagnetic Induction, which states that an EMF is induced in any closed circuit when the magnetic flux through the circuit changes. The induced EMF can be thought of as the energy provided by the source to move the charges within the circuit, resulting in an electric current.

In this particular exercise, the coil has a current of 0.150 A flowing through it with a resistance of 40.0 Ω. Through Ohm's Law, which relates the current (I), resistance (R), and EMF as \( \text{EMF} = I \times R \), we calculate the EMF needed to produce this current as 6.0 V (Volts). This EMF is effectively the driving force required for the charges to move around the coil under the influence of the changing magnetic field.
Magnetic Flux Change Rate
Magnetic flux \( \Phi \) refers to the amount of magnetic field passing through a given area. It is given by the formula \( \Phi = B \times A \), where \( B \) is the magnetic field strength and \( A \) represents the area. Faraday's Law tells us that the rate of change of magnetic flux over time induces an EMF in the coil.

When the flux changes rapidly, a greater EMF is induced, leading to a higher current if the circuit is closed. In our case, we calculated the rate of change of magnetic flux using the formula \( \frac{d\Phi}{dt} = -\frac{\text{EMF}}{N} \), where \( N \) is the number of turns in the coil (200). By substituting the EMF and number of turns, the rate of change of magnetic flux is found to be \(-0.030 \text{ T} \cdot \text{m}^2/s\). This value is important as it helps us understand how quickly the magnetic environment around the coil is changing.
Coil Resistance and Current
Resistance within a coil is essential in determining how much current flows when an EMF is applied. The relationship between resistance, current, and EMF is characterized by Ohm’s Law. The coil's resistance in the problem is given as 40.0 Ω, suggesting that this value is a limiting factor for the current flow induced by the EMF.

With an EMF of 6.0 V and resistance of 40.0 Ω, the result is a current of 0.150 A in the coil. Resistance is a property that arises due to collisions within the conductive material, and it plays a crucial role in controlling the magnitude of the current. Lower resistance would allow more current for the same EMF, while higher resistance would reduce it. The EMF, resistance, and induced current are tightly interconnected within this context.
Circular Coil Area Calculation
The area of the coil is a key factor in calculating the magnetic flux and, consequently, the rate of change of magnetic field. Given that the coil is circular, the area \( A \) can be determined using the formula \( A = \pi r^2 \), where \( r \) is the radius of the coil.

For this exercise, the radius of the coil is 3.00 cm, which needs to be converted to meters (0.0300 m) to maintain consistency in units. Substituting the radius into the area equation provides us with \( A = \pi \times (0.0300)^2 \approx 2.83 \times 10^{-3} \text{ m}^2 \). Understanding this calculation is essential, as the area directly impacts the amount of magnetic flux that permeates the coil and allows us to determine the rate of change of the magnetic field \( \frac{dB}{dt} \). The accuracy of this area calculation is crucial for the reliable computation of other related quantities.

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Most popular questions from this chapter

An empty cylindrical food container with a lid on it has a diameter of \(5.00 \mathrm{~cm} .\) The container is placed on a table, and a uniform \(1.75 \mathrm{~T}\) magnetic field is applied to the container, with the field directed vertically upward. (a) What is the total magnetic flux through the jar with the lid on? (b) What is the total magnetic flux with the lid off?

A \(12.0 \mathrm{~V}\) dc battery having no appreciable internal resistance, a \(150.0 \Omega\) resistor, an \(11.0 \mathrm{mH}\) inductor, and an open switch are all connected in series. After the switch is closed, what are (a) the time constant for this circuit, (b) the maximum current that flows through it, (c) the current \(73.3 \mu\) s after the switch is closed, and (d) the maximum energy stored in the inductor?

DATA A physics student is studying the behavior of an \(R-L\) circuit, such as the one shown in Figure \(21.30 .\) She measures the potential difference across the inductor \(V_{L}\) as a function of time. According to her lecture notes, \(V_{L}\) should decay with time as \(V_{L}=\mathcal{E} e^{-(t / \tau)},\) where \(\mathcal{E}\) is the emf of the battery and \(\tau=L / R\) is the time constant of the circuit. After closing the switch, she obtains the following data: $$ \begin{array}{cc} \hline \text { Time (s) } & \boldsymbol{V}_{\boldsymbol{L}} \text { ( } \mathbf{V} \text { ) } \\ \hline 0 & 9.0 \\ 10.0 & 4.8 \\ 18.0 & 2.9 \\ 27.0 & 1.7 \\ 35.0 & 1.0 \\ 41.0 & 0.7 \\ \hline \end{array} $$ (a) What is the emf of the battery? (b) Make a semi-log plot of \(V_{L}\) as a function of time. Using a "best fit" to the data, determine the time constant \(\tau\) of the \(R-L\) circuit.

A very thin \(15.0 \mathrm{~cm}\) copper bar is aligned horizontally along the east-west direction. If it moves horizontally from south to north at \(11.5 \mathrm{~m} / \mathrm{s}\) in a vertically upward magnetic field of \(1.22 \mathrm{~T},\) (a) what potential difference is induced across its ends, and (b) which end (east or west) is at a higher potential? (c) What would be the potential difference if the bar moved from east to west instead?

An inductor has inductance of \(0.260 \mathrm{H}\) and carries a current that is decreasing at a uniform rate of \(18.0 \mathrm{~mA} / \mathrm{s}\). Find the self-induced \(\mathrm{emf}\) in this inductor.

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