/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 On the Celsius scale, the absolu... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 10: Problem 28

On the Celsius scale, the absolute zero of temperature is at (A) \(0^{\circ} \mathrm{C}\) (B) \(-32^{\circ} \mathrm{C}\) (C) \(100^{\circ} \mathrm{C}\) (D) \(-273.15^{\circ} \mathrm{C}\)

Short Answer

Expert verified
On the Celsius scale, the absolute zero of temperature is at \(-273.15^{\circ} \mathrm{C}\) (Option D).

Step by step solution

01

Option A: 0掳C

The Celsius scale is defined based on the freezing point of water at 0掳C and the boiling point of water at 100掳C. Absolute zero temperature is the lowest possible temperature, and we know that even water in its solid state is not at its lowest possible temperature. So 0掳C cannot be absolute zero, which rules out option A.
02

Option B: -32掳C

-32掳C is a temperature where certain substances may freeze or reach certain properties, but it's not the lowest possible temperature possible. Absolute zero is the temperature at which all molecular motion theoretically ceases, and -32掳C doesn't meet that criterion. So, option B is not the correct answer.
03

Option C: 100掳C

100掳C is the boiling point of water on the Celsius scale, which is a higher temperature state compared to freezing or other lower temperature phases. Since absolute zero is the lowest possible temperature, 100掳C cannot be the correct answer, ruling out option C.
04

Option D: -273.15掳C

-273.15掳C is the correct value for absolute zero on the Celsius scale. Absolute zero is defined as 0 Kelvin, and the Kelvin scale is related to the Celsius scale through the formula: \(K = 掳C + 273.15 \) To find the Celsius value of absolute zero, we can set K = 0 and solve for 掳C: \(0 = 掳C + 273.15\) \(-273.15 = 掳C\) Since -273.15掳C is the temperature at which all molecular motion would theoretically cease, option D is the correct answer for the absolute zero temperature on the Celsius scale.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Heat is associated with, (A) Kinetic energy of random motion of molecules. (B) Kinetic energy of orderly motion of molecules. (C) Total kinetic energy of random and orderly motion of molecules. (D) Kinetic energy of random motion in some cases and kinetic energy of orderly motion in other.

An inflated rubber balloon contains 1 mole of an ideal gas, has a pressure \(p\), volume \(V\), and temperature \(T\). If the temperature rises to \(1.1 T\), and the volume is increased to \(1.05 \mathrm{~V}\), the final pressure will be (A) \(1.1 p\) (B) \(p\) (C) less than \(p\) (D) between \(p\) and \(1.1\)

An iron tyre is to be fitted onto a wooden wheel \(1.0 \mathrm{~m}\) in diameter. The diameter of the tyre is \(6 \mathrm{~mm}\) smaller than that of wheel. The tyre should be heated so that its temperature increases by a minimum of (coefficient of volumetric expansion of iron is \(3.6 \times 10^{-5} /{ }^{\circ} \mathrm{C}\) ) (A) \(167^{\circ} \mathrm{C}\) (B) \(334^{\circ} \mathrm{C}\) (C) \(500^{\circ} \mathrm{C}\) (D) \(1000^{\circ} \mathrm{C}\)

At what temperature, the Fahrenheit and the Celsius scales will give numerically equal (but opposite in sign) values? (A) \(-40^{\circ} \mathrm{F}\) and \(40^{\circ} \mathrm{C}\) (B) \(11.43^{\circ} \mathrm{F}\) and \(-11.43^{\circ} \mathrm{C}\) (C) \(-11.43^{\circ} \mathrm{F}\) and \(+11.43^{\circ} \mathrm{C}\) (D) \(+40^{\circ} \mathrm{F}\) and \(-40^{\circ} \mathrm{C}\)

Boyle's law is applicable for an (A) adiabatic process. (B) isothermal process. (C) isobaric process. (D) isochoric process.
See all solutions

Recommended explanations on Physics Textbooks

Energy Physics

Read Explanation

Conservation of Energy and Momentum

Read Explanation

Electric Charge Field and Potential

Read Explanation

Mechanics and Materials

Read Explanation

Linear Momentum

Read Explanation

Space Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.