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Use grouping symbols to clarify the meaning of each statement. Then construct a truth table for the statement. \(p \rightarrow \sim q \vee r \leftrightarrow p \wedge r\)

Short Answer

Expert verified
Grouped statement: \(p \rightarrow (\sim q \vee r) \leftrightarrow (p \wedge r)\). The truth table represents all possible truth values for this statement given the truth values of \(p\), \(q\), and \(r\)

Step by step solution

01

Group the Logical Statement

Let's begin by grouping the logical statement \(p \rightarrow (\sim q \vee r) \leftrightarrow (p \wedge r)\). The brackets clarify that \(q\) is negated first, then ORed (\(\vee\)) with \(r\). This result is then implicated with \(p\) on the left-hand side. On the right-hand side, \(p\) is ANDed (\(\wedge\)) with \(r\).
02

Construct the Truth Table

Now, we will build a truth table. It should have columns for \(p\), \(q\), and \(r\) to represent their possible truth values, as well as columns for \(\sim q\), \((\sim q \vee r)\), and \((p \wedge r)\). The final column will represent the entire statement \(p \rightarrow (\sim q \vee r) \leftrightarrow (p \wedge r)\). The table has eight lines, which represent all possible combinations of true (T) and false (F) for the three variables.
03

Fill in the Truth Table

Starting with the easiest part first, fill in T and F for each variable in every possible configuration. After that, evaluate \(\sim q\), \((\sim q \vee r)\) and \((p \wedge r)\) based on the values of \(p\), \(q\) and \(r\). Finally, evaluate the entire statement \(p \rightarrow (\sim q \vee r) \leftrightarrow (p \wedge r)\) for all cases.

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