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Find the prime factorization of each composite number. 48

Short Answer

Expert verified
The prime factorization of 48 is \(2^4 \times 3\).

Step by step solution

01

Identify the Smallest Prime Number

Identify the smallest prime number which is 2. We start the division process by this prime number.
02

Division by 2

48 is an even number, thus it's divisible by 2. Divide 48 by 2, the quotient is 24.
03

Repeat Division by 2

Next, we continue the division process on the quotient obtained in the previous step. Since 24 is also an even number, divide 24 by 2 again and the quotient in this case is 12.
04

Continue Division

We repeat the process and divide 12 by 2 to get 6 and then divide 6 by 2 to get 3.
05

Division by the Next Prime Number

Since 3 is a prime number and not divisible by 2, we move to the next prime number which is 3. Divide 3 by 3 to obtain 1. At this point, when the division result is 1, we know that there are no more divisible numbers.
06

Write the Prime Factorization

A useful way to document this process and make sure no factors are missed is to create a division-based 'tree' to help visualize what's going on. In writing the prime factorization of 48, we record all the prime numbers we divided by, in order. So, the prime factorization of 48 is \(2^4 \times 3\).

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Most popular questions from this chapter

You will develop geometric sequences that model the population growth for California and Texas, the two most populated U.S. states. The table shows the population of California for 2000 and 2010 , with estimates given by the U.S. Census Bureau for 2001 through \(2009 .\) $$ \begin{array}{|l|l|l|l|l|l|l|} \hline \text { Year } & \mathbf{2 0 0 0} & \mathbf{2 0 0 1} & \mathbf{2 0 0 2} & \mathbf{2 0 0 3} & \mathbf{2 0 0 4} & \mathbf{2 0 0 5} \\ \hline \begin{array}{l} \text { Population } \\ \text { in millions } \end{array} & 33.87 & 34.21 & 34.55 & 34.90 & 35.25 & 35.60 \\ \hline \end{array} $$ $$ \begin{array}{|l|l|l|l|l|l|} \hline \text { Year } & \mathbf{2 0 0 6} & \mathbf{2 0 0 7} & \mathbf{2 0 0 8} & \mathbf{2 0 0 9} & \mathbf{2 0 1 0} \\ \hline \begin{array}{l} \text { Population } \\ \text { in millions } \end{array} & 36.00 & 36.36 & 36.72 & 37.09 & 37.25 \\ \hline \end{array} $$ a. Divide the population for each year by the population in the preceding year. Round to two decimal places and show that California has a population increase that is approximately geometric. b. Write the general term of the geometric sequence modeling California's population, in millions, \(n\) years after \(1999 .\) c. Use your model from part (b) to project California's population, in millions, for the year 2020 . Round to two decimal places.

Determine whether each sequence is arithmetic or geometric. Then find the next two terms. \(15,30,60,120, \ldots\)

Write a formula for the general term (the nth term) of each arithmetic sequence. Then use the formula for \(a_{n}\) to find \(a_{20}\), the 20 th term of the sequence. \(a_{1}=-70, d=-5\)

Determine whether each statement makes sense or does not make sense, and explain your reasoning. I've noticed that the big difference between arithmetic and geometric sequences is that arithmetic sequences are based on addition and geometric sequences are based on multiplication.

Write the first six terms of the geometric sequence with the first term, \(a_{1}\), and common ratio, \(r\). \(a_{1}=3000, r=-1\)

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