/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 94 In Exercises 91 and 92, express ... [FREE SOLUTION] | 91Ó°ÊÓ

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In Exercises 91 and 92, express the complex number in polar form. Use identities to express the complex number \(4\left[\cos \left(\frac{5 \pi}{8}\right)+i \sin \left(\frac{5 \pi}{8}\right)\right]\) exactly in rectangular form.

Short Answer

Expert verified
The complex number in rectangular form is \( 2\sqrt{2 - \sqrt{2}} + i 2\sqrt{2 + \sqrt{2}} \).

Step by step solution

01

Identify the components of the complex number

The given complex number is expressed in polar form as \( 4\left[\cos \left(\frac{5\pi}{8}\right) + i \sin \left(\frac{5\pi}{8}\right)\right] \). First, we need to identify the magnitude \( r = 4 \) and the angle \( \theta = \frac{5\pi}{8} \).
02

Apply Euler's formula

In polar form, a complex number \( z = r (\cos\theta + i \sin\theta) \) can be expressed using Euler's formula as \( z = re^{i\theta} \). Here, \( z = 4e^{i\frac{5\pi}{8}} \).
03

Convert to rectangular form

Convert the polar expression into rectangular form using the identities for cosine and sine. We have \( 4 \cos \left(\frac{5\pi}{8}\right) \) for the real part and \( 4 \sin \left(\frac{5\pi}{8}\right) \) for the imaginary part.
04

Calculating \( \cos\left(\frac{5\pi}{8}\right) \text{ and } \sin\left(\frac{5\pi}{8}\right)\)

Use the cofunction identities: \( \cos\left(\frac{5\pi}{8}\right) = \sin\left(\frac{3\pi}{8}\right)\) and \( \sin\left(\frac{5\pi}{8}\right) = \cos\left(\frac{3\pi}{8}\right)\). These specific angles can be expressed as \( \sin\left(\frac{3\pi}{8}\right) = \frac{\sqrt{2 - \sqrt{2}}}{2} \) and \( \cos\left(\frac{3\pi}{8}\right) = \frac{\sqrt{2 + \sqrt{2}}}{2} \).
05

Calculate rectangular components

The real component is \( 4 \times \frac{\sqrt{2 - \sqrt{2}}}{2} = 2\sqrt{2 - \sqrt{2}} \). The imaginary component is \( 4 \times \frac{\sqrt{2 + \sqrt{2}}}{2} = 2\sqrt{2 + \sqrt{2}} \).
06

Formulate the rectangular form

Combine the calculated real and imaginary components into a single expression. The rectangular form of the complex number is \( 2\sqrt{2 - \sqrt{2}} + i 2\sqrt{2 + \sqrt{2}} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polar Form
The polar form of a complex number is a way of expressing it using a magnitude and an angle. Imagine a point on a 2D plane as a vector extending from the origin. The polar form uses the length of this vector, called the magnitude ( ), and the angle ( heta) it forms with the positive x-axis, measured counterclockwise. This method can simplify multiplication and division of complex numbers. The polar form is usually written as \( r(\cos\theta + i \sin\theta) \).

For example, the complex number given in the exercise is in polar form, with a magnitude \( r = 4 \) and angle \( \theta = \frac{5\pi}{8} \). In this situation, you don't directly see the real and imaginary components but rather their trigonometric representation.
Rectangular Form
The rectangular form of a complex number is a more direct expression using its real and imaginary components. Any complex number can be written as \( a + bi \), where \( a \) is the real part and \( b \) is the imaginary part. This form aligns with Cartesian coordinates on the complex plane, where the x-axis represents the real part and the y-axis represents the imaginary part.

To convert from polar to rectangular form, use the equations \( a = r \cos \theta \) and \( b = r \sin \theta \). In our exercise, the calculation of \( \cos\left(\frac{5\pi}{8}\right) \) and \( \sin\left(\frac{5\pi}{8}\right) \) gives us the real and imaginary components, leading to the rectangular form \( 2\sqrt{2 - \sqrt{2}} + i 2\sqrt{2 + \sqrt{2}} \).
Euler's Formula
Euler's Formula provides a link between exponential functions and trigonometric functions. It states that \( e^{i\theta} = \cos\theta + i \sin\theta \). This is extremely useful in converting polar form into exponential form.

In our exercise, the given complex number \( 4(\cos(\frac{5\pi}{8}) + i \sin(\frac{5\pi}{8})) \) can be represented as \( 4e^{i\frac{5\pi}{8}} \) using Euler's Formula. This simplifies operations like multiplication and division by translating it into exponential terms, where you multiply magnitudes and add angles.
Cofunction Identities
Cofunction identities help relate sine and cosine values of complementary angles. The basic idea is that \( \cos(\theta) = \sin(\frac{\pi}{2} - \theta) \) and \( \sin(\theta) = \cos(\frac{\pi}{2} - \theta) \). These identities are useful when exact values of trigonometric functions are needed.

In the exercise, we converted \( \cos\left(\frac{5\pi}{8}\right) \) to \( \sin\left(\frac{3\pi}{8}\right) \) and \( \sin\left(\frac{5\pi}{8}\right) \) to \( \cos\left(\frac{3\pi}{8}\right) \) using cofunction identities. This transformation was key to identifying the components necessary for constructing the rectangular form of the complex number.

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Most popular questions from this chapter

For Exercises 37-46, recall that the flight of a projectile can be modeled with the parametric equations $$ x=\left(v_{0} \cos \theta\right) t \quad y=-16 t^{2}+\left(v_{0} \sin \theta\right) t+h $$ where \(t\) is in seconds, \(v_{0}\) is the initial velocity in feet per second, \(\theta\) is the initial angle with the horizontal, and \(h\) is the initial height above ground, where \(x\) and \(y\) are in feet. Flight of a Baseball. A baseball is hit at an initial speed of \(105 \mathrm{mph}\) and an angle of \(20^{\circ}\) at a height of 3 feet above the ground. If there is no back fence or other obstruction, how far does the baseball travel (horizontal distance), and what is its maximum height? (Note the symmetry of the projectile path.)

In Exercises 21-36, each set of parametric equations defines a plane curve. Find an equation in rectangular form that also corresponds to the plane curve. $$ x=t^{2}-1, y=t^{2}+1 $$

Given \(r=2 \cos \left(\frac{3 \theta}{2}\right)\), find the \(\theta\)-intervals for the petal in the first quadrant.

Bicycle Racing. A boy on a bicycle racing around an oval track has a position given by the equations \(x=-100 \sin \left(\frac{t}{4}\right)\) and \(y=75 \cos \left(\frac{t}{4}\right)\), where \(x\) and \(y\) are the horizontal and vertical positions in feet relative to the center of the track \(t\) seconds after the start of the race. Find the boy's position at \(t=10,20\), and 30 .

In Exercises 45-68, graph each equation. In Exercises 63-68, convert the equation from polar to rectangular form first and identify the resulting equation as a line, parabola, or circle. $$ r^{2}=9 \cos (2 \theta) $$

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