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This problem is based on information taken from Life in America's Fifty States by G. S. Thomas. A random sample of \(n_{1}=153\) people ages 16 to 19 was taken from the island of Oahu, Hawaii, and 12 were found to be high school dropouts. Another random sample of \(n_{2}=128\) people ages 16 to 19 was taken from Sweetwater County, Wyoming, and 7 were found to be high school dropouts. Do these data indicate that the population proportion of high school dropouts on Oahu is different (either way) from that of Sweetwater County? Use a \(1 \%\) level of significance.

Short Answer

Expert verified
There is no significant difference in dropout rates between Oahu and Sweetwater County (\(p > 0.01\)).

Step by step solution

01

Formulate the Hypotheses

To determine if there is a difference in dropout rates, set the null hypothesis as \(H_0 : p_1 = p_2\), where \(p_1\) and \(p_2\) are the proportions of dropouts in Oahu and Sweetwater County, respectively. The alternative hypothesis is \(H_a : p_1 eq p_2\). This is a two-tailed test because we are looking for any difference in the dropout rates, either higher or lower.
02

Calculate Sample Proportions

Calculate the proportion of dropouts from each sample: For Oahu: \(\hat{p}_1 = \frac{12}{153} \approx 0.0784\).For Sweetwater: \(\hat{p}_2 = \frac{7}{128} \approx 0.0547\).
03

Calculate the Pooled Proportion

To perform a two-proportion z-test, first calculate the pooled proportion: \[\hat{p} = \frac{x_1 + x_2}{n_1 + n_2} = \frac{12 + 7}{153 + 128} = \frac{19}{281} \approx 0.0676\].
04

Compute the Standard Error

The standard error (SE) for the difference in proportions is calculated as: \[SE = \sqrt{\hat{p} (1 - \hat{p}) \left( \frac{1}{n_1} + \frac{1}{n_2} \right)} = \sqrt{0.0676 \times 0.9324 \left( \frac{1}{153} + \frac{1}{128} \right)} \approx 0.0322\].
05

Calculate the Test Statistic

The z-test statistic is given by: \[z = \frac{\hat{p}_1 - \hat{p}_2}{SE} = \frac{0.0784 - 0.0547}{0.0322} \approx 0.735\].
06

Determine the Critical Value and Decision

For a two-tailed test at a 1% significance level, the critical z-values are \(\pm 2.576\). Since the calculated z-value of \(0.735\) is within the range of \(-2.576\) to \(2.576\), we fail to reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Two-Proportion Z-Test
When you want to compare the proportion of success between two different groups, a two-proportion z-test is your go-to tool. It's like a detective tool for statisticians to see if there’s something interesting between two datasets. In this test, you're looking to see if the difference in proportions between the two groups is significant or if it could have happened just by chance.

In our example, the goal was to figure out if the high school dropout rate in Oahu differed significantly from that in Sweetwater County. Essentially, you compare the dropout rates using a formula that calculates how far their difference deviates from zero. This is done by considering both the difference in sample proportions and the standard error, giving you a z-score. That z-score helps you decide if the difference you see is meaningful or just a fluke due to random sampling. The beauty of the two-proportion z-test is its ability to take different sample sizes from different populations and level the playing field for comparison.
Sample Proportion
Sample proportion is a fundamental concept in inferential statistics. It tells us what proportion of our sample exhibits a particular trait, such as being a high school dropout. You find this value by dividing the number of successes (or instances of the trait) by the total number of observations in your sample.

In Oahu, with 12 dropouts out of 153 people surveyed, the sample proportion is calculated as \( \hat{p}_1 = \frac{12}{153} \approx 0.0784 \). Similarly, in Sweetwater County, with 7 dropouts out of 128 people, the sample proportion is \( \hat{p}_2 = \frac{7}{128} \approx 0.0547 \).

These proportions are an estimate of the true proportion of the population from which the samples were drawn, providing a snapshot of what is happening in the broader population. They are used as a building block to conduct further hypothesis testing and assess whether the observed differences are statistically significant.
Significance Level
The significance level, often denoted as \( \alpha \), is a critical concept in hypothesis testing. It represents the threshold for determining whether a result is statistically significant. In other words, it's the risk you are willing to take of rejecting a true null hypothesis.

For our exercise, a significance level of 1% was used. This means that there is only a 1% chance of incorrectly concluding that there is a difference in dropout rates between Oahu and Sweetwater County when, in fact, there is none (Type I error).

The significance level sets your decision boundary: For a two-tailed hypothesis test, you check if your test statistic falls within the critical values. If it does, as it did with a z-value of 0.735 here, it suggests the difference is not significant and we fail to reject the null hypothesis.
Pooled Proportion
The pooled proportion is used during a two-proportion z-test when the null hypothesis assumes equality between two population proportions. It combines the samples from both groups together to create a weighted average of the sample proportions.

Calculated as \( \hat{p} = \frac{x_1 + x_2}{n_1 + n_2} \), where \( x_1 \) and \( x_2 \) are the number of observed successes in each group, and \( n_1 \) and \( n_2 \) are the sample sizes, the pooled proportion offers a single estimate of the population proportion if the null hypothesis were true.

In this example, the pooled proportion was found to be \( \hat{p} = \frac{12 + 7}{153 + 128} = 0.0676 \). This value is used to calculate the standard error and subsequently helps in determining the z-score for the test.

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Most popular questions from this chapter

What terminology do we use for the probability of rejecting the null hypothesis when it is true? What symbol do we use for this probability? Is this the probability of a type I or a type II error?

Based on information from Harper's Index, \(r_{1}=37\) people out of a random sample of \(n_{1}=100\) adult Americans who did not attend college believe in extraterrestrials. However, out of a random sample of \(n_{2}=100\) adult Americans who did attend college, \(r_{2}=47\) claim that they believe in extraterrestrials. Does this indicate that the proportion of people who attended college and who believe in extraterrestrials is higher than the proportion who did not attend college but believe in extraterrestrials? Use \(\alpha=0.01\).

Would you favor spending more federal tax money on the arts? This question was asked by a research group on behalf of The National Institute (Reference: Painting by Numbers, J. Wypijewski, University of California Press). Of a random sample of \(n_{1}=93\) politically conservative voters, \(r_{1}=21\) responded yes. Another random sample of \(n_{2}=83\) politically moderate voters showed that \(r_{2}=22\) responded yes. Does this information indicate that the population proportion of conservative voters inclined to spend more federal tax money on funding the arts is less than the proportion of moderate voters so inclined? Use \(\alpha=0.05\).

The following is based on information taken from Winter Wind Studies in Rocky Mountain National Park by D. E. Glidden (Rocky Mountain Nature Association). At five weather stations on Trail Ridge Road in Rocky Mountain National Park, the peak wind gusts (in miles per hour) for January and April are recorded below. \begin{tabular}{l|ccccc} \hline Weather Station & 1 & 2 & 3 & 4 & 5 \\ \hline January & 139 & 122 & 126 & 64 & 78 \\ \hline April & 104 & 113 & 100 & 88 & 61 \\ \hline \end{tabular} Does this information indicate that the peak wind gusts are higher in January than in April? Use \(\alpha=0.01\).

Suppose you want to test the claim that a population mean equals \(30 .\) (a) State the null hypothesis. (b) State the alternate hypothesis if you have no information regarding how the population mean might differ from \(30 .\) (c) State the alternate hypothesis if you believe (based on experience or past studies) that the population mean may be greater than \(30 .\) (d) State the alternate hypothesis if you believe (based on experience or past studies) that the population mean may not be as large as 30 .

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