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Two rods of length \(L_{1}\) and \(L_{2}\) are made of materials whose coefficients of linear expansion are \(\alpha_{1}\) and \(\alpha_{2}\) If the difference between the two lengths is independent of temperature (A) \(\left(L_{1} / L_{2}\right)=\left(\alpha_{1} / \alpha_{2}\right)\) (B) \(\left(L_{1} / L_{2}\right)=\left(\alpha_{2} / \alpha_{1}\right)\) (C) \(L_{1}^{2} \alpha_{1}=L_{2}^{2} \alpha_{2}\) (D) \(\alpha_{1}^{2} L_{1}=\alpha_{2}^{2} L_{2}\)

Short Answer

Expert verified
The correct relationship between the lengths of the rods and the coefficients of linear expansion is given by option (B).

Step by step solution

01

Set up the equations for the change in length

Firstly, set up an equation for the change in length of each rod through thermal expansion using the formula \( \Delta L = αL\Delta T \). \n- For Rod 1: \( \Delta L_{1} = α_{1}L_{1}\Delta T \)\n- For Rod 2: \( \Delta L_{2} = α_{2}L_{2}\Delta T \)
02

Formulate the conditions given in the problem

The problem states that the difference in lengths of the two rods is independent of the temperature changes. Hence, we equate the changes - \n\( \Delta L_{1} = \Delta L_{2}\) \nSubstituting the equations from Step 1, we get - \n\( α_{1}L_{1}\Delta T = α_{2}L_{2}\Delta T \)
03

Simplify the equation

Since \( \Delta T \) is a common factor on both sides, it can be cancelled out. This leaves us with - \n\( α_{1}L_{1} = α_{2}L_{2} \)
04

Identify the matching option

Rewrite the resulting equation in the form of options given. Rearranging the equation for \( L_{1} / L_{2} \) yields - \n\( L_{1} / L_{2} = α_{2} / α_{1} \), which corresponds to option (B)

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