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Chapter 10: Problem 54
Boyle's law is applicable for an (A) adiabatic process. (B) isothermal process. (C) isobaric process. (D) isochoric process.
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If \(\gamma\) be the ratio of specific heats of a perfect gas, the number of degrees of freedom of a molecule of the gas is (A) \((\gamma-1)\) (B) \(\frac{3 \gamma-1}{2 \gamma-1}\) (C) \(\frac{2}{\gamma-1}\) (D) \(\frac{9}{2}(\gamma-1)\)
A wooden wheel of radius \(R\) is made of two semicircular parts (see Fig. 10.24). The two parts are held together by a ring made of a metal strip of crosssectional area \(S\) and length \(L . L\) is slightly less than \(2 p R\). To fit the ring on the wheel, it is heated so that its temperature rises by \(\Delta T\) and it just steps over the wheel. As it cools down to surrounding temperature, it presses the semi-circular parts together. If the coefficient of linear expansion of the metal is \(a\) and its Young's modulus is \(Y\), then the force that one part of the wheel applies on the other part is (A) \(2 \pi S Y \alpha \Delta T\) (B) \(S Y \alpha \Delta T\) (C) \(\pi S Y \alpha \Delta T\) (D) \(2 S Y \alpha \Delta T\)
The temperature of cold junction of a thermocouple is \(-20^{\circ} \mathrm{C}\) and the temperature of inversion is \(560^{\circ} \mathrm{C}\). The neutral temperature is (A) \(270^{\circ} \mathrm{C}\) (B) \(560^{\circ} \mathrm{C}\) (C) \(1120^{\circ} \mathrm{C}\) (D) \(290^{\circ} \mathrm{C}\)
Two rods of length \(L_{1}\) and \(L_{2}\) are made of materials whose coefficients of linear expansion are \(\alpha_{1}\) and \(\alpha_{2}\) If the difference between the two lengths is independent of temperature (A) \(\left(L_{1} / L_{2}\right)=\left(\alpha_{1} / \alpha_{2}\right)\) (B) \(\left(L_{1} / L_{2}\right)=\left(\alpha_{2} / \alpha_{1}\right)\) (C) \(L_{1}^{2} \alpha_{1}=L_{2}^{2} \alpha_{2}\) (D) \(\alpha_{1}^{2} L_{1}=\alpha_{2}^{2} L_{2}\)
A \(2 \mathrm{gm}\) bullet moving with a velocity of \(200 \mathrm{~m} / \mathrm{s}\) is brought to a sudden stoppage by an obstacle. The total heat produced goes to the bullet. If the specific heat of the bullet is \(0.03 \mathrm{cal} / \mathrm{gm}-{ }^{\circ} \mathrm{C}\), the rise in its temperature will be (A) \(158.0^{\circ} \mathrm{C}\) (B) \(15.80^{\circ} \mathrm{C}\) (C) \(1.58^{\circ} \mathrm{C}\) (D) \(0.1580^{\circ} \mathrm{C}\)
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