Chapter 5: Problem 12
Give an example of a number that is a real number, but not an irrational number.
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Chapter 5: Problem 12
Give an example of a number that is a real number, but not an irrational number.
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The sum, \(S_{n}\), of the first n terms of an arithmetic sequence is given by $$ S_{n}=\frac{n}{2}\left(a_{1}+a_{n}\right), $$ in which \(a_{1}\) is the first term and \(a_{n}\) is the nth term. The sum, \(S_{n}\), of the first \(n\) terms of a geometric sequence is given by $$ S_{n}=\frac{a_{1}\left(1-r^{n}\right)}{1-r}, $$ in which \(a_{1}\) is the first term and \(r\) is the common ratio \((r \neq 1)\). Determine whether each sequence is arithmetic or geometric. Then use the appropriate formula to find \(S_{10}\), the sum of the first ten terms. \(3,-6,12,-24, \ldots\)
Company A pays $$\$ 24,000$$ yearly with raises of $$\$ 1600$$ per year. Company B pays $$\$ 28,000$$ yearly with raises of $$\$ 1000$$ per year. Which company will pay more in year 10 ? How much more?
Write a formula for the general term (the nth term) of each geometric sequence. Then use the formula for \(a_{n}\) to find \(a_{7}\), the seventh term of the sequence. \(0.0007,-0.007,0.07,-0.7, \ldots\)
A person is investigating two employment opportunities. They both have a beginning salary of $$\$ 20,000$$ per year. Company A offers an increase of $$\$ 1000$$ per year. Company B offers \(5 \%\) more than during the preceding year. Which company will pay more in the sixth year?
Determine whether each sequence is arithmetic or geometric. Then find the next two terms. \(2,6,10,14, \ldots\)
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