/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 94 Given \(r=1+\sin (2 \theta)\) an... [FREE SOLUTION] | 91Ó°ÊÓ

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Given \(r=1+\sin (2 \theta)\) and \(r=1-\cos (2 \theta)\), find all points of intersection.

Short Answer

Expert verified
The points of intersection are repeated periodically due to the function symmetry, with sample point: \((r = 1 + \frac{\sqrt{2}}{2}, \theta = \frac{\pi}{8})\).

Step by step solution

01

Set the Equations Equal to Each Other

To find the points of intersection, equate the two given polar equations: \[ 1 + \sin(2\theta) = 1 - \cos(2\theta) \] Simplifying this, we remove the 1 from both sides which gives: \[ \sin(2\theta) = -\cos(2\theta) \]
02

Use a Trigonometric Identity

Recognize that we can use a trigonometric identity to solve the equation: \[ \sin(2\theta) + \cos(2\theta) = 0 \] Divide both sides by \( \cos(2\theta) \) (assuming \( \cos(2\theta) eq 0 \)): \[ \tan(2\theta) = -1 \] This implies that the angle \( 2\theta \) is an odd multiple of \( 135^\circ \) or \( \frac{3\pi}{4} \) radians.
03

Solve for \( \theta \)

We know that \( 2\theta = \frac{\pi}{4} + k\pi \) for integer values of \( k \). Solve for \( \theta \): \[ \theta = \frac{\pi}{8} + \frac{k\pi}{2} \] This gives us all possible \( \theta \) values where the curves intersect based on the periodic property of the tangent function.
04

Substitute Back to Find Intersection Points

Now, plug these \( \theta \) values back into either original equation to get \( r \). For simplicity, substitute into \( r = 1 + \sin(2\theta) \). Let \( \theta = \frac{\pi}{8} \): \[ r = 1 + \sin\left( \frac{\pi}{4} \right) = 1 + \frac{\sqrt{2}}{2} \]Repeat this process for a few values of \( k \) to verify periodic points repeating.
05

Express the Intersection Points in Polar Coordinates

Thus the intersection points when \( k = 0 \) are: \( (1 + \frac{\sqrt{2}}{2}, \frac{\pi}{8}) \). For different values of \( k \) like 1 and 2, you will find points repeating due to periodic properties, representing the same physical points upon rotating full circle in radians.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Points of Intersection
When dealing with curves in polar coordinates, the **points of intersection** are where two curves overlap or cross each other. Finding these points usually involves setting the equations of the curves equal and solving for the angle \( \theta \).
This aligns with the core idea of the polar coordinate system, where each point is represented as \((r, \theta)\), with \(r\) being the radius from the origin and \(\theta\) the angle from a reference direction.
Here, given the equations \(r=1+\sin (2 \theta)\) and \(r=1-\cos (2 \theta)\), the finding intersection step starts with equating these expressions.
Equating them allows us to solve for \(\theta\), identifying the specific angles where the curves intersect.
  • Equate the polar equations to get \( \sin(2\theta) = -\cos(2\theta) \).
  • Solve the simplified equation for specific \( \theta \) values.
  • Substitute \( \theta \) back to get the coordinates \((r, \theta)\).
This approach uncovers all potential intersection points of the curves in the polar system.
Trigonometric Identity
**Trigonometric identities** are fundamental tools in simplifying and solving equations involving trigonometric functions. In this context, the identity used is crucial to solve \( \sin(2\theta) = -\cos(2\theta) \).
By leveraging the relationship between sine and cosine, we can find an alternative form for this equation.
Here, we can manipulate the given equation as follows: Add \( \cos(2\theta) \) to both sides resulting in \( \sin(2\theta) + \cos(2\theta) = 0 \).
Utilizing the form \( \sin(A) + \cos(A) = \sqrt{2} \sin(A + \frac{\pi}{4}) \) (a derived identity), or simply rearranging, leads directly into using the tangent function.
  • Convert the equation to a form involving one function.
  • Recognize applicable identities, like angle addition or subtraction, can be key.
  • Apply identities to reduce complexity and solve for \(\theta\).
Tangent Function
The **tangent function** is a pivotal concept when solving equations derived from polar curves. Once the polar equation equation \( \sin(2\theta) = -\cos(2\theta) \) was simplified into \( \tan(2\theta) = -1 \), we tap into the properties of the tangent function.
The solution to the equation reflects the periodicity and special angles of the tangent function.
When \( \tan = -1 \), the typical solutions involve an odd multiple of \(135^\circ\) or \(\frac{3\pi}{4}\) radians.
This is due to the fact that tangent has a period of \(\pi\), so the solutions are spaced by this interval.
  • Recognize when the tangent function provides solutions based on its periodicity: \( \tan(2\theta) = -1 \)
  • Find general angles where tangent is \(-1\), typically at odd multiples of \(135^\circ\).
  • Use the general solution form \( 2\theta = \frac{3\pi}{4} + k\pi \) to find \(\theta\) values.
Polar Equations
**Polar equations** represent mathematical expressions of curves through polar coordinates \((r, \theta)\).
The equations \(r=1+\sin (2 \theta)\) and \(r=1-\cos (2 \theta)\) describe two different curves in the polar plane.
To analyze intersections or any other properties, understanding these equations is critical.
Polar equations can differ greatly from their Cartesian counterparts, but similarly, they describe relationships between angles and radial distance.
By solving such equations together, we discover intersections points, reflective of true geometrical relationships between the radial paths described.
  • Comprehend the mathematical relationship given by the polar equations.
  • Explore and interpret intersections geometrically within the radial-angled framework.
  • Use substitutions and algebraic techniques to uncover solution points in \((r, \theta)\) form.
Understanding how to manipulate these equations will enable better comprehension of geometrical structures and interactions in polar systems.

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