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A bank offers a money market account paying \(4.9 \%\) interest compounded semiannually. A competing bank offers a money market account paying \(4.8 \%\) interest compounded daily. Which account is the better investment?

Short Answer

Expert verified
The bank account with an interest rate of 4.9% compounded semiannually is a better investment.

Step by step solution

01

Analyze the first account

The first account offers a 4.9% interest rate compounded semiannually. This means n=2 (since semiannually means twice a year). Let's assume P be 1 for simplicity and t can be any number of years. So the formula becomes: \(A =1(1 + 0.049/2)^(2t)\) = \(1(1 + 0.0245)^(2t)\) = \(1(1.0245)^(2t)\)
02

Analyze the second account

The second account offers a 4.8% interest rate compounded daily. This means n = 365 (since daily means every day of the year). Again, let's assume P be 1 for simplicity and t can be any number of years. So the formula becomes: \( A = 1(1 + 0.048/365)^(365t) \) = \( 1(1 + 0.00013150)^(365t) \) = \(1(1.00013150)^(365t)\)
03

Comparing the accounts

Now compare the expressions from Step 1 and Step 2 for any time t to check which value is greater. Since \(1.0245^{2t}\) > \(1.00013150^{365t}\) for any positive t, the first account with a 4.9% interest rate compounded semiannually yields more interest than the second account with a 4.8% interest rate compounded daily for any time period.

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