/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 Solve each system by the substit... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve each system by the substitution method. Be sure to check all proposed solutions. \(\left\\{\begin{array}{r}-x+3 y=10 \\ 2 x+8 y=-6\end{array}\right.\)

Short Answer

Expert verified
The solution to this system of equations is x = -7, y = 1.

Step by step solution

01

Rewrite the first equation for x

From the first equation -x + 3y = 10, x can be expressed in terms of y as: x = 3y - 10.
02

Substitute x in the second equation

Replace x with (3y - 10) in the second equation 2x + 8y = -6, we get: 2(3y - 10) + 8y = -6.
03

Solve for y

Solve the equation from step 2 for y: 6y - 20 + 8y = -6, gives 14y = 14, hence y = 1.
04

Substitute y = 1 in the first equation

Replace y with 1 in the equation x = 3y - 10, we get: x = 3*1 - 10 = -7.
05

Verify the solutions

To confirm the solution is correct, we substitute x = -7 and y = 1 into the original equations: For the first equation -(-7) + 3*1 = 10 holds true and 2*(-7) + 8*1 = -6 for the second equation also holds true. Thus, the solution is correct, obeys both equations.

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