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If a charged particle is projected in a region of magnetic field, then : (a) the speed of the charged particle continuously changes (b) the magnetic force on the charged particle must be zero (c) the speed of the charged particle remains constant (d) the magnetic force on the charged particle must not be zero

Short Answer

Expert verified
The correct answers are (c) and (d).

Step by step solution

01

Understanding Magnetic Force

In a magnetic field, a charged particle experiences a magnetic force if and only if it is moving. The magnetic force \( F \) is given by the equation \( F = qvB \sin \theta \), where \( q \) is the charge, \( v \) is the speed of the particle, and \( B \) is the magnetic field strength. \( \theta \) is the angle between the velocity vector and the magnetic field vector. If the particle moves parallel to the magnetic field (\( \theta = 0 \) or \( 180^\circ \)), then \( \sin \theta = 0 \) and the force is zero.
02

Analyzing Speed and Direction

If a charged particle moves through a magnetic field, the magnetic force acts perpendicular to the velocity of the particle. This causes the particle to change direction, but not speed. Therefore, the speed of the charged particle remains constant over time, though its direction continuously changes to a circular or helical path.
03

Evaluating the Magnetic Force

Since the magnetic force acts perpendicularly to the velocity, it does no work on the particle. As a result, the kinetic energy and thus the speed of the charged particle does not change; it remains constant throughout the motion.
04

Choosing the Correct Statements

Based on the principles explained: (a) The speed does not change, only direction does, so this is false. (b) The magnetic force is zero only if the particle moves parallel to the magnetic field, which is not stated, so this is false. (c) The speed of the charged particle remains constant as explained, so this is true. (d) The magnetic force can be non-zero if the particle is not moving parallel to the field, so this is true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lorentz Force
The Lorentz Force is a fundamental concept in electromagnetism. It refers to the force experienced by a charged particle in a magnetic field. The formula to calculate this force is given as \( F = qvB \sin \theta \). Here, \( q \) represents the charge of the particle, \( v \) is its velocity, \( B \) is the magnetic field strength, and \( \theta \) is the angle between the particle's velocity and the magnetic field. This force is maximum when the particle moves perpendicular to the field (\( \theta = 90^\circ \)) and zero when moving parallel to it (\( \theta = 0 \) or \( 180^\circ \)).
  • The direction of the Lorentz force is always perpendicular to both the velocity of the charged particle and the direction of the magnetic field.
  • It explains why charged particles in magnetic fields tend to move in circular or spiral paths.
Understanding the Lorentz Force is essential to grasp how magnetic fields affect the trajectory of charged particles.
Trajectory of Charged Particles
When a charged particle enters a magnetic field, its path or trajectory takes on a unique shape due to the influence of the Lorentz Force. As this force acts perpendicularly to the velocity of the particle, it causes the particle to continuously change its direction, forming circular or helical paths.
  • If the particle starts off perpendicular to the magnetic field, it will describe a circular path.
  • When the particle's initial velocity has a component both parallel and perpendicular to the magnetic field, its trajectory becomes a helix.
  • The radius of these trajectories is determined by the equation \( r = \frac{mv}{qB} \), where \( m \) is the particle's mass.
The trajectory demonstrates the fascinating interaction between charged particles and magnetic fields, showing how only the particle's direction changes, whereas its speed remains constant.
Work Done by Magnetic Forces
A core principle of physics is that a force performs work when it moves an object in the direction of the force. However, the magnetic force behaves differently. Because the magnetic force is always perpendicular to the motion of a charged particle, it does no work on the particle. This characteristic has some important implications:
  • The kinetic energy of the particle remains unchanged, implying that its speed remains constant.
  • Magnetic force affects only the direction of the particle's motion, not its magnitude of velocity.
By understanding that magnetic forces do no work, one appreciates why the kinetic energy and speed of a charged particle in a magnetic field are conserved, and why we observe distinctive paths such as circles and helices as opposed to changes in speed.

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Most popular questions from this chapter

A conducting circular loop of radius \(r\) carries a constant current \(I\). It is placed in a uniform magnetic field \(B\) such that \(B_{0}\) is perpendicular to the plane of the loop. The magnetic force acting on the loop is: (a) \(\operatorname{Ir} B_{0}\) (b) \(2 \pi \operatorname{lr} B_{0}\) (c) \(\pi I r B_{0}\) (d) zero

Two charged particles each of mass \(m\) and charge \(q\) are projected in a uniform magnetic field \(B\) with the same speed as such planes of motion of particles are peipendicular to magnetic field \(B\), then (a) they move on circular path of same radii (b) the magnetic forces on them are same to each other (c) the kinetic.energy of particles are same to each other (d) all of the above

A charged particle follows a helical path of unequal pitch in a magnetic field. This means that: (a) the magnetic field is non-uniform (b) the velocity vector is not parallel to the magnetic field (c) the velocity vector is not perpendicular to the magnetic field (d) all of the above

A coil carrying electric current is placed in uniform magnetic field. Then: (a) torque is formed (b) emf is induced (c) both (a) and (b) are correct (d) none of the above.

A circular coil of 100 turns and effective diameter \(20 \mathrm{~cm}\) carries a current of \(0.5 \mathrm{~A}\). It is to be turned in a magnetic field \(B=2 T\) from a position in which \(\theta\) equals zero to one in which \(\theta\) equals \(180^{\circ}\). The work required in this process is: (a) \(\pi\) joule (b) \(2 \pi\) joule (c) \(4 \pi\) joule (d) \(8 \pi\) joule

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