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The algebraic expressions $$ \frac{D(A+1)}{24} \text { and } \frac{D A+D}{24} $$ describe the drug dosage for children between the ages of 2 and 13. In each algebraic expression, \(D\) stands for an adult dose and \(A\) represents the child's age. a. Name the property that explains why these expressions are equal for all values of \(D\) and \(A\). b. If an adult dose of ibuprofen is 200 milligrams, what is the proper dose for a 12 -year-old child? Use both forms of the algebraic expressions to answer the question. Which form is easier to use?

Short Answer

Expert verified
The algebraic property that explains why these expressions are equal for all values of \(D\) and \(A\) is the distributive property. Both expressions provide the same dosage for a 12-year-old child, which is 108.33 milligrams when the adult dose is 200 milligrams. The expression \(\frac{DA+D}{24}\) is easier to use.

Step by step solution

01

Identifying the algebraic property

In order for the terms \(\frac{D(A+1)}{24}\) and \(\frac{DA+D}{24}\) to be equal for all instances of \(D\) and \(A\), the property involved is the distributive property. The distributive property states that multiplying a number by a group of numbers added together is the same as doing each multiplication separately. Therefore, \(D(A+1) = DA + D\) holds.
02

Substitute the values

The adult dose \(D\) is given as 200mg and the child's age \(A\) is 12 years. Substitute these values into the two forms of the algebraic expressions. \n\nFirst form: \(\frac{D(A+1)}{24} = \frac{200(12+1)}{24} = \frac{2600}{24} = 108.33mg \) (rounded to two decimal places). \n\nSecond form: \(\frac{DA+D}{24} = \frac{200*12 + 200}{24} = \frac{2600}{24} = 108.33mg\)
03

Choosing the easier form of the expression

On substituting the values, both expressions yield the same results. The second form might be slightly easier to use because each term after distribution is clearly seen and there's no need to perform an operation within parentheses before multiplication.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Distributive Property
Understanding the distributive property is essential when simplifying algebraic expressions and solving equations. It's a rule that allows us to multiply a single term by terms within a parenthesis. For instance, the equation \( a(b + c) = ab + ac \) is an example of the distributive property in action.

This property is particularly useful in dosage calculation for children, as seen in our exercise. With the expressions \( \frac{D(A+1)}{24} \) and \( \frac{DA+D}{24} \) being equivalent thanks to the distributive property, it simplifies the process of determining correct dosages. The property ensures that multi-step calculations involving variables (such as a child's age, \( A \) and adult dose, \( D \) ) can be broken down into simpler parts, which helps avoid potential errors in a real-world medical setting.

For students, visualising this property can help make abstract algebraic concepts more concrete. Consider using colored markers or tiles to demonstrate how distributing the \( D \) across the terms within the parentheses results in the same total area (or total dosage) as performing the multiplication directly.
Drug Dosage for Children
When it comes to administering medication, calculating the correct drug dosage for children is paramount for their safety and health. The difference in body size and the children's developing physiology mean they typically require smaller doses than adults. The ideal pediatric dose often follows specific formulas or rules, like the one we encounter in our algebraic expressions.

The expressions \( \frac{D(A+1)}{24} \) and \( \frac{DA+D}{24} \) give us an insight into these calculations. They highlight the importance of adapting adult dosages (\(D\)) to a child’s age (\(A\)). In practice, healthcare professionals rely on such established mathematical models to ensure accuracy and avoid underdosing or overdosing.

For educational purposes, when presenting similar dosage problems, it's helpful to include age-appropriate examples and encourage the use of digital tools or calculators to practice and verify calculations. This builds confidence in real-world scenarios where precise measurements are crucial.
Mathematical Problem-Solving
Mathematical problem-solving involves a step-by-step approach to finding solutions to various types of mathematical conundrums. This approach is exemplified in the exercise, where we use algebra to solve for a child's medication dosage.

The step by step solution showcases a clear strategy: identify the mathematical property involved (distributive property), substitute known values into the expressions (age of the child and the adult dosage), and compare methods to determine the easiest approach for calculation. In this case, the second form, \( \frac{DA+D}{24} \) may be easier as it breaks down the problem into simpler, more manageable parts—a key aspect of efficient problem-solving.

Encouraging students to articulate their problem-solving process can aid understanding and retention. This might include creating and solving similar dosage problems, using algebraic equations that apply the distributive property, or even exploring potential outcomes when values change. Real-world relevance, such as calculating medication dosages, highlights the essential role mathematics plays in our daily lives, cultivating an appreciation for the subject matter.

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