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91Ó°ÊÓ

If two variables have a negative linear correlation, is the slope of the least-squares line positive or negative?

Short Answer

Expert verified
The slope of the least-squares line is negative.

Step by step solution

01

Understanding Linear Correlation

Linear correlation between two variables indicates how one variable changes in response to changes in the other. A negative linear correlation means that as one variable increases, the other variable decreases. This inverse relationship will affect the slope of the line.
02

Slope of a Line

The slope of a line measures its steepness and direction. For a linear equation in the form of \( y = mx + b \), \( m \) represents the slope. A positive slope means the line rises as it goes from left to right, while a negative slope means it falls.
03

Analyzing the Impact of Negative Correlation

In negative linear correlation, as one variable, say \( x \), increases, the other variable, \( y \), decreases. This results in a downward slope from left to right, which implies that the slope of the line that represents the least-squares fit will be negative.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Least-Squares Line
The least-squares line is a key concept in statistics used for predicting or understanding relationships between two variables. It's the straight line that best fits the data points on a scatter plot, minimizing the distances of the points from the line itself.
This method is especially powerful because it helps us to visualize the trend across data points in a straightforward manner. By drawing this line, we can observe an overall pattern in how one variable affects another. To find this line, we use mathematical techniques to minimize the sum of the squared differences between the observed values and the values predicted by the line.
Here are some important characteristics of the least-squares line:
  • It serves to provide the best linear approximation to the data.
  • It balances out the difference between actual data points and the line, creating the smallest possible cumulative gap.
  • A perfect match between the line and the data points would mean all points lie directly on the line, which is rare in real-world data.
Understanding how to interpret and draw this line is crucial for analyzing relationships in data sets, especially with variables showing correlation, such as negative linear correlation.
Slope of a Line
The slope of a line is a fundamental concept in understanding linear relationships. It indicates how steep a line is and in what direction it runs across a graph. In the linear equation format, such as \( y = mx + b \), the slope \( m \) tells us whether the line is rising or falling as it moves from left to right.
The slope explains:
  • Direction: Positive slopes rise, indicating that as one variable increases, so does the other.
  • Direction: Negative slopes fall, indicating that as one variable increases, the other decreases. This is typical for negative linear correlations.
  • Steepness: Substantial changes in \( y \) relative to changes in \( x \) mean a steep slope. Conversely, small changes produce a gentle slope.
By calculating and assessing the slope, we can obtain valuable insights into the nature of the relationship between two variables. Specifically, if we know the correlation is negative, we expect a negative slope, reflecting how they move in opposite directions.
Inverse Relationship
An inverse relationship occurs when one variable increases while the other decreases. This concept is essential in understanding many real-world situations where variables do not move in tandem but rather in opposite directions, creating a negative slope.
In the context of linear correlation:
  • Whenever you notice a negative linear correlation, you're observing an inverse relationship.
  • This relationship is visualized in graphs where the line slopes downwards from left to right, clearly showing how an increase in one variable leads to a decrease in another.
Understanding inverse relationships is vital since it helps predict how a change in one variable can affect another. Recognizing these relationships allows for better forecasting and decision-making across various fields, such as economics, science, and engineering.
These concepts are interconnected, and understanding them in tandem helps provide clear insights into the behavior of data and the mathematical relationships underlying them.

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Most popular questions from this chapter

Describe the relationship between two variables when the correlation coefficient \(r\) is (a) near \(-1\) (b) near 0 (c) near 1

What is the symbol used for the population correlation coefficient?

In Section \(5.1\), we studied linear combinations of independent random variables. What happens if the variables are not independent? A lot of mathematics can be used to prove the following: Let \(x\) and \(y\) be random variables with means \(\mu_{x}\) and \(\mu_{y}\), variances \(\sigma_{x}^{2}\) and \(\sigma_{y}^{2}\) and population correlation coefficient \(\rho\) (the Greek letter rho). Let \(a\) and \(b\) be any constants and let \(w=a x+b y .\) Then $$ \begin{aligned} &\mu_{w}=a \mu_{x}+b \mu_{y} \\ &\sigma_{w}^{2}=a^{2} \sigma_{x}^{2}+b^{2} \sigma_{y}^{2}+2 a b \sigma_{x} \sigma_{y} \rho \end{aligned} $$ In this formula, \(\rho\) is the population correlation coefficient, theoretically computed using the population of all \((x, y)\) data pairs. The expression \(\sigma_{x} \sigma_{y} \rho\) is called the covariance of \(x\) and \(y\). If \(x\) and \(y\) are independent, then \(\rho=0\) and the formula for \(\sigma_{w}^{2}\) reduces to the appropriate formula for independent variables (see Section 5.1). In most real-world applications the population parameters are not known, so we use sample estimates with the understanding that our conclusions are also estimates. Do you have to be rich to invest in bonds and real estate? No, mutual fund shares are available to you even if you aren't rich. Let \(x\) represent annual percentage return (after expenses) on the Vanguard Total Bond Index Fund, and let \(y\) represent annual percentage return on the Fidelity Real Estate Investment Fund. Over a long period of time, we have the following population estimates (based on Morningstar Mutual Fund Report). $$ \mu_{x} \approx 7.32 \quad \sigma_{x} \approx 6.59 \quad \mu_{y} \approx 13.19 \quad \sigma_{y} \approx 18.56 \quad \rho \approx 0.424 $$ (a) Do you think the variables \(x\) and \(y\) are independent? Explain. (b) Suppose you decide to put \(60 \%\) of your investment in bonds and \(40 \%\) in real estate. This means you will use a weighted average \(w=0.6 x+0.4 y\). Estimate your expected percentage return \(\mu_{w}\) and risk \(\sigma_{w}\). (c) Repeat part (b) if \(w=0.4 x+0.6 y\). (d) Compare your results in parts (b) and (c). Which investment has the higher expected return? Which has the greater risk as measured by \(\sigma_{w} ?\)

The following data are based on information from the book Life in America's Small Cities (by G. S. Thomas, Prometheus Books). Let \(x\) be the percentage of 16 - to 19 -year-olds not in school and not high school graduates. Let \(y\) be the reported violent crimes per 1000 residents. Six small cities in Arkansas (Blytheville, El Dorado, Hot Springs, Jonesboro, Rogers, and Russellville) reported the following information about \(x\) and \(y\) : $$ \begin{array}{r|rrrrrr} \hline x & 24.2 & 19.0 & 18.2 & 14.9 & 19.0 & 17.5 \\ \hline y & 13.0 & 4.4 & 9.3 & 1.3 & 0.8 & 3.6 \\ \hline \end{array} $$ Complete parts (a) through (e), given \(\Sigma x=112.8, \Sigma y=32.4, \Sigma x^{2}=2167.14\), \(\Sigma y^{2}=290.14, \Sigma x y=665.03\), and \(r \approx 0.764\). (f) If the percentage of 16 - to 19 -year-olds not in school and not graduates reaches \(24 \%\) in a similar city, what is the predicted rate of violent crimes per 1000 residents?

Aviation and high-altitude physiology is a specialty in the study of medicine. Let \(x=\) partial pressure of oxygen in the alveoli (air cells in the lungs) when breathing naturally available air. Let \(y=\) partial pressure when breathing pure oxygen. The \((x, y)\) data pairs correspond to elevations from 10,000 feet to 30,000 feet in 5000 -foot intervals for a random sample of volunteers. Although the medical data were collected using airplanes, they apply equally well to Mt. Everest climbers (summit 29,028 feet). $$ \begin{array}{l|rrrrr} \hline x & 6.7 & 5.1 & 4.2 & 3.3 & 2.1(\text { units: } \mathrm{mm} \mathrm{Hg} / 10) \\ \hline y & 43.6 & 32.9 & 26.2 & 6.2 & 13.9(\text { units: } \mathrm{mm} \mathrm{Hg} / 10) \\ \hline \end{array} $$ (Based on information taken from Medical Physiology by A. C. Guyton, M.D.) (a) Verify that \(\Sigma x=21.4, \Sigma y=132.8, \Sigma x^{2}=103.84, \Sigma y^{2}=4125.46, \Sigma x y=\) 652\. 6 , and \(r \approx 0.984\). (b) Use a \(1 \%\) level of significance to test the claim that \(\rho>0\). (c) Verify that \(S_{e} \approx 2.5319, a \approx-2.869\), and \(b \approx 6.876\). (d) Find the predicted pressure when breathing pure oxygen if the pressure from breathing available air is \(x=4.0\). (e) Find a \(90 \%\) confidence interval for \(y\) when \(x=4.0\). (f) Use a \(1 \%\) level of significance to test the claim that \(\beta>0\). (g) Find a \(95 \%\) confidence interval for \(\beta\) and interpret its meaning.

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