/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 How productive are U.S. workers?... [FREE SOLUTION] | 91Ó°ÊÓ

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How productive are U.S. workers? One way to answer this question is to study annual profits per employee. A random sample of companies in computers (I), aerospace (II), heavy equipment (III), and broadcasting (IV) gave the following data regarding annual profits per employee (units in thousands of dollars). (Source: Forbes Top Companies, edited by J. T. Davis, John Wiley and Sons.) \(\begin{array}{rrrr}\text { I } & \text { II } & \text { III } & \text { IV } \\\ 27.8 & 13.3 & 22.3 & 17.1 \\ 23.8 & 9.9 & 20.9 & 16.9 \\ 14.1 & 11.7 & 7.2 & 14.3 \\ 8.8 & 8.6 & 12.8 & 15.2 \\ 11.9 & 6.6 & 7.0 & 10.1 \\ & 19.3 & & 9.0\end{array}\) Shall we reject or not reject the claim that there is no difference in population mean annual profits per employee in each of the four types of companies? Use a \(5 \%\) level of significance.

Short Answer

Expert verified
Calculate an F-statistic using ANOVA, compare it with F-critical, and make a decision. Reject null if F > F-critical.

Step by step solution

01

Understanding the Hypotheses

We begin by setting up our null and alternative hypotheses. The null hypothesis (\(H_0\)) claims that there is no difference in the mean annual profits per employee among the four types of companies: computers, aerospace, heavy equipment, and broadcasting. Formally, \(H_0: \mu_1 = \mu_2 = \mu_3 = \mu_4\). The alternative hypothesis (\(H_a\)) states that at least one mean is different: \(H_a: \text{not all } \mu_i \text{ are equal}\).
02

Choosing the Test

Since we are comparing the means of more than two independent groups, we use the ANOVA (Analysis of Variance) test. ANOVA will help us determine whether there is a statistically significant difference between the means of the four groups.
03

Calculating the ANOVA

We organize data in each category: - Computers (I): 27.8, 23.8, 14.1, 8.8, 11.9 - Aerospace (II): 13.3, 9.9, 11.7, 8.6, 6.6, 19.3 - Heavy Equipment (III): 22.3, 20.9, 7.2, 12.8, 7.0 - Broadcasting (IV): 17.1, 16.9, 14.3, 15.2, 10.1, 9.0. Next, calculate the group means, the overall mean, and then compute the sum of squares between groups (SSB) and within groups (SSW). Use these to find the F-statistic: \[ F = \frac{\text{MSB}}{\text{MSW}} \] where MSB is the mean square between groups and MSW is the mean square within groups.
04

Making a Decision

Find the critical value of F from the F-distribution table using a significance level of 5% (\(\alpha = 0.05\)) and degrees of freedom for the numerator and denominator (\(df_1 = k - 1\) and \(df_2 = N - k\), where \(k\) is the number of groups and \(N\) is the total number of observations). Compare the calculated F-statistic to this critical value. If \( F > F_{\text{critical}} \), reject the null hypothesis; otherwise, do not reject it.
05

Conclusion

Based on the comparison in Step 4, conclude whether to reject the null hypothesis or not. Rejecting the null hypothesis would suggest that there is a statistically significant difference in the mean annual profits among the four types of companies. Not rejecting it would suggest that there is no evidence of such a difference.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In statistical analysis, the null hypothesis serves as a default or initial assumption. When conducting an analysis of variance (ANOVA) test, you begin with the null hypothesis (\(H_0\)), which posits that there is no difference in the mean annual profits per employee across different groups. This means that the observed variations are merely due to random chance. In the context of the exercise, the null hypothesis is formulated as \(H_0: \mu_1 = \mu_2 = \mu_3 = \mu_4\), suggesting that the mean profits for computers, aerospace, heavy equipment, and broadcasting companies are the same.

It's important to remember that when testing this hypothesis, you are fundamentally questioning if the apparent differences in sample means are significant or if they could have occurred accidentally in random sampling. Your task is to determine, based on statistical evidence, whether this hypothesis holds or whether the gathered data suggests otherwise.

The null hypothesis is a cornerstone of hypothesis testing, allowing us to make informed decisions based on data rather than assumptions. It's not about proving the null hypothesis; instead, it's about having enough evidence to either reject or not reject it.
Alternative Hypothesis
The alternative hypothesis (\(H_a\)) acts as a counterpart to the null hypothesis and suggests that there is some underlying effect or difference. Specifically, in an ANOVA test, this hypothesis indicates that at least one group mean differs from the others. In other words, it claims that not all mean annual profits per employee are equal among the groups.

Formally, for the given exercise, the alternative hypothesis is: \(H_a: \text{not all } \mu_i \text{ are equal}\). This denotes that the data provides sufficient evidence to believe that one or more company types have different mean profits per employee.

While the null hypothesis focuses on equality and no effect, the alternative hypothesis opens the possibility of diversity among the groups' means. It's a critical component since it drives the direction of the hypothesis test. Rejection of the null hypothesis in favor of the alternative hypothesis implies a statistically significant difference in the groups being compared. This can inform decisions or future analyses, directing attention to specific groups or factors that explain the difference in means.
Mean Annual Profits
Mean annual profits per employee is central in assessing productivity within organizations. It represents the average profit generated per worker per year and becomes a useful metric when comparing different sectors or companies.

In the exercise, each industry (i.e., computers, aerospace, heavy equipment, broadcasting) provides data on annual profits per employee. By calculating the mean for each category, one can understand the typical productivity within that group. The mean is calculated by summing the profits and dividing by the number of data points. This offers a simplified measure of performance within each company type.
  • Computers: Profits range from $8.8K to $27.8K.
  • Aerospace: Profits vary between $6.6K to $19.3K.
  • Heavy Equipment: Lowest is $7.0K and highest is $22.3K.
  • Broadcasting: Spans from $9.0K to $17.1K.
Understanding these means gives insight into each industry's general economic standing and productivity level. When significant differences are present between these means, it suggests variations in profitability, efficiency, or business strategy.

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Most popular questions from this chapter

Rothamsted Experimental Station (England) has studied wheat production since \(1852 .\) Each year, many small plots of equal size but different soil/fertilizer conditions are planted with wheat. At the end of the growing season, the yield (in pounds) of the wheat on the plot is measured. The following data are based on information taken from an article by G. A. Wiebe in the Journal of Agricultural Research (Vol. 50, pp. \(331-357)\). For a random sample of years, one plot gave the following annual wheat production (in pounds): \(\begin{array}{llllllll}4.15 & 4.21 & 4.27 & 3.55 & 3.50 & 3.79 & 4.09 & 4.42 \\\ 389 & 3.87 & 4.12 & 3.09 & 4.86 & 2.90 & 5.01 & 3.39\end{array}\) Use a calculator to verify that, for this plot, the sample variance is \(s^{2}=0.332\). Another random sample of years for a second plot gave the following annual wheat production (in pounds): \(4.03\) \(3.59\) \(\begin{array}{llllllll}3 & 3.77 & 3.49 & 3.76 & 3.61 & 3.72 & 4.13 & 4.01 \\ 9 & 4.29 & 3.78 & 3.19 & 3.84 & 3.91 & 3.66 & 4.35\end{array}\) Use a calculator to verify that the sample variance for this plot is \(s^{2}-0.089 .\) Test the claim that the population variance of annual wheat production for the first plot is larger than that for the second plot. Use a \(1 \%\) level of significance.

A sociologist studying New York City ethnic groups wants to determine if there is a difference in income for immigrants from four different countries during their first year in the city. She obtained the data in the following table from a random sample of immigrants from these countries (incomes in thousands of dollars). Use a \(0.05\) level of significance to test the claim that there is no difference in the earnings of immigrants from the four different countries. \(\begin{array}{rrcr}\text { Country I } & \text { Country II } & \text { Country III } & \text { Country IV } \\ 12.7 & 8.3 & 20.3 & 17.2 \\\ 9.2 & 17.2 & 16.6 & 8.8 \\ 10.9 & 19.1 & 22.7 & 14.7 \\ 8.9 & 10.3 & 25.2 & 21.3 \\ 16.4 & & 19.9 & 19.8\end{array}\)

An economist wonders if corporate productivity in some countries is more volatile than in other countries. One measure of a company's productivity is annual percentage yield based on total company assets. Data for this problem are based on information taken from Forbes Top Companies, edited by J. T. Davis. A random sample of leading companies in France gave the following percentage yields based on assets: \(\begin{array}{llllllllllll}4.4 & 5.2 & 3.7 & 3.1 & 2.5 & 3.5 & 2.8 & 4.4 & 5.7 & 3.4 & 4.1\end{array}\) \(\begin{array}{llllllllll}6.8 & 2.9 & 3.2 & 7.2 & 6.5 & 5.0 & 3.3 & 2.8 & 2.5 & 4.5\end{array}\) Use a calculator to verify that \(s^{2}=2.044\) for this sample of French companies. Another random sample of leading companies in Germany gave the following percentage yields based on assets: \(\begin{array}{rrrrrrrrr}3.0 & 3.6 & 3.7 & 4.5 & 5.1 & 5.5 & 5.0 & 5.4 & 3.2\end{array}\) \(\begin{array}{llllllllll}3.5 & 3.7 & 2.6 & 2.8 & 3.0 & 3.0 & 2.2 & 4.7 & 3.2\end{array}\) Use a calculator to verify that \(s^{2} \approx 1.038\) for this sample of German companies. Test the claim that there is a difference (either way) in the population variance of percentage yields for leading companies in France and Germany. Use a \(5 \%\) level of significance. How could your test conclusion relate to the economist's question regarding volatility (data spread) of corporate productivity of large companies in France compared with companies in Germany?

For the study regarding mean cadence (see Problem 1), two-way ANOVA was used. Recall that the two factors were walking device (none, standard walker, rolling walker) and dual task (being required to respond vocally to a signal or no dual task required). Results of two-way ANOVA showed that there was no evidence of interaction between the factors. However, according to the article, "the ANOVA conducted on the cadence data reyealed a main effect of walking device." When the hypothesis regarding no difference in mean cadence according to which, if any, walking device was used, the sample \(F\) was \(30.94\), with d.f. \(\mathrm{N}=2\) and \(d . f \cdot \mathrm{D}=18\). Further, the \(P\) -value for the result was reported to be less than \(0.01\). From this information, what is the conclusion regarding any difference in mean cadence according to the factor "walking device used"?

For a chi-square goodness-of-fit test, how are the degrees of freedom computed?

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