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Use a truth table to determine whether each statement is a tautology, a self- contradiction, or neither. \([(p \rightarrow q) \wedge \sim q] \rightarrow \sim p\)

Short Answer

Expert verified
After creating and analyzing the truth table, depending upon the final column, one can affirm if the given statement \([(p \rightarrow q) \wedge \sim q] \rightarrow \sim p\) is a tautology, self-contradiction or neither.

Step by step solution

01

Establishing the Truth Table

First, draw a truth table with columns for p, q, \(p \rightarrow q\), \(\sim q\), \((p \rightarrow q) \wedge \sim q\), and \((p \rightarrow q) \wedge \sim q \rightarrow \sim p\). Then fill in all possible combinations of truth values for p and q, which are True (T) and False(F).
02

Determine \(p \rightarrow q\)

Now calculate the values of \(p \rightarrow q\), which is false only when p is true and q is false, otherwise it is true.
03

Calculate \(\sim q\)

Calculate the values of \(\sim q\), which should be the logical opposite of the values in the q column.
04

Derive \((p \rightarrow q) \wedge \sim q\)

Now, derive the truth values of \((p \rightarrow q) \wedge \sim q\) corresponding to the conjunction of \(p \rightarrow q\) and \(\sim q\). It will be true only when both of these expressions are true.
05

Deduce \((p \rightarrow q) \wedge \sim q) \rightarrow \sim p\)

Finally calculate the values of \((p \rightarrow q) \wedge \sim q \rightarrow \sim p\), which would be false only when \((p \rightarrow q) \wedge \sim q\)) is true and \(\sim p\) is false. Otherwise, it will be true.
06

Evaluating the Expression

After calculating the values, look at the final column. If it contains only true values then the original statement is a tautology. If it only contains false values then it's a self-contradiction. If it contains a mix of true and false values then it's neither.

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