Chapter 7: Problem 11
Basic Computation: Confidence Interval Suppose \(x\) has a mound-shaped symmetric distribution. A random sample of size 16 has sample mean 10 and sample standard deviation 2 (a) Check Requirements Is it appropriate to use a Student's \(t\) distribution to compute a confidence interval for the population mean \(\mu\) ? Explain. (b) Find a \(90 \%\) confidence interval for \(\mu\) (c) Interpretation Explain the meaning of the confidence interval you computed.
Short Answer
Step by step solution
Check Sample Size Requirement
Symmetry Requirement
T-Score Selection for 90% Confidence
Confidence Interval Calculation
Interpret the Confidence Interval
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Student's t-distribution
You might wonder why it's called the Student's t-distribution. Well, it got its name from a statistician named William Sealy Gosset who published under the pseudonym "Student". The t-distribution is vital because it allows us to make inferences about a population mean when the population standard deviation is unknown and the sample size is small.
In our case, with a sample size of 16, using the Student's t-distribution helps accurately estimate the confidence interval, ensuring our results are reliable despite not having a large sample.
Sample Size Requirement
In this exercise, the sample size is 16, which is considered small. For a small sample, the central limit theorem (which states that the sampling distribution of the sample mean will be normal) does not adequately apply unless the sample comes from a normal distribution. Hence, the use of the t-distribution is appropriate to capture the true variability.
If our sample were larger, say over 30, we might opt to use the standard normal distribution (z-distribution) as it gives similarly reliable estimates in larger sample sizes.
Symmetric Distribution
In the given problem, it's stated that the distribution is mound-shaped and symmetric. This description ensures that the t-distribution can be applied without issue. When the distribution is skewed or not symmetric, the estimates from a t-distribution might become biased.
Symmetry helps in keeping the assumptions of the statistical methods intact, lending more reliability to the confidence interval derived from such data.
T-Score Selection
For a 90% confidence interval and 15 degrees of freedom (since our sample size is 16), we refer to the t-distribution table to find the required t-score. In our example, this value is approximately 1.753. This critical value accounts for the tails of the distribution being heavier, catering to the variability in smaller samples.
Choosing the right t-score ensures that our confidence interval appropriately covers the desired proportion of the data, representing a 90% likelihood that the true population mean is within this interval.
Confidence Interval Calculation
In our example:
- The sample mean \( \bar{x} \) is 10.
- The sample standard deviation \( s \) is 2.
- The t-score (for 90% confidence and 15 degrees of freedom) is 1.753.
- The confidence interval then becomes \( 10 \pm 1.753 \times \frac{2}{\sqrt{16}} = 10 \pm 0.8765 \).
This range indicates that we have a 90% confidence that the true population mean \( \mu \) lies within \( 9.1235 \) to \( 10.8765 \). This means, if we repeated the sampling process many times, about 90% of the intervals we compute would contain the true population mean.