/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 27 Find the prime factorization of ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the prime factorization of each composite number. 56

Short Answer

Expert verified
The prime factorization of 56 is \(2^3 \times 7\).

Step by step solution

01

Identify the Problem

The problem requires finding the prime factorization of the composite number 56. This means breaking down 56 into prime factors, them being the smallest building blocks of a number.
02

Start Dividing by Smallest Prime Number

Start by dividing the given number by the smallest prime number, 2. So if we divide 56 by 2, we get a quotient of 28. Since 28 is not a prime number, we will continue this process.
03

Continue Division

Continuing the division, divide 28 by 2, we get 14. Again, divide 14 by 2 gives a quotient of 7. Now, the quotient 7 is a prime number, so we stop here.
04

Write Down The Prime Factorization

We expressed the number as the product of primes. So, the prime factorization of 56 is \(2^3 \times 7\).

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Most popular questions from this chapter

Use the appropriate formula shown above to find \(2+4+6+8+\cdots+200\), the sum of the first 100 positive even integers.

You will develop geometric sequences that model the population growth for California and Texas, the two most populated U.S. states. The table shows the population of California for 2000 and 2010 , with estimates given by the U.S. Census Bureau for 2001 through \(2009 .\) $$ \begin{array}{|l|l|l|l|l|l|l|} \hline \text { Year } & \mathbf{2 0 0 0} & \mathbf{2 0 0 1} & \mathbf{2 0 0 2} & \mathbf{2 0 0 3} & \mathbf{2 0 0 4} & \mathbf{2 0 0 5} \\ \hline \begin{array}{l} \text { Population } \\ \text { in millions } \end{array} & 33.87 & 34.21 & 34.55 & 34.90 & 35.25 & 35.60 \\ \hline \end{array} $$ $$ \begin{array}{|l|l|l|l|l|l|} \hline \text { Year } & \mathbf{2 0 0 6} & \mathbf{2 0 0 7} & \mathbf{2 0 0 8} & \mathbf{2 0 0 9} & \mathbf{2 0 1 0} \\ \hline \begin{array}{l} \text { Population } \\ \text { in millions } \end{array} & 36.00 & 36.36 & 36.72 & 37.09 & 37.25 \\ \hline \end{array} $$ a. Divide the population for each year by the population in the preceding year. Round to two decimal places and show that California has a population increase that is approximately geometric. b. Write the general term of the geometric sequence modeling California's population, in millions, \(n\) years after \(1999 .\) c. Use your model from part (b) to project California's population, in millions, for the year 2020 . Round to two decimal places.

Determine whether each statement makes sense or does not make sense, and explain your reasoning. I've noticed that the big difference between arithmetic and geometric sequences is that arithmetic sequences are based on addition and geometric sequences are based on multiplication.

Determine whether each sequence is arithmetic or geometric. Then find the next two terms. \(7,-7,7,-7, \ldots\)

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