/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 In general, how do the hypothese... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In general, how do the hypotheses for chi-square tests of independence differ from those for chi-square tests of homogeneity? Explain.

Short Answer

Expert verified
Chi-square test of independence examines associations between variables, while chi-square test of homogeneity compares distributions across groups.

Step by step solution

01

Understand the Hypotheses for a Chi-Square Test of Independence

A chi-square test of independence is used to determine if there is a significant association between two categorical variables. The null hypothesis ( H_0 ) states that the variables are independent, meaning there is no association between the two. The alternative hypothesis ( H_a ) argues that the variables are dependent, indicating there is an association.
02

Understand the Hypotheses for a Chi-Square Test of Homogeneity

A chi-square test of homogeneity is used to determine if distribution of categories is the same across different populations or groups. The null hypothesis ( H_0 ) states that the distribution of the categories is the same across all groups. The alternative hypothesis ( H_a ) suggests that at least one of the groups has a different distribution.
03

Identify the Key Differences in Hypotheses

Although both tests use similar statistical procedures, their hypotheses differ in focus. The test of independence evaluates relationships between variables within a single population, while the test of homogeneity compares category distributions across multiple populations or groups.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independence Hypothesis
The independence hypothesis is a fundamental concept in chi-square tests. It is specifically used to determine if there are associations between two categorical variables within a single population.

In the context of a chi-square test of independence, the null hypothesis ( H_0 ) suggests that there is no association between the variables, meaning the variables are independent. If the test results show significant evidence to reject the null hypothesis, it indicates that there is an association between the variables, or they are dependent on each other.

For example, if you're testing the independence of gender and preference for a specific product, the independence hypothesis would imply that knowing a person's gender would not help in predicting their preference. If the test suggests a dependency, gender might influence product preference.
Homogeneity Hypothesis
The homogeneity hypothesis in chi-square tests serves a different purpose than the independence hypothesis. It is mainly concerned with comparing the distribution of a single categorical variable across multiple groups or populations.

In a chi-square test of homogeneity, the null hypothesis ( H_0 ) proposes that the distribution of categories is consistent across all groups under consideration. In simple terms, it asserts uniformity across populations concerning the categorical trait. Conversely, the alternative hypothesis ( H_a ) argues that at least one group exhibits a different category distribution.

To illustrate, consider investigating whether different age groups have a consistent pattern in exercising regularly. The homogeneity hypothesis would state that all age groups have similar patterns. If rejected, differences in regular exercise patterns among age groups would be indicated.
Categorical Variables
Categorical variables represent data that can be divided into different categories. They do not have a specific numeric or ordered value but rather involve distinct groups or types.

In the context of chi-square tests, these variables are essential, as they serve as the basis for testing hypotheses. Examples of categorical variables include things like the type of pet owned, brand of smartphone used, or voting preference.

When performing chi-square tests, understanding the nature of categorical variables allows us to generate contingency tables which are crucial for calculations. The ability to discern groups based on traits is vital, which ensures that the constructed hypotheses align correctly with the type of analysis being conducted.
Statistical Tests
Statistical tests, like the chi-square test, are essential tools in analyzing data and making informed decisions based on statistical evidence. They help in validating or refuting hypotheses, allowing us to draw meaningful conclusions from data.

Specifically, chi-square tests excel in examining relationships and patterns among categorical variables. The two main types discussed here are the chi-square test of independence and the chi-square test of homogeneity.

The process involves comparing observed data against what would be expected under the null hypothesis to see if there is a significant difference. This comparison helps determine whether the null hypothesis might be rejected in favor of the alternative hypothesis.

For students and researchers, understanding statistical tests is crucial, as they are often applied in numerous fields such as social sciences, biology, and market research, making them integral to any analytical toolkit.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For chi-square distributions, as the number of degrees of freedom increases, does any skewness increase or decrease? Do chi-square distributions become more symmetric (and normal) as the number of degrees of freedom becomes larger and larger?

Where are the deer? Random samples of square-kilometer plots were taken in different ecological locations of Mesa Verde National Park. The deer counts per square kilometer were recorded and are shown in the following table. (Source: The Mule Deer of Mesa Verde National Park, edited by G. W. Mierau and J. L. Schmidt, Mesa Verde Museum Association.) \(\begin{array}{ccc}\text { Mountain Brush } & \text { Sagebrush Grassland } & \text { Pinon Juniper } \\\ 30 & 20 & 5 \\ 29 & 58 & 7 \\ 20 & 18 & 4 \\ 29 & 22 & 9\end{array}\) Shall we reject or accept the claim that there is no difference in the mean number of deer per square kilometer in these different ecological locations? Use a \(5 \%\) level of significance.

How productive are U.S. workers? One way to answer this question is to study annual profits per employee. A random sample of companies in computers (I), aerospace (II), heavy equipment (III), and broadcasting (IV) gave the following data regarding annual profits per employee (units in thousands of dollars). (Source: Forbes Top Companies, edited by J. T. Davis, John Wiley and Sons.) \(\begin{array}{rrrr}\text { I } & \text { II } & \text { III } & \text { IV } \\\ 27.8 & 13.3 & 22.3 & 17.1 \\ 23.8 & 9.9 & 20.9 & 16.9 \\ 14.1 & 11.7 & 7.2 & 14.3 \\ 8.8 & 8.6 & 12.8 & 15.2 \\ 11.9 & 6.6 & 7.0 & 10.1 \\ & 19.3 & & 9.0\end{array}\) Shall we reject or not reject the claim that there is no difference in population mean annual profits per employee in each of the four types of companies? Use a \(5 \%\) level of significance.

A new thermostat has been engineered for the frozen food cases in large supermarkets. Both the old and new thermostats hold temperatures at an average of \(25^{\circ} \mathrm{F}\). However, it is hoped that the new thermostat might be more dependable in the sense that it will hold temperatures closer to \(25^{\circ} \mathrm{F}\). One frozen food case was equipped with the new thermostat, and a random sample of 21 temperature readings gave a sample variance of \(5.1 .\) Another similar frozen food case was equipped with the old thermostat, and a random sample of 16 temperature readings gave a sample variance of \(12.8 .\) Test the claim that the population variance of the old thermostat temperature readings is larger than that for the new thermostat. Use a \(5 \%\) level of significance. How could your test conclusion relate to the question regarding the dependability of the temperature readings?

The following problem is based on information taken from Accidents in North American Mountaineering (jointly published by The American Alpine Club and The Alpine Club of Canada). Let \(x\) represent the number of mountain climbers killed each year. The long-term variance of \(x\) is approximately \(\sigma^{2}=136.2\). Suppose that for the past 8 years, the variance has been \(s^{2}=115.1 .\) Use a \(1 \%\) level of significance to test the claim that the recent variance for number of mountain-climber deaths is less than \(136.2\). Find a \(90 \%\) confidence interval for the population variance.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.