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Determine the truth value for each statement when \(p\) is false, \(q\) is true, and \(r\) is false. \(\sim p \leftrightarrow(\sim q \wedge r)\)

Short Answer

Expert verified
The truth value for the statement \(\sim p \leftrightarrow(\sim q \wedge r)\) when p is false, q is true, and r is false is false.

Step by step solution

01

Identify the Truth Values

In this step, let's identify the truth values for each proposition: p is false, q is true, and r is false.
02

Apply Negation

Now we begin with evaluating the expression \(\sim p \leftrightarrow(\sim q \wedge r)\). Convert every p, q, and r in the expression with their respective truth values and apply the negation (NOT/\sim) operators first. So, \(\sim p\) will become true (since p is false), \(\sim q\) will become false (since q is true), and r will remain false.
03

Apply Conjunction

Next, we apply the conjunction (AND/\wedge) operation. Thus, the term \((\sim q \wedge r)\) becomes false and false, which is false (since AND operation returns true only when both the operands are true.
04

Apply Biconditional

Lastly, we apply biconditional/IF AND ONLY IF operation which returns true if both the operands are similar. Thus \(\sim p \leftrightarrow(\sim q \wedge r)\) becomes true IF AND ONLY IF false. Since they aren't similar, it returns false.

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Most popular questions from this chapter

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