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Chapter 7: Problem 3

Plot the given point in a rectangular coordinate system. \((-2,3)\)

Short Answer

Expert verified
The point \((-2,3)\) is 2 units to the left and 3 units up from the origin, in the second quadrant of the rectangular coordinate system.

Step by step solution

01

Understand The Coordinates

First, you need to understand the coordinates given, \((-2,3)\). This means the point is 2 units to the left of the y-axis (since -2 is the x-coordinate) and 3 units above the x-axis (3 is the y-coordinate). So the point is in the second quadrant of the graph.
02

Draw The Coordinate System

Draw a rectangular coordinate system which consists of two perpendicular lines or axes. The horizontal line is called the x-axis and the vertical line is called the y-axis. The point where the x-axis and y-axis intersect is called the origin.
03

Plot The Point

Starting from the origin, count 2 units to the left along the x-axis and make a small mark. From this mark, count 3 units up parallel to the y-axis. Mark this point, which represents the point \((-2,3)\). This point is in the 2nd quadrant as anticipated.

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Most popular questions from this chapter

In Exercises 23-24, use a table of coordinates to graph each exponential function. Begin by selecting \(-2,-1,0,1\), and 2 for \(x\). Based on your graph, describe the shape of a scatter plot that can be modeled by \(f(x)=b^{x}, 0

Graph each linear inequality. \(y \geq 0\)

Make Sense? In Exercises 58-61, determine whether each statement makes sense or does not make sense, and explain your reasoning. When graphing a linear inequality, I should always use \((0,0)\) as a test point because it's easy to perform the calculations when 0 is substituted for each variable.

Graph the solution set of each system of inequalities. \(\left\\{\begin{array}{l}x \leq 5 \\ y>-3\end{array}\right.\)

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