/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 Explain why goodness-of-fit test... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Explain why goodness-of-fit tests are always right-tailed tests.

Short Answer

Expert verified
Goodness-of-fit tests are right-tailed because they identify large discrepancies between observed and expected frequencies, indicating a poor fit.

Step by step solution

01

Understanding the Goodness-of-Fit Test

The goodness-of-fit test is a type of statistical test used to determine if a sample data fits a distribution from a certain population. It's often used to see how well sample data matches a theoretical distribution, such as the normal, binomial, or Poisson distribution.
02

Formulating the Hypotheses

In a goodness-of-fit test, the null hypothesis ( H_0 ) states that there is no significant difference between the observed frequencies and the expected frequencies of a distribution. The alternative hypothesis ( H_a ) indicates there is a significant difference.
03

Chi-Square Statistic

The goodness-of-fit test often uses the chi-square statistic, calculated by \( \chi^2 = \sum \frac{(O_i - E_i)^2}{E_i} \), where O_i is the observed frequency and E_i is the expected frequency. This statistic measures the total discrepancy between observed and expected frequencies.
04

Interpreting the Test Statistic

The larger the chi-square statistic, the greater the discrepancy between the observed and expected frequencies. A small chi-square value indicates a good fit, while a large value suggests a poor fit to the expected distribution.
05

Right-Tail Test Explanation

The goodness-of-fit test is always right-tailed because we are interested in finding out if the chi-square statistic falls far to the right of the distribution, which indicates a poor fit and leads us to reject the null hypothesis. We never consider the left tail since it corresponds to smaller discrepancies, suggesting a good fit.
06

Decision Making Based on the Test

If the calculated chi-square statistic is greater than the critical value from the chi-square distribution table at a given significance level, we reject the null hypothesis. This decision is made based on the tail area of the chi-square distribution at the right end.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chi-Square Statistic
The chi-square statistic is a crucial concept in statistical tests, especially in the goodness-of-fit test. It provides a numerical measure of the discrepancy between observed and expected frequencies in a data set.
For example, suppose you have a set of observed data and a theoretical model predicting the outcome. The chi-square statistic helps you understand how much the observed data deviate from the model predictions.
Mathematically, it is calculated using the formula:
\[ \chi^2 = \sum \frac{(O_i - E_i)^2}{E_i} \]
Here, \(O_i\) represents the observed frequency, and \(E_i\) is the expected frequency based on the theoretical distribution.
This formula sums up the squared differences between observed and expected frequencies, adjusted by the expected frequencies, to give a single overall measure of discrepancy.
A small chi-square value indicates that the observed data closely fits the expected model, while a large chi-square value suggests significant deviation, necessitating further investigation or possible model adjustments.
Statistical Hypothesis Testing
Statistical hypothesis testing is a formal process used to make inferences or educated guesses about specific parameters in a population based on sample data.
This approach involves two main hypotheses:
  • Null hypothesis \((H_0)\): Suggests no significant effect or difference. It is the default or initial assumption.
  • Alternative hypothesis \((H_a)\): Indicates a significant effect or difference. It opposes the null hypothesis and represents what we seek evidence for.
The objective of hypothesis testing is to examine sample data and decide whether there is sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis.
In the context of a goodness-of-fit test, you're seeing if there is a good fit (null hypothesis) or a poor fit (alternative hypothesis) between your observed data and the expected distribution. The test calculates a test statistic (like the chi-square statistic) and compares it to a threshold to make this decision. The outcome helps in determining whether the observations differ significantly from the null hypothesis expectations.
Null Hypothesis
The null hypothesis \((H_0)\) essentially serves as a starting point in statistical hypothesis testing. It posits that there is no effect or difference, implying that any observed variation is by random chance.
For instance, in a goodness-of-fit test, the null hypothesis claims that the observed frequency matches the expected frequency from a theoretical distribution. This means you're assuming the data fits well with your chosen model or distribution unless proven otherwise.
The null hypothesis is designed to be challenged. In statistical tests, data is examined to determine whether the null hypothesis should be rejected in favor of the alternative hypothesis. A real-world analogy might be the presumption of innocence in a court case. The defendant is considered innocent \((H_0)\) until the prosecution provides enough evidence to prove guilt \((H_a)\).
The null hypothesis is central because it provides a baseline against which the observed data is tested. Decisions in the hypothesis testing process revolve around whether data provide compelling enough evidence to reject this initial assumption.
Right-Tailed Test
A right-tailed test in statistics deals with determining whether a test statistic falls in the extreme right end of a probability distribution.
In the case of a goodness-of-fit test, this is crucial because you're assessing whether the observed data significantly differ from the expected distribution.
The right-tailed aspect comes into play as follows: When you compute your chi-square statistic, large values that fall on the right side of the chi-square distribution indicate the observed frequencies deviate substantially from the expected frequencies. This large deviation suggests the possibility of rejecting the null hypothesis.
Why do we focus on the right tail? Because a large chi-square statistic corresponds to a more poor fit, driving the decision to reject the null hypothesis. The left tail, in contrast, would indicate minimal deviation, aligning with what the null hypothesis posits (that there is a good fit).
Thus, a right-tailed test helps identify when observed data significantly differ (in a negative way) from the theoretical expectations, guiding decisions around hypothesis rejection only on that side of the distribution.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A new thermostat has been engineered for the frozen food cases in large supermarkets. Both the old and new thermostats hold temperatures at an average of \(25^{\circ} \mathrm{F}\). However, it is hoped that the new thermostat might be more dependable in the sense that it will hold temperatures closer to \(25^{\circ} \mathrm{F}\). One frozen food case was equipped with the new thermostat, and a random sample of 21 temperature readings gave a sample variance of \(5.1 .\) Another similar frozen food case was equipped with the old thermostat, and a random sample of 16 temperature readings gave a sample variance of \(12.8 .\) Test the claim that the population variance of the old thermostat temperature readings is larger than that for the new thermostat. Use a \(5 \%\) level of significance. How could your test conclusion relate to the question regarding the dependability of the temperature readings?

Academe, Bulletin of the American Association of University Professors (Vol. 83, No. 2\()\) presents results of salary surveys (average salary) by rank of the faculty member (professor, associate, assistant, instructor) and by type of institution (public, private). List the factors and the number of levels of each factor. How many cells are there in the data table?

How productive are U.S. workers? One way to answer this question is to study annual profits per employee. A random sample of companies in computers (I), aerospace (II), heavy equipment (III), and broadcasting (IV) gave the following data regarding annual profits per employee (units in thousands of dollars). (Source: Forbes Top Companies, edited by J. T. Davis, John Wiley and Sons.) \(\begin{array}{rrrr}\text { I } & \text { II } & \text { III } & \text { IV } \\\ 27.8 & 13.3 & 22.3 & 17.1 \\ 23.8 & 9.9 & 20.9 & 16.9 \\ 14.1 & 11.7 & 7.2 & 14.3 \\ 8.8 & 8.6 & 12.8 & 15.2 \\ 11.9 & 6.6 & 7.0 & 10.1 \\ & 19.3 & & 9.0\end{array}\) Shall we reject or not reject the claim that there is no difference in population mean annual profits per employee in each of the four types of companies? Use a \(5 \%\) level of significance.

The quantity of dissolved oxygen is a measure of water pollution in lakes, rivers, and streams. Water samples were taken at four different locations in a river in an effort to determine if water pollution varied from location to location. Location I was 500 meters above an industrial plant water discharge point and near the shore. Location II was 200 meters above the discharge point and in midstream. Location III was 50 meters downstream from the discharge point and near the shore. Location IV was 200 meters downstream from the discharge point and in midstream. The following table shows the results. Lower dissolved oxygen readings mean more pollution. Because of the difficulty in getting midstream samples, ecology students collecting the data had fewer of these samples. Use an \(\alpha=0.05\) level of significance. Do we reject or not reject the claim that the quantity of dissolved oxygen does not vary from one location to another? \(\begin{array}{cccc}\text { Location I } & \text { Location II } & \text { Location III } & \text { Location IV } \\ 7.3 & 6.6 & 4.2 & 4.4 \\ 6.9 & 7.1 & 5.9 & 5.1 \\ 7.5 & 7.7 & 4.9 & 6.2 \\ 6.8 & 8.0 & 5.1 & \\ 6.2 & & 4.5 & \end{array}\)

A sociologist studying New York City ethnic groups wants to determine if there is a difference in income for immigrants from four different countries during their first year in the city. She obtained the data in the following table from a random sample of immigrants from these countries (incomes in thousands of dollars). Use a \(0.05\) level of significance to test the claim that there is no difference in the earnings of immigrants from the four different countries. \(\begin{array}{rrcr}\text { Country I } & \text { Country II } & \text { Country III } & \text { Country IV } \\ 12.7 & 8.3 & 20.3 & 17.2 \\\ 9.2 & 17.2 & 16.6 & 8.8 \\ 10.9 & 19.1 & 22.7 & 14.7 \\ 8.9 & 10.3 & 25.2 & 21.3 \\ 16.4 & & 19.9 & 19.8\end{array}\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.