Chapter 8: Problem 18
Harper's Index reported that \(80 \%\) of all supermarket prices end in the digit 9 or \(5 .\) Suppose you check a random sample of 115 items in a supermarket and find that 88 have prices that end in 9 or \(5 .\) Does this indicate that less than \(80 \%\) of the prices in the store end in the digits 9 or 5 ? Use \(\alpha=0.05\)
Short Answer
Step by step solution
Formulate the Hypotheses
Gather the Sample Data
Determine the Standard Error
Calculate the Test Statistic
Determine the Critical Value and Make a Decision
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Null Hypothesis
When we conduct a hypothesis test, the aim is to determine if there is enough statistical evidence to support an alternative hypothesis, suggesting a different scenario.
- The null hypothesis always includes an equality (e.g., \(p = 0.80\)).
- The alternative hypothesis in our test aims to show that the observed sample proportion is less than 80%.
Sample Proportion
In the supermarket pricing example, we took a random sample of 115 items to examine how many prices ended in the digits 9 or 5, which helps us form a sample proportion.
To calculate the sample proportion (\(\hat{p}\)), we divided the number of items meeting our criterion (88) by the total number of items in our sample (115): \(\hat{p} = \frac{88}{115} \approx 0.765\).
- The sample proportion is our best estimate of the true population proportion.
- It serves as the basis for conducting hypothesis tests and calculating confidence intervals.
Z-test for Proportions
The process involves several steps: calculating the standard error, finding the test statistic, and comparing it against a critical value.
In our example:
- The standard error (SE) measures the variability of the sample proportion and is calculated via the formula: \(SE = \sqrt{\frac{p(1-p)}{n}}\).
- We used the hypothesized proportion (\(p = 0.80\)), obtaining a SE of approximately 0.037.
- The Z-test statistic is computed using the formula: \(z = \frac{\hat{p} - p}{SE}\).
Since the calculated Z-value did not exceed the critical value, we did not find strong evidence to reject the null hypothesis, concluding that the true proportion of prices ending in 9 or 5 is still possibly 80% or more.