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Use a Maxwell relation from the previous problem and the third law of thermodynamics to prove that the thermal expansion coefficient β(defined in Problem 1.7) must be zero at T=0.

Short Answer

Expert verified

Coefficient of Expansion becomes Zero at T=0.

Step by step solution

01

Given Information

Maxwellrelation:∂V∂TP=-δSδPT

02

Explanation

We know that " The thermal expansion coefficient is defined as the fractional change in volume per unit temperature change".

This means

β=ΔV/VΔTβ=1V∂V∂TP

From the Maxwell relation -δSδPT

So,

β=1V∂V∂TPβ=-1VδSδPT

From the the third law of thermodynamics as T→0, the entropy approaches to zero or some constant value which is independent of pressure.

This means δSδPTbecomes Zero as T→0.and βbecomes 0.

We can conclude that coefficient of expansion becomes zero at T→0.

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Most popular questions from this chapter

Sketch qualitatively accurate graphs of G vs. P for the three phases of H20 (ice, water, and steam) at 0°C. Put all three graphs on the same set of axes, and label the point corresponding to atmospheric pressure. How would |the graphs differ at slightly higher temperatures?

Derive the thermodynamic identity for G (equation 5.23), and from it the three partial derivative relations 5.24.

A formula analogous to that for CP-CVrelates the isothermal and isentropic compressibilities of a material:

κT=κS+TVβ2CP.

(Here κS=-(1/V)(∂V/∂P)Sis the reciprocal of the adiabatic bulk modulus considered in Problem 1.39.) Derive this formula. Also check that it is true for an ideal gas.

In Problem 1.40 you calculated the atmospheric temperature gradient required for unsaturated air to spontaneously undergo convection. When a rising air mass becomes saturated, however, the condensing water droplets will give up energy, thus slowing the adiabatic cooling process.

(a) Use the first law of thermodynamics to show that, as condensation forms during adiabatic expansion, the temperature of an air mass changes by dT=27TPdP-27LnRdnw

where nw is the number of moles of water vapor present, L is the latent heat of vaporization per mole, and I've assumed f=7/5for air.

(b) Assuming that the air is always saturated during this process, the ratio nw/n is a known function of temperature and pressure. Carefully express dnw/dz in terms of dP/dzanddT/dz, and the vapor pressure PvT. Use the Clausius-Clapeyron relation to eliminate dP/dT.

(c) Combine the results of parts (a) and (b) to obtain a formula relating the temperature gradient, dT/dz, to the pressure gradient, dP/dz. Eliminate Figure 5.18. Cumulus clouds form when rising air expands adiabatically and cools to the dew point (Problem 5.44); the onset of condensation slows the cooling, increasing the tendency of the air to rise further (Problem 5.45). These clouds began to form in late morning, in a sky that was clear only an hour before the photo was taken. By mid-afternoon they had developed into thunderstorms. the latter using the "barometric equation" from Problem 1.16. You should finally obtain dTdz=-27MgR1+PvPLRT1+27PvPLRT2

where " width="9">

(d) Calculate the wet adiabatic lapse rate at atmospheric pressure (I bar) and 25°C, then at atmospheric pressure and 0°C. Explain why the results are different, and discuss their implications. What happens at higher altitudes, where the pressure is lower?

Sketch qualitatively accurate graphs of Gvs.Tfor the three phases ofH2O(ice, water, and steam) at atmospheric pressure. Put all three graphs on the same set of axes, and label the temperatures0°Cand 100°C. How would the graphs differ at a pressure of0.001bar?

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