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Chapter 16: Problem 132

Alternating current cannot be measured by DC ammeter because (A) Average value of current for complete cycle is zero. (B) AC changes direction. (C) AC cannot pass through DC ammeter. (D) DC ammeter will get damaged.

Short Answer

Expert verified
The correct answer is (B) AC changes direction. A DC ammeter is designed to measure constant current in one direction and will be unable to handle the changing positive and negative values of AC, resulting in inaccurate measurements.

Step by step solution

01

Understanding Alternating Current (AC) and Direct Current (DC)

Alternating current (AC) is an electric current that reverses its direction periodically, meaning the voltage and current alternate between positive and negative values. On the other hand, direct current (DC) is an electric current that flows in one constant direction, meaning the voltage and current are constant and do not change over time.
02

Understanding Ammeters

An ammeter is an instrument used to measure the electric current in a circuit. Ammeters are designed to work with specific types of current, either AC or DC. A DC ammeter is designed to measure direct current, meaning it is optimized to work with a constant voltage and current direction.
03

Assessing the Options

Let's go through each option and evaluate whether it explains why AC cannot be measured by a DC ammeter: (A) Average value of current for the complete cycle is zero. This statement is true, as the positive and negative values of AC current cancel each other out over a complete cycle. However, this isn't the reason why AC cannot be measured by a DC ammeter, as AC ammeters are designed to measure RMS (root mean square) current and not the average value. (B) AC changes direction. This statement is true, and it is a crucial factor in why a DC ammeter cannot accurately measure AC. The DC ammeter is designed to measure constant current in one direction and will be unable to handle the changing positive and negative values of AC. This option seems like the correct answer, but let's evaluate the other options as well. (C) AC cannot pass through DC ammeter. This statement is not accurate, as AC can pass through a DC ammeter. However, when it does, it will not result in an accurate measurement due to the reasons explained in option (B). (D) DC ammeter will get damaged. This statement is not necessarily true. While it is not recommended to use a DC ammeter to measure AC current, it will not always result in damage to the device. The main problem is the inaccurate measurement.
04

Conclusion

Based on the analysis above, we can conclude that the correct answer is: (B) AC changes direction. This is because a DC ammeter is designed to measure constant current in one direction and will be unable to handle the changing positive and negative values of AC, resulting in inaccurate measurements.

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Most popular questions from this chapter

A coil in the shape of an equilateral triangle of side \(\ell\) is suspended between the pole pieces of a permanent magnet such that \(\vec{B}\) is in the plane of the coil. If due to a current \(i\) in the triangle, a torque \(\tau\) acts on it, the side \(\ell\) of the triangle is (A) \(\frac{2}{\sqrt{3}}\left(\frac{\tau}{B i}\right)\) (B) \(2\left(\frac{\tau}{\sqrt{3} B i}\right)^{1 / 2}\) (C) \(\frac{2}{\sqrt{3}}\left(\frac{\tau}{B i}\right)^{1 / 2}\) (D) \(\frac{1}{\sqrt{3}}\left(\frac{\tau}{B i}\right)\)

A bar magnet, of magnetic moment \(M\), is placed in a magnetic field of induction \(B\). The torque exerted on it is (A) \(\vec{M} \cdot \vec{B}\) (B) \(\vec{B} \times \vec{M}\) (C) \(\vec{M} \times \vec{B}\) (D) \(-\vec{B} \cdot \vec{M}\)

If the flux of magnetic induction through a coil of resistance \(R\) and having \(n\) turns changes from \(\phi_{1}\) to \(\phi_{2}\), then the magnitude of the charge that passes through the coil is (A) \(\frac{\left(\phi_{2}-\phi_{1}\right)}{R}\) (B) \(\frac{n\left(\phi_{2}-\phi_{1}\right)}{R}\) (C) \(\frac{\left(\phi_{2}-\phi_{1}\right)}{n R}\) (D) \(\frac{n R}{\left(\phi_{2}-\phi_{1}\right)}\)

A conducting square loop of side \(L\) and resistance \(R\) moves in its plane with a uniform velocity \(v\) perpendicular to one of its sides. A magnetic field \(B\), constant in space and time, pointing perpendicular and into the plane of the loop exists everywhere as shown in Fig. 16.38. The current induced in the loop is (A) \(B L v / R\) clockwise (B) \(B L v / R\) anti-clockwise (C) \(2 B L v / R\) anti-clockwise (D) Zero

An ideal coil of \(10 \mathrm{H}\) is connected in series with a resistance of \(5 \Omega\) and a battery of \(5 \mathrm{~V} .2\) second after the connection is made. The current flowing in ampere in the circuit is (A) \(\left(1-e^{-1}\right)\) (B) \((1-e)\) (C) \(e\) (D) \(e^{-1}\)
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