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Construct a truth table for the given statement. \((p \rightarrow q) \wedge \sim q\)

Short Answer

Expert verified
The truth table for \( (p \rightarrow q) \wedge \sim q \) will be as follows: \[\begin{align*}p && q && p \rightarrow q && \sim q && (p \rightarrow q) \wedge \sim q \T && T && T && F && F \T && F && F && T && F \F && T && T && F && F \F && F && T && T && T \\end{align*}\]

Step by step solution

01

Define the Variables

The most basic parts of this statement are the propositions p and q. They can each be true (T) or false (F). Start by creating a table with columns for p and q, and list all possible combinations of truth values.
02

Evaluate the Implication

Remember the truth values for an implication statement \( p \rightarrow q \) are: TT-T, TF-F, FT-T, FF-T. Create a column for the implication \( p \rightarrow q \), and fill in its truth values based on the combinations of p and q in your table.
03

Evaluate the Negation

Next, evaluate the negation \( \sim q \). The negation of a true statement is false and the negation of a false statement is true. Create another column for \( \sim q \), and fill in its truth values based on the values of q in your table.
04

Evaluate the Conjunction

The final step is to evaluate the conjunction: \( (p \rightarrow q) \wedge \sim q \). The truth value of the conjunction is true only if both of its components are true. Create a final column for the entire statement, and fill in its truth values based on the values of \( p \rightarrow q \) and \( \sim q \) in your table.

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