/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 The following data are based on ... [FREE SOLUTION] | 91Ó°ÊÓ

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The following data are based on information from the book Life in America's Small Cities (by G. S. Thomas, Prometheus Books). Let \(x\) be the percentage of 16 - to 19 -year-olds not in school and not high school graduates. Let \(y\) be the reported violent crimes per 1000 residents. Six small cities in Arkansas (Blytheville, El Dorado, Hot Springs, Jonesboro, Rogers, and Russellville) reported the following information about \(x\) and \(y\) : $$ \begin{array}{r|rrrrrr} \hline x & 24.2 & 19.0 & 18.2 & 14.9 & 19.0 & 17.5 \\ \hline y & 13.0 & 4.4 & 9.3 & 1.3 & 0.8 & 3.6 \\ \hline \end{array} $$ Complete parts (a) through (e), given \(\Sigma x=112.8, \Sigma y=32.4, \Sigma x^{2}=2167.14\), \(\Sigma y^{2}=290.14, \Sigma x y=665.03\), and \(r \approx 0.764\). (f) If the percentage of 16 - to 19 -year-olds not in school and not graduates reaches \(24 \%\) in a similar city, what is the predicted rate of violent crimes per 1000 residents?

Short Answer

Expert verified
Predicted rate is approximately 11.69 violent crimes per 1000 residents.

Step by step solution

01

Understand the Linear Regression Formula

To find the predicted rate of violent crimes when the percentage of 16- to 19-year-olds not in school and not graduates is 24%, we use the linear regression equation: \[ y = mx + b \] where \( m \) is the slope and \( b \) is the y-intercept.
02

Calculate the Slope (m)

The slope \( m \) is given by the formula:\[ m = \frac{n \Sigma xy - \Sigma x \Sigma y}{n \Sigma x^2 - (\Sigma x)^2} \]Plugging in the values for \( n = 6 \), \( \Sigma xy = 665.03 \), \( \Sigma x = 112.8 \), \( \Sigma y = 32.4 \), and \( \Sigma x^2 = 2167.14 \), we calculate:\[ m = \frac{6 \times 665.03 - 112.8 \times 32.4}{6 \times 2167.14 - (112.8)^2} \]\[ m = \frac{3990.18 - 3650.72}{13002.84 - 12722.24} \] \[ m = \frac{339.46}{280.6} \approx 1.21 \]
03

Calculate the Y-Intercept (b)

The y-intercept \( b \) is given by the formula:\[ b = \frac{\Sigma y - m \Sigma x}{n} \]Substitute the calculated \( m \) and other given values:\[ b = \frac{32.4 - 1.21 \times 112.8}{6} \]\[ b = \frac{32.4 - 136.488}{6} \]\[ b = \frac{-104.088}{6} \approx -17.35 \]
04

Predict the Violent Crime Rate for 24%

Now that we have \( m \) and \( b \), use the linear regression equation to predict \( y \) when \( x = 24 \):\[ y = 1.21 \times 24 - 17.35 \]\[ y = 29.04 - 17.35 \]\[ y = 11.69 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistics Education
Understanding statistics is essential for analyzing and interpreting the world around us. One vital application of statistics is linear regression, a powerful method to establish a relationship between two variables.
In this exercise, we see a practical example of linear regression used to study the impact of education on crime rates in small cities within Arkansas. Different variables are represented in statistics: here, \(x\) denotes the percentage of young individuals not in school, and \(y\), the rate of violent crimes. These examples exemplify the importance of statistics education in solving real-world problems.
Grasping these statistical concepts allows students to comprehend how data can predict societal trends and behaviors. By understanding the relationships between different sets of data, students not only excel academically but are also better equipped to make informed decisions in their personal and professional lives.
Predictive Modeling
Predictive modeling is a statistical technique involving the use of mathematical formulas to predict future outcomes based on historical data.
A common form of predictive modeling is linear regression, as used in this exercise to forecast crime rates. Here, linear regression models the prediction that a city with 24% of teenagers not in school or not high school graduates will have a predicted crime rate of 11.69 per 1000 residents.
Predictive modeling requires selecting and interpreting variables correctly, ensuring the model is both reliable and valid. This involves calculating the model's slope and y-intercept, which tells us how much change in the independent variable \(x\) affects the dependent variable \(y\).
Through these methods, predictive modeling greatly aids in decision-making processes across multiple fields such as economics, engineering, and public policy.
Statistical Analysis
Statistical analysis is the process of collecting, reviewing, and interpreting data to uncover patterns and trends.
This exercise integrated comprehensive statistical analysis by calculating several key metrics, including sums of squares and products \(\Sigma x\), \(\Sigma y\), and \(\Sigma xy\), to determine the slope \(m\) and y-intercept \(b\) of the linear equation.
By examining these statistics, we gain insights into the direct relationship between education and crime rates. The analysis shows us the strength and direction of this relationship. Statistical analysis empowers learners to derive conclusions from supplied data.
With proper analysis, data reveals not just past records, but also enables accurate predictions and strategic planning.
Correlation Coefficient
The correlation coefficient \(r\) is a statistical measure that expresses the extent to which two variables are linearly related; it shows the strength and direction of this relationship.
In this exercise, the calculated correlation coefficient is approximately 0.764, signifying a strong positive relationship between the percentage of teenagers not in school and crime rates.
Values of \(r\) range from -1 to 1. An \(r\) close to 1 implies a strong positive correlation; conversely, an \(r\) near -1 suggests a strong negative correlation. An \(r\) around 0 indicates no correlation.
Understanding the correlation coefficient helps students grasp how much one variable is likely to affect another. It explains why certain variables in a linear regression model, like education and crime in this example, can be reliable for predictive modeling and strategic decision-making.

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Most popular questions from this chapter

How does the \(t\) -value for the sample correlation coefficient \(r\) compare to the \(t\) -value for the corresponding slope \(b\) of the sample least-squares line?

Suppose two variables are negatively correlated. Does the response variable increase or decrease as the explanatory variable increases?

Given the linear regression equation \(x_{3}=-16.5+4.0 x_{1}+9.2 x_{4}-1.1 x_{7}\) (a) Which variable is the response variable? Which variables are the explanatory variables? (b) Which number is the constant term? List the coefficients with their corresponding explanatory variables. (c) If \(x_{1}=10, x_{4}=-1\), and \(x_{7}=2\), what is the predicted value for \(x_{3}\) ? (d) Explain how each coefficient can be thought of as a "slope." Suppose \(x_{1}\) and \(x_{7}\) were held as fixed but arbitrary values. If \(x_{4}\) increased by 1 unit, what would we expect the corresponding change in \(x_{3}\) to be? If \(x_{4}\) increased by 3 units, what would be the corresponding expected change in \(x_{3} ?\) If \(x_{4}\) decreased by 2 units, what would we expect for the corresponding change in \(x_{3}\) ? (e) Suppose that \(n=15\) data points were used to construct the given regression equation and that the standard error for the coefficient of \(x_{4}\) is \(0.921\). Construct a \(90 \%\) confidence interval for the coefficient of \(x_{4}\). (f) Using the information of part (e) and level of significance \(1 \%\), test the claim that the coefficient of \(x_{4}\) is different from zero. Explain how the conclusion has a bearing on the regression equation.

Can a low barometer reading be used to predict maximum wind speed of an approaching tropical cyclone? Data for this problem are based on information taken from Weatherwise \((\) Vol. 46, No. 1\()\), a publication of the American Meteorological Society. For a random sample of tropical cyclones, let \(x\) be the lowest pressure (in millibars) as a cyclone approaches, and let \(y\) be the maximum wind speed (in miles per hour) of the cyclone. $$ \begin{array}{l|rrrrrr} \hline x & 1004 & 975 & 992 & 935 & 985 & 932 \\ \hline y & 40 & 100 & 65 & 145 & 80 & 150 \\ \hline \end{array} $$ (a) Make a scatter diagram and draw the line you think best fits the data. (b) Would you say the correlation is low, moderate, or strong? positive or negative? (c) Use a calculator to verify that \(\Sigma x=5823, \Sigma x^{2}=5,655,779, \Sigma y=580\), \(\Sigma y^{2}=65,750\), and \(\Sigma x y=556,315 .\) Compute \(r .\) As \(x\) increases, does the value of \(r\) imply that \(y\) should tend to increase or decrease? Explain.

Let \(x=\) day of observation and \(y=\) number of locusts per square meter during a locust infestation in a region of North Africa. $$ \begin{array}{r|rrrrr} \hline x & 2 & 3 & 5 & 8 & 10 \\ \hline y & 2 & 3 & 12 & 125 & 630 \\ \hline \end{array} $$ (a) Draw a scatter diagram of the \((x, y)\) data pairs. Do you think a straight line will be a good fit to these data? Do the \(y\) values almost seem to explode as time goes on? (b) Now consider a transformation \(y^{\prime}=\log y .\) We are using common logarithms of base \(10 .\) Draw a scatter diagram of the \(\left(x, y^{\prime}\right)\) data pairs and compare this diagram with the diagram of part (a). Which graph appears to better fit a straight line? (c) Use a calculator with regression keys to find the linear regression equation for the data pairs \(\left(x, y^{\prime}\right) .\) What is the correlation coefficient? (d) The exponential growth model is \(y=\alpha \beta^{x}\). Estimate \(\alpha\) and \(\beta\) and write the exponential growth equation. Hint: See Problem 22 .

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