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Consider a \(90 \%\) confidence interval for \(\mu .\) Assume \(\sigma\) is not known. For which sample size, \(n=10\) or \(n=20\), is the critical value \(t_{c}\) larger?

Short Answer

Expert verified
The critical value \(t_{c}\) is larger for \(n=10\).

Step by step solution

01

Understanding the Problem

We're given a 90% confidence interval for the mean, \(\mu\), and we need to determine which sample size, \(n=10\) or \(n=20\), will result in a larger critical value \(t_{c}\). Since \(\sigma\) is unknown, we will use a t-distribution.
02

Identify Degrees of Freedom

The degrees of freedom for a t-distribution is calculated as \(n-1\). For \(n=10\), the degrees of freedom is \(10 - 1 = 9\). For \(n=20\), the degrees of freedom is \(20 - 1 = 19\).
03

Find the Critical Values

For a 90% confidence interval, the area in each tail of the t-distribution is \(0.05\). Use a t-table to find \(t_{c}\) for 9 and 19 degrees of freedom. For \(df=9\), \(t_{c}\) is around 1.833. For \(df=19\), \(t_{c}\) is around 1.729.
04

Compare the Critical Values

By comparing the critical values, \(t_{c} = 1.833\) for \(df=9\) is larger than \(t_{c} = 1.729\) for \(df=19\). Thus, the smaller sample size \(n=10\) results in a larger \(t_{c}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the t-distribution
The t-distribution is a type of probability distribution that is used when the sample size is small and the population standard deviation, \( \sigma \), is unknown. Unlike the normal distribution, which is symmetrical and bell-shaped, the t-distribution is also symmetrical but has fatter tails. This indicates that there's a larger probability of values further away from the mean.The t-distribution becomes particularly useful in estimating the mean of a normally distributed population in situations where the sample size is small and \( \sigma \) is unknown. As the sample size increases, the t-distribution approaches the normal distribution. This is because a larger sample provides a more accurate approximation of the population parameter.In summary, the key characteristics of a t-distribution are:
  • Used when the population standard deviation is unknown.
  • Applicable for smaller sample sizes.
  • Has heavier tails compared to the normal distribution.
  • Converges to a normal distribution as sample size increases.
Degrees of Freedom in Statistics
Degrees of freedom are a fundamental concept in statistics that help quantify the flexibility or variability you have when estimating statistical parameters. They are calculated as the sample size minus one, denoted as \( df = n - 1 \). Degrees of freedom are crucial when working with the t-distribution.Think of degrees of freedom as the number of values in a statistical calculation that are free to vary. For instance, when you're estimating the mean from a sample and using it to understand a population, the final sample value is not free to vary once the mean has been determined. This constraint is why we subtract one from the sample size to get the degrees of freedom.In the context of a t-distribution:
  • Higher degrees of freedom indicate a larger sample size.
  • More degrees of freedom mean the t-distribution is closer to a normal distribution.
  • It influences the critical value and interval estimates.
Understanding degrees of freedom helps in calculating the precision and reliability of a sample estimate, contributing to more accurate statistical conclusions.
Decoding Critical Values
Critical values are crucial in statistics as they determine the cutoff points that separate regions of acceptance from regions of rejection in hypothesis testing. In the context of confidence intervals, a critical value is the t-score or z-score that marks the boundary of the confidence interval.For a predefined confidence level, critical values tell us how many standard deviations away from the mean we can expect a parameter estimate to fall, with a certain degree of confidence. When using a t-distribution, critical values are derived from the t-table and depend on both the confidence level and the degrees of freedom. This dependency makes critical values larger for smaller samples with a lower degrees of freedom.When constructing a confidence interval:
  • The significance level, \( \alpha \), reflects the risk we are willing to take of being incorrect.
  • For a 90% confidence interval, the critical value marks where the upper 5% and lower 5% tail off.
  • Smaller sample sizes tend to have larger critical values since fewer data points make larger intervals necessary for the same confidence level.
Understanding critical values helps in accurately determining the range within which a population parameter is expected to lie, ensuring informed statistical decision-making.

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Most popular questions from this chapter

Lorraine was in a hurry when she computed a confidence interval for \(\mu .\) Because \(\sigma\) was not known, she used a Student's \(t\) distribution. However, she accidentally used degrees of freedom \(n\) instead of \(n-1 .\) Will her confidence interval be longer or shorter than one found using the correct degrees of freedom \(n-1 ?\) Explain.

A random sample of 328 medical doctors showed that 171 had a solo practice. (Source: Practice Patterns of General Internal Medicine, American Medical Association.) (a) Let \(p\) represent the proportion of all medical doctors who have a solo practice. Find a point estimate for \(p\). (b) Find a \(95 \%\) confidence interval for \(p .\) Give a brief explanation of the meaning of the interval. (c) As a news writer, how would you report the survey results regarding the percentage of medical doctors in solo practice? What is the margin of error based on a \(95 \%\) confidence interval?

Jobs and productivity! How do banks rate? One way to answer this question is to examine annual profits per employee. Forbes Top Companies, edited by J. T. Davis (John Wiley \& Sons), gave the following data about annual profits per employee (in units of one thousand dollars per employee) for representative companies in financial services. Companies such as Wells Fargo, First Bank System, and Key Banks were included. Assume \(\sigma \approx 10.2\) thousand dollars. $$ \begin{array}{llllllllll} 42.9 & 43.8 & 48.2 & 60.6 & 54.9 & 55.1 & 52.9 & 54.9 & 42.5 & 33.0 & 33.6 \\ 36.9 & 27.0 & 47.1 & 33.8 & 28.1 & 28.5 & 29.1 & 36.5 & 36.1 & 26.9 & 27.8 \\ 28.8 & 29.3 & 31.5 & 31.7 & 31.1 & 38.0 & 32.0 & 31.7 & 32.9 & 23.1 & 54.9 \\ 43.8 & 36.9 & 31.9 & 25.5 & 23.2 & 29.8 & 22.3 & 26.5 & 26.7 & & \end{array} $$ (a) Use a calculator or appropriate computer software to verify that, for the preceding data, \(\bar{x} \approx 36.0\). (b) Let us say that the preceding data are representative of the entire sector of (successful) financial services corporations. Find a \(75 \%\) confidence interval for \(\mu\), the average annual profit per employee for all successful banks. (c)Let us say that you are the manager of a local bank with a large number of employees. Suppose the annual profits per employee are less than 30 thousand dollars per employee. Do you think this might be somewhat low compared with other successful financial institutions? Explain by referring to the confidence interval you computed in part (b). (d) Suppose the annual profits are more than 40 thousand dollars per employee. As manager of the bank, would you feel somewhat better? Explain by referring to the confidence interval you computed in part (b). (e) Repeat parts (b), (c), and (d) for a \(90 \%\) confidence level.

Overproduction of uric acid in the body can be an indication of cell breakdown. This may be an advance indication of illness such as gout, leukemia, or lymphoma (Reference: Manual of Laboratory and Diagnostic Tests, F. Fischbach). Over a period of months, an adult male patient has taken eight blood tests for uric acid. The mean concentration was \(\bar{x}=5.35 \mathrm{mg} / \mathrm{dl} .\) The distribution of uric acid in healthy adult males can be assumed to be normal, with \(\sigma=1.85 \mathrm{mg} / \mathrm{d}\). (a) Find a \(95 \%\) confidence interval for the population mean concentration of uric acid in this patient's blood. What is the margin of error? (b) What conditions are necessary for your calculations? (c) Give a brief interpretation of your results in the context of this problem. (d) Find the sample size necessary for a \(95 \%\) confidence level with maximal error of estimate \(E=1.10\) for the mean concentration of uric acid in this patient's blood.

In a random sample of 519 judges, it was found that 285 were introverts (see reference of Problem 5). (a) Let \(p\) represent the proportion of all judges who are introverts. Find a point estimate for \(p\). (b) Find a \(99 \%\) confidence interval for \(p .\) Give a brief interpretation of the meaning of the confidence interval you have found. (c) Do you think the conditions \(n p>5\) and \(n q>5\) are satisfied in this problem? Explain why this would be an important consideration.

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