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At the instant when the current in an inductor is increasing at a rate of \(0.0640 \mathrm{~A} / \mathrm{s}\), the magnitude of the self-induced emf is \(0.0160 \mathrm{~V}\). What is the inductance of the inductor?

Short Answer

Expert verified
The inductance of the inductor is 0.25 H.

Step by step solution

01

Identify the Known Variables

First, identify the given variables from the problem statement. The rate of change of current is given as \( \frac{di}{dt} = 0.0640 \, \text{A/s} \), and the magnitude of the induced emf is \( \varepsilon = 0.0160 \, \text{V} \).
02

Understand the Relation for Inductance

We use the formula for self-induced emf in an inductor: \( \varepsilon = L \frac{di}{dt} \), where \( L \) is the inductance, \( \varepsilon \) is the induced emf, and \( \frac{di}{dt} \) is the rate of change of current.
03

Solve for Inductance

Rearrange the equation \( \varepsilon = L \frac{di}{dt} \) to solve for \( L \). This gives us \( L = \frac{\varepsilon}{\frac{di}{dt}} \).
04

Substitute the Known Values

Substitute \( \varepsilon = 0.0160 \, \text{V} \) and \( \frac{di}{dt} = 0.0640 \, \text{A/s} \) into the equation: \[ L = \frac{0.0160}{0.0640} \]
05

Compute the Inductance

Calculate the division: \( L = \frac{0.0160}{0.0640} = 0.25 \). The inductance \( L \) is found to be \( 0.25 \, \text{H} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Self-induced emf
Self-induced emf refers to the voltage that is generated within an inductor when the current flowing through it changes. This phenomenon occurs due to the principle of electromagnetic induction. In simple terms, when the current in a coil or loop varies, a magnetic field is created or altered, which in turn induces an emf (electromotive force) in the coil itself.
In electrical systems, this self-induced emf is important because it acts to oppose the change in current that originally generated it—a principle known as Lenz's Law. This means the inductor resists changes in the current flowing through it by generating an opposing voltage.
This concept can be seen in the equation for self-induced emf: \[ \varepsilon = -L \frac{di}{dt} \]
  • Where \( \varepsilon \) is the self-induced emf.
  • \( L \) is the inductance.
  • \( \frac{di}{dt} \) is the rate of change of current through the inductor.
Thus, understanding self-induced emf allows us to predict how an inductor will respond to changes in electrical current. It is a cornerstone principle for understanding circuits that involve inductive components.
Current rate of change
The current rate of change in an electrical circuit is a measure of how quickly the current is increasing or decreasing over time. It is expressed in terms of amperes per second (A/s).
This rate of change is crucial in the context of inductors because it directly affects the amount of emf that is induced across the inductor. According to the formula for self-induced emf, \( \varepsilon = -L \frac{di}{dt} \), the induced emf is directly proportional to this rate of change.
In practical terms:
  • If the current increases rapidly, the induced emf will be correspondingly large.
  • If the current changes slowly, the induced emf will be smaller.
Understanding how the rate of current change affects self-induced emf helps in designing circuits to manage effective power distribution and energy efficiency. For example, in systems requiring precise control of current, knowing the rate of change is essential.
Inductor
An inductor is a fundamental component in electrical circuits whose main characteristic is its ability to store energy in a magnetic field when electrical current flows through it. Inductors are typically made by wrapping a coil of wire around a core, which can be air or magnetic material.
The key property of an inductor is its inductance, denoted by \( L \). Inductance quantifies an inductor's ability to resist changes in current and is measured in henries (H).
Key aspects of an inductor:
  • Acts as a short circuit for DC (direct current) after initial surge.
  • Exhibits resistance to changes in AC (alternating current).
  • The magnitude of inductance depends on the number of coils, the cross-sectional area of the coil, and the type of material forming the core.
Inductors are used in various applications such as tuning circuits, filters, transformers, and energy storage systems. When integrated into circuits, they help control current flow and enhance the functioning of AC systems by smoothing out voltage fluctuations and reducing noise.

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Most popular questions from this chapter

A transformer consists of 275 primary windings and 834 secondary windings. If the potential difference across the primary coil is \(25.0 \mathrm{~V}\) (a) what is the voltage across the secondary coil, and (b) what is the current in the secondary coil if it is connected across a \(125 \Omega\) resistor?

Two coils are wound around the same cylindrical form, like the coils in Example \(21.8 .\) When the current in the first coil is decreasing at a rate of \(0.242 \mathrm{~A} / \mathrm{s},\) the induced emf in the second coil has magnitude \(1.65 \mathrm{mV}\). (a) What is the mutual inductance of the pair of coils? (b) If the second coil has 25 turns, what is the average magnetic flux through each turn when the current in the first coil equals \(1.20 \mathrm{~A} ?\) (c) If the current in the second coil increases at a rate of \(0.360 \mathrm{~A} / \mathrm{s},\) what is the magnitude of the induced emf in the first coil?

BIO Measuring blood flow. Blood contains positive and negative ions and so is a conductor. A blood vessel, therefore, can be viewed as an electrical wire. We can even picture the flowing blood as a series of parallel conducting slabs whose thickness is the diameter \(d\) of the vessel moving with speed \(v\). (See Figure \(21.59 .\) ) (a) If the blood vessel is placed in a magnetic field \(\overrightarrow{\boldsymbol{B}}\) perpendicular to the vessel, as in the figure, show that the motional potential difference induced across it is \(\mathcal{E}=v B d\). (b) If you expect that the blood will be flowing at \(15 \mathrm{~cm} / \mathrm{s}\) for a vessel \(5.0 \mathrm{~mm}\) in diameter, what strength of magnetic field will you need to produce a potential difference of \(1.0 \mathrm{mV} ?\) (c) Show that the volume rate of flow \((R)\) of the blood is equal to \(R=\pi \mathcal{E} d / 4 B\). (Note: Although the method developed here is useful in measuring the rate of blood flow in a vessel, it is of limited use in surgery because measurement of the potential \(\mathcal{E}\) must be made directly across the vessel.)

A toroidal solenoid has a self-inductance \(L\) and \(N=100\) coils. How many more coils would have to be added to the solenoid in order to increase its inductance to \(2 L ?\)

A \(5.00 \mu \mathrm{F}\) capacitor is initially charged to a potential of \(16.0 \mathrm{~V}\). It is then connected in series with a \(3.75 \mathrm{mH}\) inductor. (a) What is the total energy stored in this circuit? (b) What is the maximum current in the inductor? What is the charge on the capacitor plates at the instant the current in the inductor is maximal?

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