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If the original \(x\) distribution has a relatively small standard deviation, the confidence interval for \(\mu\) will be relatively short.

Short Answer

Expert verified
A small standard deviation results in a more precise, shorter confidence interval for \\(\\mu\\).

Step by step solution

01

Understanding the Relationship

A confidence interval for the mean \(\mu\) is affected by the variability in the data, represented by the standard deviation \(s\). If \(s\) is small, the data points are closely clustered around the mean, leading to a shorter confidence interval.
02

Examine the Formula

The formula for a confidence interval for the mean is given by \[ \bar{x} \pm z \left(\frac{s}{\sqrt{n}}\right) \], where \z\ is the z-score corresponding to the desired confidence level, \ is the sample size, and \s\ is the standard deviation. A smaller \s\ results in a smaller margin of error \(z\frac{s}{\sqrt{n}}\).
03

Impact of a Small Standard Deviation

When the standard deviation \(s\) is small, the term \(\frac{s}{\sqrt{n}}\) becomes smaller, thereby reducing the margin of error. This leads to a shorter confidence interval around the sample mean \(\bar{x}\).
04

Concluding the Impact on Confidence Interval

Since the confidence interval is shorter, the estimate of the population mean \(\mu\) is more precise. Hence, with a small standard deviation, we can say we are more confident that the computed interval contains the true mean.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Deviation
The standard deviation is a crucial measure in statistics that indicates how spread out the data points are in a data set. Imagine you have a bunch of numbers, like test scores. The standard deviation tells you how much those scores deviate, or differ, from the average score (the mean). If the standard deviation is small, it means that most of the scores are clustered close to the average. Proportionally, if it's large, the scores vary greatly from the mean.

The significance of the standard deviation is highlighted when calculating confidence intervals. A small standard deviation results in a more precise estimate of the average, as the data points are not widely scattered. This precision is desirable in statistical analyses, as it allows conclusions to be drawn with greater confidence.

In practical terms: - **Small Standard Deviation:** Data are tightly packed around the mean. - **Large Standard Deviation:** Data are widely spread over a range.

This measurement plays a key role in determining the width of confidence intervals, ultimately affecting the certainty of our findings.
Mean
The mean is often referred to as the "average" and is a fundamental concept in statistics and everyday life. It is calculated by adding up all the numbers in a data set and then dividing by the number of values. Knowing the mean gives you a general idea of the "center" of your data.

For example, if you're looking at the test scores of a class, the mean score tells you what you can expect an average student to receive. It's a simple yet powerful measure that is commonly used to summarize data with a single number.

In relation to confidence intervals, the mean (\( \bar{x} \)) is at the center, with intervals extending on both sides to capture the population mean. This interval tells us that we estimate the true average, taking into account some level of uncertainty. The precision of this estimate depends not only on the mean itself but also on how spread out our data are.
Margin of Error
The margin of error is an essential component of any confidence interval, providing a range within which the true population parameter (like a mean) is expected to fall. It quantifies uncertainty about this estimate.

The formula for determining the margin of error in a confidence interval for the mean is \( z \left( \frac{s}{\sqrt{n}} \right) \). Each component plays a role:- **\( z \):** The z-score, which reflects the confidence level (like 95%).- **\( s \):** The standard deviation, indicating data variability.- **\( n \):** Sample size, where a larger sample results in a smaller fraction and, thus, a smaller margin of error.

When the standard deviation (\( s \)) is smaller or the sample size (\( n \)) is larger, the margin of error decreases, which leads to a shorter, more exact confidence interval.

This means that the smaller the margin of error, the more precise is our estimate of the population mean, providing a sharper focus on data analysis conclusions.

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Most popular questions from this chapter

Consider a \(90 \%\) confidence interval for \(\mu .\) Assume \(\sigma\) is not known. For which sample size, \(n=10\) or \(n=20\), is the critical value \(t_{c}\) larger?

A New York Times/CBS poll asked the question, "What do you think is the most important problem facing this country today?" Nineteen percent of the respondents answered "crime and violence." The margin of sampling error was plus or minus 3 percentage points. Following the convention that the margin of error is based on a \(95 \%\) confidence interval, find a \(95 \%\) confidence interval for the percentage of the population that would respond "crime and violence" to the question asked by the pollsters.

If a \(90 \%\) confidence interval for the difference of proportions contains some positive and some negative values, what can we conclude about the relationship between \(p_{1}\) and \(p_{2}\) at the \(90 \%\) confidence level?

Results of a poll of a random sample of 3003 American adults showed that \(20 \%\) do not know that caffeine contributes to dehydration. The poll was conducted for the Nutrition Information Center and had a margin of error of \(\pm 1.4 \%\). (a) Does the margin of error take into account any problems with the wording of the survey question, interviewer errors, bias from sequence of questions, and so forth? (b) What does the margin of error reflect?

Jobs and productivity! How do banks rate? One way to answer this question is to examine annual profits per employee. Forbes Top Companies, edited by J. T. Davis (John Wiley \& Sons), gave the following data about annual profits per employee (in units of one thousand dollars per employee) for representative companies in financial services. Companies such as Wells Fargo, First Bank System, and Key Banks were included. Assume \(\sigma \approx 10.2\) thousand dollars. $$ \begin{array}{llllllllll} 42.9 & 43.8 & 48.2 & 60.6 & 54.9 & 55.1 & 52.9 & 54.9 & 42.5 & 33.0 & 33.6 \\ 36.9 & 27.0 & 47.1 & 33.8 & 28.1 & 28.5 & 29.1 & 36.5 & 36.1 & 26.9 & 27.8 \\ 28.8 & 29.3 & 31.5 & 31.7 & 31.1 & 38.0 & 32.0 & 31.7 & 32.9 & 23.1 & 54.9 \\ 43.8 & 36.9 & 31.9 & 25.5 & 23.2 & 29.8 & 22.3 & 26.5 & 26.7 & & \end{array} $$ (a) Use a calculator or appropriate computer software to verify that, for the preceding data, \(\bar{x} \approx 36.0\). (b) Let us say that the preceding data are representative of the entire sector of (successful) financial services corporations. Find a \(75 \%\) confidence interval for \(\mu\), the average annual profit per employee for all successful banks. (c)Let us say that you are the manager of a local bank with a large number of employees. Suppose the annual profits per employee are less than 30 thousand dollars per employee. Do you think this might be somewhat low compared with other successful financial institutions? Explain by referring to the confidence interval you computed in part (b). (d) Suppose the annual profits are more than 40 thousand dollars per employee. As manager of the bank, would you feel somewhat better? Explain by referring to the confidence interval you computed in part (b). (e) Repeat parts (b), (c), and (d) for a \(90 \%\) confidence level.

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