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Chapter 10: Problem 3

The temperature of cold junction of a thermocouple is \(-20^{\circ} \mathrm{C}\) and the temperature of inversion is \(560^{\circ} \mathrm{C}\). The neutral temperature is (A) \(270^{\circ} \mathrm{C}\) (B) \(560^{\circ} \mathrm{C}\) (C) \(1120^{\circ} \mathrm{C}\) (D) \(290^{\circ} \mathrm{C}\)

Short Answer

Expert verified
The neutral temperature can be found using the relation N = (I + C) / 2, where I is the inversion temperature (560掳C) and C is the cold junction temperature (-20掳C). Substituting the values, we get N = (560 + (-20)) / 2 = 540 / 2 = 270掳C. Therefore, the neutral temperature is \(270^{\circ} \mathrm{C}\) (option A).

Step by step solution

01

Identify the given temperatures

The cold junction temperature is given as -20掳C, and the temperature of inversion is given as 560掳C.
02

Apply the relation between N, I and C

The formula for the neutral temperature (N) in relation to the inversion temperature (I) and the cold junction temperature (C) is: N = (I + C) / 2
03

Calculate the neutral temperature

Now, plug in the given values for I and C into the formula: N = (560 + (-20)) / 2 N = (540) / 2 N = 270 The neutral temperature is 270掳C. The correct answer is: (A) \(270^{\circ} \mathrm{C}\)

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