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In Exercises 19-22, suppose that the pairwise comparison method is used to determine the winner in an election. If there are five candidates, how many comparisons must be made?

Short Answer

Expert verified
10 comparisons must be made.

Step by step solution

01

Identify the Variables

In this case, each comparison involves 2 candidates, so \(r = 2\). We have 5 candidates in total to choose from, so \(n = 5\).
02

Apply the Combinations Formula

Plug \(n = 5\) and \(r = 2\) into the combinations formula \(C(n, r) = \frac{n!}{r!(n-r)!}\).
03

Calculate the Factorials

Calculate the factorials of 5, 2, and \(5 - 2 = 3\) which are 120, 2, and 6 respectively. So, \(C(5, 2) = \frac{120}{2 \times 6}\).
04

Compute the Number of Comparisons

Perform the division to find the number of combinations, which gives us \(C(5, 2) = \frac{120}{12} = 10\).

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Most popular questions from this chapter

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