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Chapter 10: Problem 89

Cooking gas containers are loaded on to a truck moving with uniform speed. The temperature of the gas molecules inside the containers will (A) increase. (B) decrease. (C) remain same. (D) decrease for some, whereas increase for others.

Short Answer

Expert verified
Since there is no work being done on the gas molecules, and there is no energy exchange between the gas and its surroundings due to the truck's motion, the temperature of the gas molecules will remain the same. The correct answer is (C) remain same.

Step by step solution

01

Analyze the system

The gas containers are being loaded onto a truck that is moving with uniform speed. This means that the truck is moving at a constant speed and not accelerating or decelerating. The motion of the truck will not cause any external force to be applied to the gas molecules inside the containers.
02

Consider the behavior of gas molecules

Gas molecules in a container move randomly, constantly colliding with the walls of the container and each other. The temperature of a gas is related to the average kinetic energy of the gas molecules. If the overall energy of the gas molecules change (either due to work being done on the gas or energy being exchanged between the gas and its surroundings), then the temperature of the gas will change as well.
03

Check for work being done on the gas

In this scenario, since the truck is not accelerating, it is not exerting any net force on the gas molecules. Thus, the truck's motion is not doing work on the gas molecules. The kinetic energy of the gas molecules is not influenced by the motion of the truck, and the random motion of the gas molecules remains essentially the same as when the truck is not moving.
04

Check for energy exchange between the gas and surroundings

A potential way for the temperature of the gas to change is if energy is being transferred between the gas molecules and their surroundings. In this case, there is no mention of any heat exchange or energy transfer process when the containers are loaded onto the truck. So, we assume that there is no energy being exchanged between the gas and its surroundings due to the truck's motion.
05

Make a conclusion

Since there is no work being done on the gas molecules, and there is no energy exchange between the gas and its surroundings due to the truck's motion, the temperature of the gas molecules will remain the same. The correct answer is: (C) remain same.

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Most popular questions from this chapter

We have a jar \(A\) filled with gas characterized by parameters \(P, V\), and \(T\) and another jar \(B\) filled with gas with parameters \(2 P, V / 4\), and \(2 T\), where the symbols have their usual meanings. The ratio of the number of molecules of jar \(A\) to those of jar \(B\) is (A) \(1: 1\) (B) \(1: 2\) (C) \(2: 1\) (D) \(4: 1\)

Heat given to a body which raises its temperature by \(1^{\circ} \mathrm{C}\) is (A) water equivalent. (B) thermal capacity. (C) specific heat. (D) temperature gradient.

An aluminium sphere of \(20 \mathrm{~cm}\) diameter is heated from \(0^{\circ} \mathrm{C}\) to \(100^{\circ} \mathrm{C}\). Its volume changes by (given that the coefficient of linear expansion for aluminium \(\left.\alpha_{A l}=23 \times 10^{-6} /{ }^{\circ} \mathrm{C}\right)\) (A) \(28.9 \mathrm{cc}\) (B) \(2.89 \mathrm{cc}\) (C) \(9.28 \mathrm{cc}\) (D) \(49.8 \mathrm{cc}\)

\(10 \mathrm{gm}\) of ice at \(0^{\circ} \mathrm{C}\) is mixed with \(5 \mathrm{gm}\) of steam at \(100^{\circ} \mathrm{C}\). If latent heat of fusion of ice is \(80 \mathrm{cal} / \mathrm{gm}\) and latent heat of vaporization is \(540 \mathrm{cal} / \mathrm{gm}\). Then at thermal equilibrium (A) temperature of mixture is \(0^{\circ} \mathrm{C}\). (B) temperature of mixture is \(100^{\circ} \mathrm{C}\). (C) mixture contains \(13.33 \mathrm{gm}\) of water and \(1.67 \mathrm{gm}\) of steam. (D) mixture contains \(5.3 \mathrm{gm}\) of ice and \(9.7 \mathrm{gm}\) of water.

1 \(\mathrm{kg}\) water of specific heat \(1 \mathrm{cal} / \mathrm{gm}{ }^{\circ} \mathrm{C}\) is kept in a container at \(10^{\circ} \mathrm{C}\). If \(50 \mathrm{gm}\) of ice at \(0^{\circ} \mathrm{C}\) is required to cool down the water from \(10^{\circ} \mathrm{C}\) to \(0^{\circ} \mathrm{C}\), the water equivalent of container is (Latent of fusion for ice \(=80 \mathrm{cal} / \mathrm{gm}\) and specific heat of water is \(1 \mathrm{cal} / \mathrm{gm}^{\circ} \mathrm{C}\) ) (A) \(1 \mathrm{~kg}\) (B) \(2 \mathrm{~kg}\) (C) \(3 \mathrm{~kg}\) (D) \(\frac{1}{2} \mathrm{~kg}\)
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