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Chapter 9: Problem 11

Use dimensional analysis to convert the quantity to the indicated unit. If necessary, round the answer to two decimal places. \(6 \mathrm{ft}\) to \(\mathrm{yd}\)

Short Answer

Expert verified
6 feet is equivalent to 2 yards.

Step by step solution

01

Identify Conversion Factor

Identify the conversion factor between the given units. The conversion factor between feet to yards is that 1 yard equals 3 feet.
02

Set Up Conversion Equation

Write a conversion equation, putting the value to be converted (6 feet) times the conversion factor which is fraction. Since we are converting from feet to yards, the conversion factor should be set so that the unit 'feet' cancels out and 'yard' remains: \(6 \, \mathrm{ft}\) \(\times\) \( \frac{1 \, \mathrm{yd}}{3 \, \mathrm{ft}} \)
03

Perform Calculation

Perform the multiplication operation. The 'feet' unit in the numerator and denominator will cancel out each other and you will be left with the distance in yards: \(6 \, \mathrm{ft} \) \(\times \) \(\frac{1 \, \mathrm{yd}}{3 \, \mathrm{ft}} = 2 \, \mathrm{yd} \)

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Most popular questions from this chapter

The distance from the Earth to the sun is about 93 million miles. What is this distance in kilometers?

Use the following English and metric equivalents, along with dimensional analysis, to convert the given measurement to the unit indicated.English and Metric Equivalents$$\begin{aligned}&1 \text { in. }=2.54 \mathrm{~cm} \\\&1 \mathrm{ft}=30.48 \mathrm{~cm} \\\&1 \mathrm{yd} \approx 0.9 \mathrm{~m} \\\&1 \mathrm{mi} \approx 1.6 \mathrm{~km}\end{aligned}$$ \(12 \mathrm{~m}\) to \(\mathrm{yd}\)

Select the best estimate for the measure of the given item. The height of a skyscraper a. \(325 \mathrm{~m}\) b. \(32.5 \mathrm{~km}\) c. \(325 \mathrm{~km}\) d. \(3250 \mathrm{~km}\)

Use the following English and metric equivalents, along with dimensional analysis, to convert the given measurement to the unit indicated.English and Metric Equivalents$$\begin{aligned}&1 \text { in. }=2.54 \mathrm{~cm} \\\&1 \mathrm{ft}=30.48 \mathrm{~cm} \\\&1 \mathrm{yd} \approx 0.9 \mathrm{~m} \\\&1 \mathrm{mi} \approx 1.6 \mathrm{~km}\end{aligned}$$ \(20 \mathrm{~m}\) to \(\mathrm{yd}\)

Find the population density, to the nearest tenth, for each state. Which state has the greater population density? How many more people per square mile inhabit the state with the greater density than inhabit the state with the lesser density? New York population: \(19,465,197\) area: \(54,555 \mathrm{mi}^{2}\) Rhode Island population: \(1,051,302\) area: \(1545 \mathrm{mi}^{2}\)
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