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Use properties of exponents to simplify each expression. Express answers in exponential form with positive exponents only. Assume that any variables in denominators are not equal to zero. \(\left(-2 x^{3} y^{-4}\right)\left(3 x^{-1} y\right)\)

Short Answer

Expert verified
\(-(2 x^{2})(3/y^{3})\)

Step by step solution

01

Begin by expanding the expression

Expand the expression by multiplying coefficients, then individual variables (in each case, add the exponents since we're multiplying values with the same base, according to exponent rules). This gives us: \(-6 x^{3 - 1} y^{-4 + 1}\), or \(-6 x^{2} y^{-3}\)
02

Apply the rule for negative exponents

We apply the rule \(b^{-n} = 1/b^n\) to swap \(y^{-3}\) to its equivalent with positive exponent. Thus, the expression becomes \(-6 x^{2}/ y^{3}\)
03

Render the final form

The final form asked for doesn't allow negative coefficients, and aims to write entire expression in exponential form. Therefore, -6 is written as \(-1 \times 2 \times 3\), and the final expression becomes \(-(2 x^{2})(3/y^{3})\)

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