/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 Determine whether \(\subseteq, \... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine whether \(\subseteq, \subset\), both, or neither can be placed in each blank to form a true statement. \(\\{x \mid x\) is a woman \(\\}\) ____ \(\\{x \mid x\) is a person \(\\}\)

Short Answer

Expert verified
Both \(\subseteq\) and \(\subset\) can be placed in the blank to form a true statement.

Step by step solution

01

Analyze the Elements

Firstly, one needs to analyze the elements of the two provided sets. The first set is constituted by elements \(x\) that are women, and the second set is composed of elements \(x\) that are persons.
02

Evaluate Subset Relationship

Since every woman is a person but not every person is a woman, the set of women is a subset of people. Hence, \(\{x | x\) is a woman\(\}\) \(\subseteq\) \(\{x | x\) is a person\(\}\). And also, \(\{x | x\) is a woman\(\}\) is a proper subset of \(\{x | x\) is a person\(\}\), which can be denoted as \(\{x | x\) is a woman\(\}\) \(\subset\) \(\{x | x\) is a person\(\}\).
03

Conclusion

It can be concluded that both \(\subseteq\) and \(\subset\) can be placed in the blank to form a true statement between the two given sets.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Set Theory
Set theory is a fundamental area of mathematics that deals with collections of objects, known as sets. In the context of the problem provided, we deal with two sets: the set of women and the set of persons. A set is generally described using curly braces \( \{ \} \) and contains elements that share a common property.

The subset relationship is a core concept in set theory. If every element of Set A is also an element of Set B, then Set A is a subset of Set B, which can be denoted as \( A \subseteq B \). In our exercise, since every woman (element of the first set) is a person (element of the second set), we establish that the set of women is a subset of the set of persons.

Proper Subset

A proper subset is a type of subset where Set A is a subset of Set B, but the two sets are not identical—meaning there are elements in Set B that are not in Set A. This relationship is denoted as \( A \subset B \). The set of women is not only a subset but also a proper subset of the set of persons because there are persons who are not women.
Mathematical Logic
Mathematical logic is the study of formal logical systems and their applications in mathematics. It includes understanding propositions, logical connectives, and quantifiers. In terms of set theory, mathematical logic helps us reason about the relationships between sets based on their elements.

In the given exercise, we use logical reasoning to determine the relationship between the set of women and the set of persons. We know from general human categorization that if someone is a woman, they must also be a person but not vice versa. Mathematical logic allows us to convert this reasoning into a precise statement using the subset notation. The use of \(\subseteq\) and \(\subset\) reflects the logical conclusion drawn from the given conditions. Understanding these logical foundations is essential for accurately determining relationships between sets in mathematics.
Elementary Set Operations
Elementary set operations are basic processes that can be performed on sets, such as union, intersection, difference, and complement. These operations allow us to combine sets or compare them to each other. The focus of our exercise, however, is on evaluating the subset relationship, which is equally fundamental in set operations.

The subset operation does not combine or alter sets but rather compares them to determine if one set is completely contained within another. By establishing that the set of women is a subset of the set of persons, we can understand important aspects of these sets' relationships without altering the sets themselves.

Under the umbrella of elementary set operations, understanding the subset relationship equips us with a tool for classifying and comparing different sets based on their elements. Noteworthy is that these operations and relations, like \(\subset\) and \(\subseteq\), serve as the building blocks for more complex topics in set theory.

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Most popular questions from this chapter

An anonymous survey of college students was taken to determine behaviors regarding alcohol, cigarettes, and illegal drugs. The results were as follows: 894 drank alcohol regularly. 665 smoked cigarettes, 192 used illegal drugs, 424 drank alcohol regularly and smoked cigarettes, 114 drank alcohol regularly and used illegal drugs, 119 smoked cigarettes and used illegal drugs, 97 engaged in all three behaviors, and 309 engaged in none of these behaviors. Source: Jamie Langille, University of Nevada Las Vegas a. How many students were surveyed? Of those surveyed, b. How many drank alcohol regularly or smoked cigarettes? c. How many used illegal drugs only? d. How many drank alcohol regularly and smoked cigarettes, but did not use illegal drugs? e. How many drank alcohol regularly or used illegal drugs, but did not smoke cigarettes? f. How many engaged in exactly two of these behaviors? g. How many engaged in at least one of these behaviors?

Use the Venn diagram and the given conditions to determine the number of elements in each region, or explain why the conditions are impossible to meet. \(n(U)=42, n(A)=26, n(B)=22, n(C)=25\) \(n(A \cap B)=17, n(A \cap C)=11, n(B \cap C)=9\) \(n(A \cap B \cap C)=5\)

In Exercises 41-66, let $$ \begin{aligned} U &=\\{\mathrm{a}, \mathrm{b}, \mathrm{c}, \mathrm{d}, \mathrm{e}, \mathrm{f}, \mathrm{g}, \mathrm{h}\\} \\ A &=\\{\mathrm{a}, \mathrm{g}, \mathrm{h}\\} \\ B &=\\{\mathrm{b}, \mathrm{g}, \mathrm{h}\\} \\ C &=\\{\mathrm{b}, \mathrm{c}, \mathrm{d}, \mathrm{e}, \mathrm{f}\\} \end{aligned} $$ Find each of the following sets. \(A^{\prime} \cup B^{\prime}\)

In Exercises 41-66, let $$ \begin{aligned} U &=\\{\mathrm{a}, \mathrm{b}, \mathrm{c}, \mathrm{d}, \mathrm{e}, \mathrm{f}, \mathrm{g}, \mathrm{h}\\} \\ A &=\\{\mathrm{a}, \mathrm{g}, \mathrm{h}\\} \\ B &=\\{\mathrm{b}, \mathrm{g}, \mathrm{h}\\} \\ C &=\\{\mathrm{b}, \mathrm{c}, \mathrm{d}, \mathrm{e}, \mathrm{f}\\} \end{aligned} $$ Find each of the following sets. \(A \cup \varnothing\)

Assume \(A \neq B\). Draw a Venn diagram that correctly illustrates the relationship between the sets. \(A \cap B=B\)

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