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\(P=\$ 5000, r=8.5 \%, t=9\) months

Short Answer

Expert verified
The result of the calculation from Step 3 will be the simple interest earned on the principal amount.

Step by step solution

01

Conversion of months into years

The time period is given in months. Since the interest rate is per annum, the time should also be in years. Therefore, convert 9 Months into years by dividing by 12. Which gives, \(t=9/12=0.75\) years.
02

Substitution in the formula

Substitute the values of P, r and t into the formula \(I = P*r*t/100\). So the equation becomes, \(I = 5000*8.5*0.75/100\).
03

Calculation

Perform the mathematical operations and calculate the interest.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Simple Interest Formula
Understanding the interest formula is crucial for calculating how much additional money is earned or paid on a sum over time. Simple interest specifically is determined by multiplying the principal amount (\( P \)), the rate of interest per year (\( r \) as a percentage), and the time the money is invested or borrowed for (\( t \) in years). The formula is represented as:
\[\begin{equation}I = \frac{P \times r \times t}{100}\end{equation}\]
In this context, 'Interest' (\( I \) represents the interest amount), 'Principal' is the initial amount of money before interest, 'Rate' is the percentage of interest per annum, and 'Time' is the period for which the money is invested or borrowed. This formula is simple yet powerful, giving you a straightforward way to calculate interest without compounding effects.
Converting Months to Years
To work with the interest formula, we often need to convert the time period into years because interest rates are typically annual. If a time period is given in months, like in our example exercise, it needs to be converted to years because the simple interest formula requires 't' to be in years.
To convert months into years, you divide the number of months by 12 since there are 12 months in a year:
\[\begin{equation}t (\text{in years}) = \frac{\text{Number of months}}{12}\end{equation}\]
So for our problem with a 9-month period:\[\begin{equation}t = \frac{9}{12} = 0.75 \text{ years}\end{equation}\]
This essential step ensures the accuracy of your interest calculations. Remembering to convert units is a fundamental skill in math and finance, not just for simple interest problems but in various situations where quantities are expressed in different units of time.
Mathematical Operations
The last phase in our interest calculation process involves basic mathematical operations. Assuming we have already inserted our values into the formula correctly, we simply multiply the principal (\( P \) by the rate (\( r \) and the time (\( t \) then divide by 100 to find the interest (\( I \) due to the percentage rate. In our exercise example, here's how the operations unfold:
\[\begin{equation}I = \frac{5000 \times 8.5 \times 0.75}{100}\end{equation}\]
In this case:
  • Multiplication of the numbers gives the actual interest earned over the period before accounting for the percentage.
  • The division by 100 is necessary to adjust for the percentage rate.
Performing these operations correctly, you'd end up with the total interest earned for the 9-month period. Always double-check your calculations for accuracy and use a calculator if necessary to ensure you get the correct results. Being methodical in this step avoids errors and helps solidify your understanding of how simple interest is computed.

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Most popular questions from this chapter

The price of a home is $$ 160,000\(. The bank requires a \)15 \%\( down payment. The buyer is offered two mortgage options: 15 -year fixed at \)8 \%\( or 30 -year fixed at \)8 \%$. Calculate the amount of interest paid for each option. How much does the buyer save in interest with the 15 -year option?

Suppose that you are buying a car for \(\$ 60,000\), including taxes and license fees. You saved \(\$ 10,000\) for a down payment. The dealer is offering you two incentives: Incentive \(\mathrm{A}\) is \(\$ 5000\) off the price of the car, followed by a five-year loan at \(734 \%\). Incentive \(\mathrm{B}\) does not have a cash rebate, but provides free financing (no interest) over five years. What is the difference in monthly payments between the two offers? Which incentive is the better deal?

To borrow money, you pawn your guitar. Based on the value of the guitar, the pawnbroker loans you \(\$ 960\). One month later, you get the guitar back by paying the pawnbroker \(\$ 1472\). What annual interest rate did you pay?

In Exercises 11-14, use the formula $$ A=\frac{P\left[\left(1+\frac{r}{n}\right)^{n t}-1\right]}{\left(\frac{r}{n}\right)} $$ Round all computations to the nearest dollar. Suppose that you drive 40,000 miles per year and gas averages \(\$ 4\) per gallon. a. What will you save in annual fuel expenses by owning a hybrid car averaging 40 miles per gallon rather than an SUV averaging 16 miles per gallon? b. If you deposit your monthly fuel savings at the end of each month into an annuity that pays \(5.2 \%\) compounded monthly, how much will you have saved at the end of six years?

In Exercises 1-10, use $$ P M T=\frac{P\left(\frac{r}{n}\right)}{\left[1-\left(1+\frac{r}{n}\right)^{-n t}\right]} $$ Round answers to the nearest dollar. Suppose that you decide to borrow \(\$ 40,000\) for a new car. You can select one of the following loans, each requiring regular monthly payments: Installment Loan A: three-year loan at \(6.1 \%\) Installment Loan B: five-year loan at \(7.2 \%\). a. Find the monthly payments and the total interest for \(\operatorname{Loan} A\). b. Find the monthly payments and the total interest for Loan B. c. Compare the monthly payments and the total interest for the two loans.

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