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A circular coil of 100 turns and effective diameter \(20 \mathrm{~cm}\) carries a current of \(0.5 \mathrm{~A}\). It is to be turned in a magnetic field \(B=2 T\) from a position in which \(\theta\) equals zero to one in which \(\theta\) equals \(180^{\circ}\). The work required in this process is: (a) \(\pi\) joule (b) \(2 \pi\) joule (c) \(4 \pi\) joule (d) \(8 \pi\) joule

Short Answer

Expert verified
The work required is \( 4 \pi \) joules, so option (c).

Step by step solution

01

Calculate the Area of the Coil

First, find the area \( A \) of the coil. Since the coil is circular, its radius \( r \) is half of the diameter: \[ r = \frac{20 \text{ cm}}{2} = 10 \text{ cm} = 0.1 \text{ m} \] The area \( A \) of the circle is given by the formula: \[ A = \pi r^2 \] So, substituting the value of \( r \): \[ A = \pi (0.1)^2 = 0.01\pi \text{ m}^2 \]
02

Calculate the Initial Magnetic Moment

The magnetic moment \( \mu \) of the coil is given by: \[ \mu = NAI \] where \( N \) is the number of turns (100), \( A \) is the area calculated previously \( 0.01\pi \text{ m}^2 \), and \( I \) is the current (0.5 A). Substitute these values into the formula: \[ \mu = 100 \times 0.01\pi \times 0.5 = 0.5\pi \text{ Am}^2 \] This is the initial magnetic moment when \( \theta = 0 \).
03

Calculate Work Done in Rotating the Coil

The work done \( W \) in rotating the coil in a magnetic field \( B = 2 \text{ T} \) from \( \theta = 0 \) to \( \theta = 180^\circ \) is given by the change in potential energy, which is: \[ W = \mu B (\cos \theta_{initial} - \cos \theta_{final}) \] Since the coil is initially at \( \theta = 0 \) and is turned to \( \theta = 180^\circ \), this becomes: \[ W = 0.5\pi \times 2 \times (\cos 0^\circ - \cos 180^\circ) \] Substitute the values of \( \cos 0^\circ = 1 \) and \( \cos 180^\circ = -1 \): \[ W = 0.5\pi \times 2 \times (1 - (-1)) = 2\pi \times 2 = 4\pi \text{ joules} \]
04

Conclusion: Determine the Correct Option

From the calculated work \( W = 4\pi \text{ joules} \), the correct choice from the given options is: (c) \( 4 \pi \) joule.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Moment
The magnetic moment is a core concept when dealing with magnetic fields and electrical coils. It represents the strength and direction of a magnetic source. In the case of a coil, the magnetic moment (often denoted by \( \mu \)) is determined by various factors, including the number of turns, the current flowing through the coil, and the coil's area.
The formula for calculating the magnetic moment of a circular coil is \( \mu = NAI \), where:
  • \(N\) is the number of turns in the coil.
  • \(A\) is the effective area covered by the coil.
  • \(I\) is the current passing through the coil.
In practical applications, knowing the magnetic moment helps in determining how a coil will behave when placed in a magnetic field, including the torque experienced and its orientation.
Circular Coil
A circular coil is essentially a loop of wire that is shaped into a circle. It is often characterized by its number of turns and effective diameter. The importance of the coil's circular shape comes from its consistent geometric properties, which simplifies calculations involving fields and forces.
- The diameter of the coil tells us how broad the loop is, and is crucial for calculating the coil’s radius.- With a known radius, you can find the area \( A \) using the formula \( A = \pi r^2 \).
For example, a coil with an effective diameter of \(20 \text{ cm}\) has a radius of \( r = 0.1 \text{ m} \). Calculating its area results in \( A = 0.01\pi \text{ m}^2 \). This area factor is essential for understanding how the coil interacts with magnetic fields.
Potential Energy in Magnetic Fields
When a coil with a magnetic moment \(\mu\) is placed in a magnetic field \(B\), it possesses potential energy that depends on its orientation with respect to the field. This potential energy is expressed as \(U = -\mu B \cos \theta\), where \( \theta \) is the angle between the magnetic moment and the magnetic field.
As the coil rotates in the magnetic field, its potential energy changes, thus work is done on or by the system. During a full rotation from \(0\) to \(180^{\circ}\), the change in potential energy is given by \(\Delta U = \mu B (\cos \theta_{initial} - \cos \theta_{final})\).
This change allows us to calculate the work done, helping understand how energy is necessary to rotate or reorient the coil in the magnetic field, as shown in the exercise.
Angle of Rotation
The angle of rotation plays a pivotal role in determining how a coil behaves in a magnetic field. It is the angle between the magnetic moment of the coil and the applied magnetic field.
  • At \( \theta = 0 \): The magnetic moment is aligned with the field, and the potential energy is at a minimum.
  • At \( \theta = 180^{\circ} \): The magnetic moment is opposite to the field, and the potential energy is at its maximum.
Changing this angle requires work, especially when moving from \(0^{\circ}\) to \(180^{\circ}\). This work is connected to the change in potential energy. As described, for a half-turn rotation (0 to 180 degrees), the work done can be calculated using the change in potential energy equation, providing valuable insights into the system's behavior under magnetic influence.

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Most popular questions from this chapter

A long wire carries a current of \(20 \mathrm{~A}\) along the axis of a solenoid, the field due to the solenoid is \(4 \mathrm{mT}\). The resultant field at a point \(3 \mathrm{~mm}\) from the solenoid axis is: (a) \(1.33 \mathrm{mT}\) (b) \(4.2 \mathrm{mT}\) (c) \(2.1 \mathrm{mT}\) (d) \(8.4 \mathrm{mT}\)

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