/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 An economist wonders if corporat... [FREE SOLUTION] | 91Ó°ÊÓ

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An economist wonders if corporate productivity in some countries is more volatile than in other countries. One measure of a company's productivity is annual percentage yield based on total company assets. Data for this problem are based on information taken from Forbes Top Companies, edited by J. T. Davis. A random sample of leading companies in France gave the following percentage yields based on assets: \(\begin{array}{llllllllllll}4.4 & 5.2 & 3.7 & 3.1 & 2.5 & 3.5 & 2.8 & 4.4 & 5.7 & 3.4 & 4.1\end{array}\) \(\begin{array}{llllllllll}6.8 & 2.9 & 3.2 & 7.2 & 6.5 & 5.0 & 3.3 & 2.8 & 2.5 & 4.5\end{array}\) Use a calculator to verify that \(s^{2}=2.044\) for this sample of French companies. Another random sample of leading companies in Germany gave the following percentage yields based on assets: \(\begin{array}{rrrrrrrrr}3.0 & 3.6 & 3.7 & 4.5 & 5.1 & 5.5 & 5.0 & 5.4 & 3.2\end{array}\) \(\begin{array}{llllllllll}3.5 & 3.7 & 2.6 & 2.8 & 3.0 & 3.0 & 2.2 & 4.7 & 3.2\end{array}\) Use a calculator to verify that \(s^{2} \approx 1.038\) for this sample of German companies. Test the claim that there is a difference (either way) in the population variance of percentage yields for leading companies in France and Germany. Use a \(5 \%\) level of significance. How could your test conclusion relate to the economist's question regarding volatility (data spread) of corporate productivity of large companies in France compared with companies in Germany?

Short Answer

Expert verified
No significant difference in variance; no strong evidence of different volatility.

Step by step solution

01

State the hypotheses

We need to test if there is a significant difference in the variances of the two samples (France and Germany). The null hypothesis \( H_0 \) is that the variances are equal \( \sigma_1^2 = \sigma_2^2 \) and the alternative hypothesis \( H_a \) is that the variances are not equal \( \sigma_1^2 eq \sigma_2^2 \).
02

Calculate the F-statistic

To compare the variances, use the F-statistic: \( F = \frac{s_1^2}{s_2^2} \) where \( s_1^2 = 2.044 \) is the variance for France and \( s_2^2 = 1.038 \) is the variance for Germany. So, \( F = \frac{2.044}{1.038} \approx 1.970 \).
03

Determine degrees of freedom

The degrees of freedom \( df_1 \) for the French sample is \( n_1 - 1 = 21 - 1 = 20 \) and for the German sample \( df_2 = n_2 - 1 = 18 - 1 = 17 \). These will be used to find the critical value from the F-distribution table.
04

Find the critical value

Using an F-distribution table and a significance level \( \alpha = 0.05 \), we find the critical values for \( F_{20,17} \). Checking a table or calculator, the critical value for a two-tailed test at \( \alpha/2 = 0.025 \) is approximately between 0.405 and 2.54.
05

Compare F-statistic to critical value

Our calculated F-statistic is \( 1.970 \). Since \( 1.970 \) is less than the upper critical value \( 2.54 \) and greater than the lower critical value \( 0.405 \), we do not reject the null hypothesis.
06

Make the conclusion

Since we failed to reject the null hypothesis, there is not enough evidence to claim that there is a significant difference in the variances of yields between companies in France and Germany. Thus, there is no significant evidence to suggest different levels of volatility in productivity between the two countries.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

F-distribution
When comparing variances from two different populations, such as French and German companies, the F-distribution plays a crucial role. This distribution is widely used in hypothesis testing to determine if there are significant differences between variances of two populations. It is named after Ronald Fisher.
  • The F-distribution is skewed to the right and defined only for positive values. This makes it suitable for ratios of variances since variances are always non-negative.
  • The shape of the F-distribution depends on two sets of degrees of freedom: one for the numerator (the first sample variance) and another for the denominator (the second sample variance).
  • When utilizing an F-distribution, you compare the calculated F-statistic to a critical value obtained from an F-distribution table, considering the desired level of significance.
This distribution helps determine whether the observed ratio of variances could occur by random chance, making it key in variance analysis.
Variance
Variance is a statistical measurement that describes the spread of data points in a dataset. Specifically, it quantifies how much the data spreads around the mean.
  • A higher variance indicates that the data points are more spread out from the mean, showing more diversity or variability.
  • A lower variance suggests that the data points are closer to the mean, indicating less variability.
In the context of the exercise, comparing the variances of French and German companies helps understand the consistency of their annual percentage yields. Calculating variance involves squaring the standard deviation of a dataset. For example, the variance for French companies is calculated as 2.044, and for German companies, it is approximately 1.038. This shows how variation occurs in terms of productivity within these economies, which can reflect on how stable or volatile they are.
Level of Significance
The level of significance, indicated as \( \alpha \), is a threshold in hypothesis testing that determines when you will reject the null hypothesis. It represents the probability of committing a Type I error, which occurs when you wrongly reject a true null hypothesis.
  • Commonly, levels of significance are set at \( 0.05 \) or \( 0.01 \), indicating a 5% or 1% risk, respectively, of being wrong when rejecting the null hypothesis.
  • The alpha level divides the F-distribution, helping isolate the critical region where we would decide to reject the null hypothesis.
  • In our case, an \( \alpha \) level of 0.05 was used, implying a 95% confidence that any observed effect is not due to random chance.
Choosing the right level of significance is crucial because it balances the risk of false rejection of the null hypothesis against the risk of failing to detect a true difference.

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Most popular questions from this chapter

When using the \(F\) distribution to test variances from two populations, should the random variables from each population be independent or dependent?

The fan blades on commercial jet engines must be replaced when wear on these parts indicates too much variability to pass inspection. If a single fan blade broke during operation, it could severely endanger a flight. A large engine contains thousands of fan blades, and safety regulations require that variability measurements on the population of all blades not exceed \(\sigma^{2}=0.18 \mathrm{~mm}^{2}\). An engine inspector took a random sample of 61 fan blades from an engine. She measured each blade and found a sample variance of \(0.27\) \(\mathrm{mm}^{2}\). Using a \(0.01\) level of significance, is the inspector justified in claiming that all the engine fan blades must be replaced? Find a \(90 \%\) confidence interval for the population standard deviation.

How productive are U.S. workers? One way to answer this question is to study annual profits per employee. A random sample of companies in computers (I), aerospace (II), heavy equipment (III), and broadcasting (IV) gave the following data regarding annual profits per employee (units in thousands of dollars). (Source: Forbes Top Companies, edited by J. T. Davis, John Wiley and Sons.) \(\begin{array}{rrrr}\text { I } & \text { II } & \text { III } & \text { IV } \\\ 27.8 & 13.3 & 22.3 & 17.1 \\ 23.8 & 9.9 & 20.9 & 16.9 \\ 14.1 & 11.7 & 7.2 & 14.3 \\ 8.8 & 8.6 & 12.8 & 15.2 \\ 11.9 & 6.6 & 7.0 & 10.1 \\ & 19.3 & & 9.0\end{array}\) Shall we reject or not reject the claim that there is no difference in population mean annual profits per employee in each of the four types of companies? Use a \(5 \%\) level of significance.

In general, how do the hypotheses for chi-square tests of independence differ from those for chi-square tests of homogeneity? Explain.

Where are the deer? Random samples of square-kilometer plots were taken in different ecological locations of Mesa Verde National Park. The deer counts per square kilometer were recorded and are shown in the following table. (Source: The Mule Deer of Mesa Verde National Park, edited by G. W. Mierau and J. L. Schmidt, Mesa Verde Museum Association.) \(\begin{array}{ccc}\text { Mountain Brush } & \text { Sagebrush Grassland } & \text { Pinon Juniper } \\\ 30 & 20 & 5 \\ 29 & 58 & 7 \\ 20 & 18 & 4 \\ 29 & 22 & 9\end{array}\) Shall we reject or accept the claim that there is no difference in the mean number of deer per square kilometer in these different ecological locations? Use a \(5 \%\) level of significance.

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