Chapter 27: Problem 44
The dimensions of \(\frac{1}{\sqrt{\mu_{0} \varepsilon_{0}}}\) are same as : (a) \(\frac{E}{B}\) (b) \(\frac{B}{E}\) (c) \(\frac{E^{2}}{B^{2}}\) (d) \(\sqrt{\left(\frac{E}{B}\right)}\)
Short Answer
Expert verified
The answer is (a) \(\frac{E}{B}\).
Step by step solution
01
Identify the expression
The expression given is \(\frac{1}{\sqrt{\mu_{0} \varepsilon_{0}}}\). This expression is often related to the speed of light \(c\), expressed as \(c = \frac{1}{\sqrt{\mu_{0} \varepsilon_{0}}}\) in physics.
02
Determine dimensions of speed
The speed of light \(c\) has the dimensions of \( [M^{0}L^{1}T^{-1}] \), which represents meters per second (\(m/s\)).
03
Determine dimensions of \(E\) and \(B\)
The dimensional formula for electric field \(E\) is \([M^{1}L^{1}T^{-3}A^{-1}]\) and for magnetic field \(B\) is \([M^{1}L^{0}T^{-2}A^{-1}]\).
04
Find dimensions of \(\frac{E}{B}\)
Divide the dimensional formula of \(E\) by that of \(B\): \([M^{1}L^{1}T^{-3}A^{-1}] / [M^{1}L^{0}T^{-2}A^{-1}] = [M^{0}L^{1}T^{-1}]\). This matches the dimensions of speed (\([M^{0}L^{1}T^{-1}]\)).
05
Compare with the given options
The dimensions \([M^{0}L^{1}T^{-1}]\) match the dimensions of \(\frac{E}{B}\). Thus, the correct option is \( (a) \frac{E}{B} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Speed of Light
The speed of light, represented as \( c \), is an essential constant in physics. It is approximately \( 299,792,458 \) meters per second in a vacuum. This speed is a fundamental limit, meaning that nothing can travel faster than light in a vacuum. The expression \( c = \frac{1}{\sqrt{\mu_{0} \varepsilon_{0}}} \) gives us insight into how electromagnetic forces govern the speed of light. Here, \( \mu_{0} \) is the permeability of free space, and \( \varepsilon_{0} \) is the permittivity of free space. Together, they define how electromagnetic waves, such as light, propagate through empty space. The dimensions of speed are \([M^{0}L^{1}T^{-1}]\), where:
- \( M^{0} \) refers to no dependency on mass,
- \( L^{1} \) implies a direct dependency on length (in meters, since light travels a certain distance),
- \( T^{-1} \) indicates an inverse dependency on time (as speed is measured as distance per time unit).
Electric Field Dimensions
Electric fields, denoted as \( E \), are vector fields representing the electric force exerted per unit charge at every point in space. An electric field encompasses how charged particles interact at a distance. The dimensional formula for an electric field is \([M^{1}L^{1}T^{-3}A^{-1}]\). This illustrates the fundamental physical quantities that define electric fields:
- \( M^{1} \): Dependence on mass, emphasizing that electric fields relate to forces (which depend on mass),
- \( L^{1} \): Dependency on length, given that the field acts over distances,
- \( T^{-3} \): Indicates the relation to temporal changes in electric fields,
- \( A^{-1} \): Shows the dependency inversely on current (amperes), linking electric fields to the flow of charge.
Magnetic Field Dimensions
Magnetic fields, denoted as \( B \), describe the magnetic force experienced by moving charged particles or magnetic poles. Like electric fields, magnetic fields are a cornerstone of electromagnetism. The dimensional formula of a magnetic field is \([M^{1}L^{0}T^{-2}A^{-1}]\). Let's break this down:
- \( M^{1} \): Implies the dependency on mass, as magnetic forces are a type of mechanical force,
- \( L^{0} \): Indicates no dependency on physical distance in its definition,
- \( T^{-2} \): Signifies a strong relation with time, showing how quickly magnetic fields change influences their effects,
- \( A^{-1} \): Reveals the inverse relationship with electrical current, essential in electromagnetism.