/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 At wind speeds above 1000 centim... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

At wind speeds above 1000 centimeters per second (cm/sec), significant sand- moving events begin to occur. Wind speeds below \(1000 \mathrm{cm} / \mathrm{sec}\) deposit sand, and wind speeds above \(1000 \mathrm{cm} / \mathrm{sec}\) move sand to new locations. The cyclic nature of wind and moving sand determines the shape and location of large dunes (Reference: Hydraulic, Geologic, and Biologic Research at Great Sand Dunes National Monument and Vicinity. Colorado, Proceedings of the National Park Service Research Symposium). At a test site, the prevailing direction of the wind did not change noticeably. However, the velocity did change. Sixty wind speed readings gave an average velocity of \(\bar{x}=1075 \mathrm{cm} / \mathrm{sec} .\) Based on long-term experience, \(\sigma\) can be assumed to be \(265 \mathrm{cm} / \mathrm{sec}\). (a) Find a \(95 \%\) confidence interval for the population mean wind speed at this site. (b) Interpretation Does the confidence interval indicate that the population mean wind speed is such that the sand is always moving at this site? Explain.

Short Answer

Expert verified
The confidence interval is \([1008.57, 1141.43]\ cm/sec, indicating the sand is always moving.

Step by step solution

01

Identify the Given Data

Given data includes the sample mean wind speed, \(\bar{x} = 1075 \ \text{cm/sec}\); the population standard deviation, \(\sigma = 265 \ \text{cm/sec}\); and the number of wind speed readings, \(n = 60\). We need to construct a 95% confidence interval for the population mean \(\mu\).
02

Find the Standard Error of the Mean

The standard error (SE) of the mean is calculated using the formula: \(SE = \frac{\sigma}{\sqrt{n}}\). Substituting the values to find SE: \[ SE = \frac{265}{\sqrt{60}} \approx 34.20 \ \text{cm/sec} \]
03

Determine the Z-score for 95% Confidence

For a 95% confidence interval, the Z-score corresponding to the 95% level of confidence is approximately 1.96, which we'll use in our calculations.
04

Calculate the Confidence Interval

The confidence interval is determined by the formula: \[\bar{x} \pm Z \times SE\]Plugging in the values, we get:\[ 1075 \pm 1.96 \times 34.20 \]This calculates to:\[ 1075 \pm 66.43 \]So, the confidence interval is approximately \([1008.57, 1141.43]\ \text{cm/sec}\).
05

Interpretation of the Confidence Interval

The confidence interval \([1008.57, 1141.43]\) suggests that the population mean wind speed is likely between 1008.57 cm/sec and 1141.43 cm/sec. Since this interval is entirely above 1000 cm/sec, it indicates that the population mean wind speed is such that sand is always moving at this site.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Mean
The population mean, often represented by the symbol \( \mu \), is a measure that indicates the central tendency of a population distribution. In simpler terms, it's the average value in an entire population.
When we talk about wind speed in the context of sand dune movement, it's crucial to understand what happens on average across all measurements.
  • The population mean allows us to gauge what the typical wind speed would be if we could measure every single instance of wind at the site.
  • Knowing the population mean helps us predict how often and how strongly natural events, like sand movement, might occur.
However, obtaining the exact population mean isn't always feasible because it involves measuring every instance, which is why we estimate it using sample data, such as the wind speeds from our test site.
Standard Error
The standard error (SE) of the mean is an important concept when estimating a population parameter. It tells us how accurately we can expect our sample mean to represent the population mean.
  • It's calculated by dividing the population standard deviation \( \sigma \) by the square root of the sample size \( n \).
  • The formula is \( SE = \frac{\sigma}{\sqrt{n}} \).
This calculation shows how much the sample mean will vary from one sample to another.
  • A smaller standard error indicates a more precise estimate of the population mean.
  • In our example, with a standard error of 34.20 cm/sec, we get a clear window around the sample mean, showing the possible range for the actual population mean.
This provides us with insight into the reliability of our estimates and is crucial in constructing confidence intervals.
Z-score
The Z-score is a statistical measure that indicates how many standard deviations an element is from the mean. When constructing a confidence interval for a population mean, knowing the right Z-score is vital.
  • A Z-score translates confidence levels into a standardized form.
  • At a 95% confidence level, the Z-score is approximately 1.96. This means that 95% of the data is expected to fall within 1.96 standard deviations of the mean.
Using the Z-score in our confidence interval calculations helps us determine the margin of error for the estimate of our population mean. With a Z-score of 1.96, we accommodate most values around the mean while assessing the probability that the true mean falls within our calculated interval.
Understanding Z-scores not only assists in constructing intervals but also offers insight into data distribution and significance.
Wind Speed Analysis
Wind speed analysis in the context of sand dunes is significant as it directly impacts the movement and shaping of dunes.
Wind speeds over 1000 cm/sec result in sand moving from one place to another. This process is critical in understanding dune dynamics.
  • In our analysis, we calculated a confidence interval for the population mean wind speed based on sample data.
  • The interval suggests that the mean wind speed is above the threshold necessary for sand movement, indicating a continuous reshaping process.
Analyzing wind speed not only aids in predicting sand movement patterns but also provides a better understanding of the environmental forces at play.
With the data and interval calculated, we could conclude that the mean wind speed allows for constant sand transport, confirming consistent changes in dune landscapes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Why do we use \(1 / 4\) in place of \(p(1-p)\) in formula (22) for sample size when the probability of success \(p\) is unknown? (a) Show that \(p(1-p)=1 / 4-(p-1 / 2)^{2}\). (b) Why is \(p(1-p)\) never greater than \(1 / 4 ?\)

In order to use a normal distribution to compute confidence intervals for \(p,\) what conditions on \(n p\) and \(n q\) need to be satisfied?

In a marketing survey, a random sample, of 730 women shoppers revealed that 628 remained loyal to their favorite supermarket during the past year (i.e., did not switch stores) (Source: Trends in the United States: Consumer Attitudes and the Supermarket, The Research Department, Food Marketing Institute). (a) Let \(p\) represent the proportion of all women shoppers who remain loyal to their favorite supermarket. Find a point estimate for \(p\). (b) Find a \(95 \%\) confidence interval for \(p\). Give a brief explanation of the meaning of the interval. (c) As a news writer, how would you report the survey results regarding the percentage of women supermarket shoppers who remained loyal to their favorite supermarket during the past year? What is the margin of error based on a \(95 \%\) confidence interval?

A random sample is drawn from a population with \(\sigma=12 .\) The sample mean is 30 (a) Compute a \(95 \%\) confidence interval for \(\mu\) based on a sample of size 49 What is the value of the margin of error? (b) Compute a \(95 \%\) confidence interval for \(\mu\) based on a sample of size \(100 .\) What is the value of the margin of error? (c) Compute a \(95 \%\) confidence interval for \(\mu\) based on a sample of size \(225 .\) What is the value of the margin of error? (d) Compare the margins of error for parts (a) through (c). As the sample size increases, does the margin of error decrease? (e) Critical Thinking Compare the lengths of the confidence intervals for parts (a) through (c). As the sample size increases, does the length of a \(90 \%\) confidence interval decrease?

In the Focus Problem at the beginning of this chapter, a study was described comparing the hatch ratios of wood duck nesting boxes. Group I nesting boxes were well separated from each other and well hidden by available brush. There were a total of 474 eggs in group I boxes, of which a field count showed about 270 had hatched. Group II nesting boxes were placed in highly visible locations and grouped closely together. There were a total of 805 eggs in group II boxes, of which a field count showed about 270 had hatched. (a) Find a point estimate \(\hat{p}_{1}\) for \(p_{1},\) the proportion of \(\mathrm{cggs}\) that hatched in group I nest box placements. Find a \(95 \%\) confidence interval for \(p_{1}\) (b) Find a point estimate \(\hat{p}_{2}\) for \(p_{2},\) the proportion of eggs that hatched in group II nest box placements. Find a \(95 \%\) confidence interval for \(p_{2}\) (c) Find a \(95 \%\) confidence interval for \(p_{1}-p_{2} .\) Does the interval indicate that the proportion of eggs hatched from group I nest boxes is higher than, lower than, or equal to the proportion of eggs hatched from group II nest boxes? (d) What conclusions about placement of nest boxes can be drawn? In the article discussed in the Focus Problem, additional concerns are raised about the higher cost of placing and maintaining group I nest box placements. Also at issue is the cost efficiency per successful wood duck hatch.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.