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Socially conscious investors screen out stocks of alcohol and tobacco makers, firms with poor environmental records, and companies with poor labor practices. Some examples of "good," socially conscious companies are Johnson and Johnson, Dell Computers, Bank of America, and Home Depot. The question is, are such stocks overpriced? One measure of value is the \(\mathrm{P} / \mathrm{E}\), or. price-to-earnings, ratio. High \(\mathrm{P} / \mathrm{E}\) ratios may indicate a stock is overpriced. For the S\&P stock index of all major stocks, the mean \(\mathrm{P} / \mathrm{E}\) ratio is \(\mu=19.4\). A random sample of 36 "socially conscious" stocks gave a \(\mathrm{P} / \mathrm{E}\) ratio sample mean of \(\bar{x}=17.9\), with sample standard deviation \(s=5.2\) (Reference: Morningstar, a financial analysis company in Chicago). Does this indicate that the mean \(\mathrm{P} / \mathrm{E}\) ratio of all socially conscious stocks is different (either way) from the mean \(\mathrm{P} / \mathrm{E}\) ratio of the \(S \& P\) stock index? Use \(\alpha=0.05\).

Short Answer

Expert verified
The test indicates no significant difference; socially conscious stocks' mean P/E ratio is not statistically different from the S&P mean.

Step by step solution

01

Identify the Hypotheses

We need to set up the null hypothesis (\(H_0\)) and the alternative hypothesis (\(H_a\)). The null hypothesis is that the mean P/E ratio of socially conscious stocks is equal to the mean P/E ratio of the S&P stock index (\(\mu = 19.4\)). The alternative hypothesis is that the mean P/E ratio of socially conscious stocks is different from 19.4 (\(\mu eq 19.4\)). Therefore,\[H_0: \mu = 19.4\]\[H_a: \mu eq 19.4\]
02

Calculate the Test Statistic

We will use the t-test for the sample mean because the population standard deviation is unknown and the sample size is 36. The formula for the test statistic is:\[t = \frac{\bar{x} - \mu}{s / \sqrt{n}}\]Substitute the values:\(\bar{x} = 17.9\), \(\mu = 19.4\), \(s = 5.2\), \(n = 36\).\[t = \frac{17.9 - 19.4}{5.2 / \sqrt{36}} = \frac{-1.5}{5.2 / 6}\]Calculate the value:\[t = \frac{-1.5}{0.8667} \approx -1.73\]
03

Determine the Critical Value and Decision Rule

For a two-tailed test at \(\alpha = 0.05\) and 35 degrees of freedom (\(n-1=35\)), we will use the t-distribution table to find the critical value. The critical t-values are approximately \(±2.030\) at \(df = 35\) for a two-tailed test. The decision rule is: if the calculated t-statistic falls outside the range of -2.030 to 2.030, we reject the null hypothesis.
04

Make Decision

Since the calculated t-statistic \(t = -1.73\) does not fall outside the range of the critical values \(-2.030\) to \(2.030\), we do not reject the null hypothesis. Thus, there is not enough evidence to conclude that the mean P/E ratio of socially conscious stocks is different from 19.4.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

t-test
A t-test is a statistical method used to determine if there is a significant difference between the means of two groups. In our case, it helps us check if the average P/E ratio of socially conscious stocks differs from the S&P stock index's average. Since the standard deviation of the entire population is unknown, and we only have a sample size of 36, the t-test is appropriate.

When conducting a t-test, we start by setting up our hypotheses:
  • The null hypothesis (\(H_0\)) states that there is no difference between the means (\(\mu = 19.4\)).
  • The alternative hypothesis (\(H_a\)) claims that there is a difference (\(\mu eq 19.4\)).
Next, we calculate the t-statistic using the formula:\[t = \frac{\bar{x} - \mu}{s / \sqrt{n}}\]Here, \(\bar{x}\) is the sample mean, \(\mu\) is the population mean, \(s\) is the sample standard deviation, and \(n\) is the sample size.

If the resulting t-statistic falls outside the critical values in the t-distribution table, we reject the null hypothesis, indicating a significant difference.
p/e ratio
The P/E ratio, or price-to-earnings ratio, is a vital metric in the investment world, used to evaluate whether a stock is potentially overpriced. It compares a company's current share price to its per-share earnings. A high P/E ratio often suggests that investors expect higher earnings growth in the future compared to companies with a lower P/E ratio.

For socially conscious investors, assessing the P/E ratio helps determine if these ethically chosen stocks perform as well, if not better, in terms of value. In our problem, we're comparing the mean P/E ratio of socially conscious stocks against the standard market average, which is 19.4 according to the S&P index.

If a company's P/E ratio is notably higher than the market average, it might be seen as overpriced. On the other hand, a lower P/E ratio might indicate an undervaluation or lesser growth expectations. Hence, understanding these metrics can guide better investment decisions.
critical value
Critical values are boundaries in hypothesis testing that determine whether to reject the null hypothesis. They are based on the significance level, \(\alpha\), which represents the probability of rejecting the null hypothesis when it is actually true.

In our exercise, we use a two-tailed test with \(\alpha = 0.05\). For the sample size of 36, with degrees of freedom (\(n-1=35\)), we consult the t-distribution table to find critical values. In this case, they are approximately \(\pm 2.030\).

The decision rule in hypothesis testing is straightforward:
  • If the calculated t-statistic exceeds these critical values, it indicates that we have enough evidence to reject the null hypothesis.
  • If it does not exceed these values, we fail to reject the null, suggesting insufficient evidence of a difference between the groups being compared.
socially conscious investing
Socially conscious investing, also known as ethical investing, is a strategy where investors choose stocks based on societal impact, preferring companies with positive environmental, social, and governance (ESG) practices. Investors typically avoid stocks in industries such as tobacco, alcohol, or those with poor labor practices and environmental records.

Examples of such ethically vetted companies include Johnson and Johnson, Bank of America, and Dell Computers. These companies are often seen as contributing positively to society, rather than just focusing on profit.

For investors, socially conscious investing means balancing ethical considerations with financial returns. As the exercise suggests, examining the P/E ratios of these firms compared to industry standards helps investors understand whether they might be compromising financial returns for ethical considerations. It's a growing field, showing that many investors believe financial success can align with positive societal impact.

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Most popular questions from this chapter

Consider a set of data pairs. What is the first step in processing the data for a paired differences test? What is the formula for the sample test statistic \(t ?\) Describe each symbol used in the formula.

A random sample of size 16 from a normal distribution with \(\sigma=3\) produced a sample mean of \(4.5\). (a) Cbeck Requirements Is the \(\bar{x}\) distribution normal? Explain. (b) Compute the sample test statistic \(z\) under the null hypothesis \(H_{0}: \mu=6.3\). (c) For \(H_{1}: \mu<6.3\), estimate the \(P\) -value of the test statistic. (d) For a level of significance of \(0.01\) and the hypotheses of parts (b) and (c), do you reject or fail to reject the null hypothesis? Explain.

Suppose you want to test the claim that a population mean equals \(30 .\) (a) State the null hypothesis. (b) State the alternate hypothesis if you have no information regarding how the population mean might differ from \(30 .\) (c) State the alternate hypothesis if you believe (based on experience or past studies) that the population mean may be greater than \(30 .\) (d) State the alternate hypothesis if you believe (based on experience or past studies) that the population mean may not be as large as 30 .

A random sample of \(n_{1}=16\) communities in western Kansas gave the following information for people under 25 years of age. \(x_{1}:\) Rate of hay fever per 1000 population for people under 25 \(\begin{array}{rr}98 & 90 \\ 125 & 95\end{array}\) 120 125 \(\begin{array}{ll}0 & 128 \\ 25 & 117\end{array}\) \(\begin{array}{ll}28 & 92 \\\ 17 & 97\end{array}\) 123 \(\begin{array}{ll}112 & 93 \\ 127 & 88\end{array}\) \(\begin{array}{lllll}5 & 125 & 117 & 97 & 12\end{array}\) A random sample of \(n_{2}=14\) regions in western Kansas gave the following information for people over 50 years old. \(x_{2}:\) Rate of hay fever per 1000 population for people over 50 \(\begin{array}{ll}95 & 110 \\ 79 & 115\end{array}\) 10 1 \(\begin{array}{llllr}101 & 97 & 112 & 88 & 110 \\ 100 & 89 & 114 & 85 & 96\end{array}\) (Reference: National Center for Health Statistics.) i. Use a calculator to verify that \(\bar{x}_{1}=109.50, s_{1}=15.41, \bar{x}_{2}=99.36\), and \(s_{2} \approx 11.57\) ii. Assume that the hay fever rate in each age group has an approximately normal distribution. Do the data indicate that the age group over 50 has a lower rate of hay fever? Use \(\alpha=0.05\).

In the journal Mental Retardation, an article reported the results of a peer tutoring program to help mildly mentally retarded children learn to read. In the experiment, the mildly retarded children were randomly divided into two groups: the experimental group received peer tutoring along with regular instruction, and the control group received regular instruction with no peer tutoring. There were \(n_{1}=n_{2}=30\) children in each group. The Gates- MacGintie Reading Test was given to both groups before instruction began. For the experimental group, the mean score on the vocabulary portion of the test was \(\bar{x}_{1}=344.5\), with sample standard deviation \(s_{1}=49.1\). For the control group, the mean score on the same test was \(\bar{x}_{2}=354.2\), with sample standard deviation \(s_{2}=50.9\). Use a \(5 \%\) level of significance to test the hypothesis that there was no difference in the vocabulary scores of the two groups before the instruction began.

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