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If a \(90 \%\) confidence interval for the difference of proportions contains some positive and some negative values, what can we conclude about the relationship between \(p_{1}\) and \(p_{2}\) at the \(90 \%\) confidence level?

Short Answer

Expert verified
The proportions p_{1} and p_{2} are not significantly different at the 90% confidence level.

Step by step solution

01

Understanding Confidence Intervals

A confidence interval provides a range of values, derived from sample statistics, that is believed to contain the true value of an unknown population parameter. A 90% confidence interval implies that we are 90% confident that the interval includes the true parameter.
02

Interpreting Confidence Interval For Proportions

If a confidence interval for the difference between two proportions (p_{1} - p_{2}) includes both positive and negative values, this means that the actual difference could be either positive or negative. This indicates that the sample data does not provide enough evidence to conclude a definite direction of the difference at the given confidence level.
03

Relationship Conclusion

Since the interval includes both positive and negative values, we cannot say with 90% confidence that one proportion is definitely larger than the other. Hence, at a 90% confidence level, there is insufficient evidence to determine whether p_{1} is greater than, less than, or equal to p_{2}.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
A confidence interval is a statistical tool used to estimate a range within which we expect a population parameter to lie. Picture it as a spotlight that shines on the range of possible values. When we say a 90% confidence interval, it means if we were to take 100 different samples and compute a confidence interval for each sample, around 90 of those intervals would contain the true population parameter. It's like saying, "We're pretty sure, but there's still a sliver of doubt."

Confidence intervals give us a sense of the precision of our sample estimate. A narrower interval suggests more precision, while a wider one suggests less precision. When interpreting these intervals, it's essential to say, "We're X% confident," rather than "There's an X% probability." The latter misinterprets the statistical nuance, wrongly suggesting a probability distribution over parameter values.
Proportions
Proportions are a way to describe a part of a whole, usually expressed as a fraction, percentage, or ratio. They are a fundamental concept in statistics, often used to summarize categorical data. For instance, if you sampled a population to determine the proportion of people who prefer one brand over another, you'd get an estimate based on your sample data.

When comparing two proportions, like the proportion of people who prefer Brand A versus Brand B, we look at the difference between these two sample proportions. Let's call them \( p_1 \) and \( p_2 \). The difference, \( p_1 - p_2 \), helps understand whether there's a significant preference or not. However, due to sampling variacies, the exact difference in the population might differ slightly, which is why confidence intervals are so important.

By constructing a confidence interval for the difference \( p_1 - p_2 \), we can assess the range of possible differences, offering insight into whether that difference is meaningful or just due to sampling error.
Statistical Inference
Statistical inference is all about making predictions or decisions about a population based on sample data. It's like detective work with numbers, drawing conclusions about an unknown population parameter from a sample. The main goal is to bridge the gap between the data we have and the knowledge we seek.

In the context of our exercise, we are using a confidence interval to infer something about the difference between two proportions based on sample data. The concept of inference here tells us how confident we can be about the sample results reflecting the true population parameter. However, statistical inference inherently involves uncertainty, and it's crucial to communicate this uncertainty along with any statistical conclusions.

For example, when a confidence interval for \( p_1 - p_2 \) includes both positive and negative values, inference becomes more challenging. We can't confidently say whether there's a difference or in which direction it leans. This situation directs us back to understanding the limitations and assumptions of our methods, reminding us always to consider the possibility of sampling errors or random variations when making inferences.

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Most popular questions from this chapter

Answer true or false. Explain your answer. For the same random sample, when the confidence level \(c\) is reduced, the confidence interval for \(\mu\) becomes shorter.

Results of a poll of a random sample of 3003 American adults showed that \(20 \%\) did not know that caffeine contributes to dehydration. The poll was conducted for the Nutrition Information Center and had a margin of error of \(\pm 1.4 \%\). (a) Does the margin of error take into account any problems with the wording of the survey question, interviewer errors, bias from sequence of questions, and so forth? (b) What does the margin of error reflect?

Finance: \(\mathrm{P} / \mathrm{E}\) Ratio The price of a share of stock divided by a company's estimated future earnings per share is called the P/E ratio. High P/E ratios usually indicate "growth" stocks, or maybe stocks that are simply overpriced. Low P/E ratios indicate "value" stocks or bargain stocks. A random sample of 51 of the largest companies in the United States gave the following \(P / E\) ratios (Reference: Forbes). (a) Use a calculator with mean and sample standard deviation keys to verify that \(\bar{x} \approx 25.2\) and \(s \approx 15.5\) (b) Find a \(90 \%\) confidence interval for the \(\mathrm{P} / \mathrm{E}\) population mean \(\mu\) of all large U.S. companies. (c) Find a \(99 \%\) confidence interval for the \(\mathrm{P} / \mathrm{E}\) population mean \(\mu\) of all large U.S. companies. (d) Interpretation Bank One (now merged with J.P. Morgan) had a P/E of \(12,\) AT\&T Wireless had a \(\mathrm{P} / \mathrm{E}\) of \(72,\) and Disney had a \(\mathrm{P} / \mathrm{E}\) of 24 Examine the confidence intervals in parts (b) and (c). How would you describe these stocks at the time the sample was taken? (e) Check Requirements In previous problems, we assumed the \(x\) distribution was normal or approximately normal. Do we need to make such an assumption in this problem? Why or why not? Hint: See the central limit theorem in Section 6.5.

Answer true or false. Explain your answer. If the original \(x\) distribution has a relatively small standard deviation, the confidence interval for \(\mu\) will be relatively short.

As the degrees of freedom increase, what distribution does the Student's \(t\) distribution become more like?

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